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31.66. A resistance \(R,\) capacitance \(C,\) and inductance \(L\) are connected in series to a voltage source with amplitude \(V\) and variable angular frequency \(\omega\) . If \(\omega=\omega_{0}\) , the resonance angular frequency, find (a) the maximum current in the resistor; (b) the maximum voltage across the capacitor; (c) the maximum voltage across thinductor; (d) the maximum energy stored in the capacitor; (e) the maximum energy stored in the inductor. Give your answers in terms of \(R, C, L,\) and \(V .\)

Short Answer

Expert verified
(a) \( \frac{V}{R} \); (b) \( \frac{V}{R} \cdot \sqrt{\frac{L}{C}} \); (c) \( \frac{V}{R} \cdot \sqrt{\frac{L}{C}} \); (d) \( \frac{V^2 L}{2R^2} \); (e) \( \frac{V^2 L}{2R^2} \).

Step by step solution

01

Identify the Resonance Condition

At resonance, the angular frequency \( \omega = \omega_0 \). This means the inductive reactance \( \omega L \) equals the capacitive reactance \( \frac{1}{\omega C} \). Hence, \( \omega_0 = \frac{1}{\sqrt{LC}} \).
02

Find Maximum Current in the Resistor

At resonance, the current is maximized and is equal to \( I_{max} = \frac{V}{R} \), because the impedance is purely resistive (\( R \)) due to the cancellation of inductive and capacitive reactances.
03

Determine Maximum Voltage Across the Capacitor

The maximum voltage across the capacitor is given by \( V_{C_{max}} = I_{max} \cdot \frac{1}{\omega_0 C} \). Substituting \( I_{max} = \frac{V}{R} \) and \( \omega_0 = \frac{1}{\sqrt{LC}} \), we have \( V_{C_{max}} = \frac{V}{R} \cdot \sqrt{\frac{L}{C}} \).
04

Calculate Maximum Voltage Across the Inductor

Similarly, the maximum voltage across the inductor is \( V_{L_{max}} = I_{max} \cdot \omega_0 L \). Substituting \( I_{max} = \frac{V}{R} \) and \( \omega_0 = \frac{1}{\sqrt{LC}} \), we obtain \( V_{L_{max}} = \frac{V}{R} \cdot \sqrt{\frac{L}{C}} \).
05

Compute Maximum Energy Stored in the Capacitor

The maximum energy stored in the capacitor is \( U_{C_{max}} = \frac{1}{2} C V_{C_{max}}^2 \). Substituting \( V_{C_{max}} = \frac{V}{R} \cdot \sqrt{\frac{L}{C}} \), we find \( U_{C_{max}} = \frac{1}{2} C \left( \frac{V^2 L}{R^2 C} \right) = \frac{V^2 L}{2R^2} \).
06

