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An electromagnetic wave with frequency \(5.70 \times 10^{14} \mathrm{Hz}\) propagates with a speed of \(2.17 \times 10^{8} \mathrm{m} / \mathrm{s}\) in a certain piece of glass. Find (a) the wavelength of the wave in the glass; (b) the wavelength of a wave of the same frequency propagating in air; (c) the index of refraction \(n\) of the glass for an electromagnetic wave with this frequency; (d) the dielectric constant for glass at this frequency, assuming that the relative permeability is unity.

Short Answer

Expert verified
(a) Wavelength in glass is approximately \(3.81 \times 10^{-7} \, \text{m}\); (b) in air \(5.26 \times 10^{-7} \, \text{m}\); (c) index of refraction is \(1.38\); (d) dielectric constant is \(1.90\).

Step by step solution

01

Calculate Wavelength in Glass

To find the wavelength of the wave in the glass, use the formula: \[ \lambda = \frac{v}{f} \]where \( \lambda \) is the wavelength, \( v \) is the speed of the wave, and \( f \) is the frequency.Substitute the given values:\[ \lambda = \frac{2.17 \times 10^8 \, \text{m/s}}{5.70 \times 10^{14} \, \text{Hz}} \approx 3.81 \times 10^{-7} \, \text{m} \]
02

Calculate Wavelength in Air

The speed of light in air is approximately \(3.00 \times 10^8\, \text{m/s}\). Use the same formula:\[ \lambda_{\text{air}} = \frac{c}{f} \]Substitute the given values:\[ \lambda_{\text{air}} = \frac{3.00 \times 10^8 \, \text{m/s}}{5.70 \times 10^{14} \, \text{Hz}} \approx 5.26 \times 10^{-7} \, \text{m} \]
03

Calculate Index of Refraction

The index of refraction \( n \) can be calculated using the formula:\[ n = \frac{c}{v} \]Substitute the given values:\[ n = \frac{3.00 \times 10^8 \, \text{m/s}}{2.17 \times 10^8 \, \text{m/s}} \approx 1.38 \]
04

Calculate Dielectric Constant

The dielectric constant \( \varepsilon_r \) is related to the index of refraction by:\[ \varepsilon_r = n^2 \]Substitute the value of \( n \):\[ \varepsilon_r = (1.38)^2 \approx 1.90 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength Calculation
Wavelength is a critical characteristic of electromagnetic waves. It tells us the distance between two consecutive peaks of a wave. Understanding wavelength helps us know more about the wave's behavior and its energy properties. The formula to find the wavelength (\(\lambda\)) is: \[ \lambda = \frac{v}{f} \]
Here, \(v\) is the speed of the wave, and \(f\) is the frequency.
In our problem, the wave moves through glass at a speed of \(2.17 \times 10^8 \text{ m/s}\) with a frequency of \(5.70 \times 10^{14} \text{ Hz}\).
  • Substituting these values gives us the wavelength in glass: \(\lambda \approx 3.81 \times 10^{-7} \text{ m}\).
  • In air, where the speed of light is \(3.00 \times 10^8 \text{ m/s}\), the wavelength is longer due to the higher speed. Using the same formula, we get \(\lambda_{\text{air}} \approx 5.26 \times 10^{-7} \text{ m}\).
Calculating the wavelength is essential for understanding how waves change as they move through different materials.
Index of Refraction
The index of refraction (n) of a medium illustrates how much the speed of light changes as it enters the material. It is defined by the equation: \[ n = \frac{c}{v} \]
where \(c\) is the speed of light in a vacuum \((3.00 \times 10^8 \, \text{m/s})\), and \(v\) is the speed of light in the medium.
  • For the glass in this exercise, \(n\) calculates to approximately \(1.38\).
This number tells us that light travels 1.38 times slower in glass than it does in a vacuum. The refractive index is crucial in optics because it determines how much light bends when entering a new medium. Different materials have distinctive indices of refraction, influencing how lenses and other optical devices function.
Dielectric Constant
The dielectric constant (\varepsilon_r) is a measure of a material's ability to transmit electric fields. It is particularly relevant in the context of wave propagation in media like glass or air. This constant is connected to the index of refraction through the relationship: \[ \varepsilon_r = n^2 \]
  • For our glass medium, given \(n \approx 1.38\), the dielectric constant \(\varepsilon_r\) is approximately \(1.90\).
This value helps us understand the material's electrical insulating properties. A higher dielectric constant means a medium can reduce electric field strength more effectively, affecting light and electromagnetic waves' propagation characteristics. In many materials, particularly non-conductive ones, the dielectric constant plays a key role in determining overall dielectric behavior and effectiveness.
Wave Propagation in Media
Wave propagation in different media deals with how waves such as light or sound move through materials. Factors like speed, wavelength, and medium composition all matter. As waves enter new materials, they often change speed, causing phenomena like refraction or reflection.
  • In the given problem, we see this through how light travels at \(2.17 \times 10^8 \, \text{m/s}\) in glass versus \(3.00 \times 10^8 \, \text{m/s}\) in air.
    • This demonstrates a critical concept: that waves slow down in denser materials, causing bending effects due to the change in speed.
      Understanding these dynamics between wave speed, wavelength, and medium allows for the design and innovation of lenses, glasses, and other optical instruments essential to technology and science.

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Most popular questions from this chapter

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