Determine Maximum Energy Stored in the Inductor

The maximum energy stored in the inductor is \( U_{L_{max}} = \frac{1}{2} L I_{max}^2 \). Substituting \( I_{max} = \frac{V}{R} \), we obtain \( U_{L_{max}} = \frac{1}{2} L \left( \frac{V^2}{R^2} \right) = \frac{V^2 L}{2R^2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resonance Frequency
In an RLC circuit, resonance frequency is a key concept and crucial to understanding how the circuit behaves at its most efficient state. The resonance frequency (\( \omega_0 \)) is the frequency at which the inductive and capacitive reactances are equal but opposite, thereby cancelling each other out. This means the impedance of the circuit is at its minimum and is purely resistive. The formula for calculating the resonance frequency is\[ \omega_0 = \frac{1}{\sqrt{LC}} \]where \( L \)is the inductance and \( C \) is the capacitance. This relationship highlights the inversely proportional impact between the inductance and capacitance on the resonance frequency. By understanding this, learners can predict at which frequency the circuit will have its highest current.
Inductive Reactance
Inductive reactance (\( X_L \)) is an important concept when analyzing RLC circuits. It represents the opposition that an inductor offers to the change in current. This is mathematically defined as \( X_L = \omega L \), where \( \omega \)is the angular frequency and \( L \)is the inductance. At the resonance frequency, the inductive reactance equals the capacitive reactance, resulting in their effects canceling each other out. However, off-resonance, \( X_L \)is a significant factor in determining the circuit's total impedance. It increases with frequency, which means at higher frequencies, the inductor poses a greater opposition to current.
Capacitive Reactance
Capacitive reactance (\( X_C \)) measures how much a capacitor resists the flow of alternating current. The formula is\( X_C = \frac{1}{\omega C} \), where \( \omega \)is the angular frequency and\( C \)is the capacitance. In a resonant circuit, as frequency increases, \( X_C \)decreases. This inverse relationship allows capacitive elements to provide less opposition at higher frequencies. At resonance, the capacitive reactance is exactly balanced by the inductive reactance, easing the current's path through the circuit.
Maximum Current
Maximizing the current in an RLC circuit occurs at the resonance frequency. At this point, the impedance is purely resistive, and its value equals the resistance \( R \)of the resistor in the circuit. This leads to the current being maximized and can be calculated bythe formula:\[ I_{max} = \frac{V}{R} \]Where \( V \)is the voltage source amplitude. This direct relationship between the voltage and resistance at resonance allows for maximum energy transfer because the effects of the inductor and capacitor cancel out.
Stored Energy in Capacitor
The energy stored in a capacitor in an RLC circuit is crucial for understanding the dynamics of energy exchange at resonance. The maximum energy (\( U_{C_{max}} \)) stored in a capacitor is given by the equation:\[ U_{C_{max}} = \frac{1}{2} C V_{C_{max}}^2 \]Where \( V_{C_{max}} \)is the maximum voltage across the capacitor. Substituting the known values from previous calculations, \( V_{C_{max}} = \frac{V}{R} \cdot \sqrt{\frac{L}{C}} \), we find:\[ U_{C_{max}} = \frac{V^2 L}{2R^2} \]This equation shows how the energy stored depends on the circuit's components and voltage, highlighting the potential energy that can be stored and released within the circuit during oscillation.

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Most popular questions from this chapter

31.59. In an \(L . R-C\) series circuit the magnitude of the phase angle is \(54.0^{\circ}\) , with the source voltage lagging the current. The reactance of the capacitor is 350\(\Omega\) , and the resistor resistance is \(180 \Omega .\) The average power delivered by the source is 140 \(\mathrm{W}\) . Find (a) the reactance of the inductor, \((\mathrm{b})\) the rms current; (c) the rms voltage of the source.

31.33. In an \(L . R-C\) series circuit, \(R=150 \Omega, L=0.750 \mathrm{H},\) and \(C=0.0180 \mu \mathrm{F} .\) The source has voltage amplitude \(V=150 \mathrm{V}\) and a frequency equal to the resonance frequency of the circuit. (a) What is the power factor? (b) What is the average power delivered by the source? (c) The capacitor is replaced by one with \(C=0.0360 \mu \mathrm{F}\) and the source frequency is adjusted to the new resonance value. Then what is the average power delivered by the source?

31.14. You have a \(200-\Omega\) resistor, a \(0.400-\mathrm{H}\) inductor, and a \(6.00-\mu \mathrm{F}\) capacitor. Suppose you take the resistor and inductor and make a series circuit with a voltage source that has voltage amplitude 30.0 \(\mathrm{V}\) and an angular frequency of 250 \(\mathrm{rad} / \mathrm{s}\) . (a) What is the impedance of the circuit? (b) What is the current amplitude? (c) What are the voltage amplitudes across the resistor and across the inductor? (d) What is the phase angle \(\phi\) of the source voltage with respect to the current? Does the source voltage lag or lead the conrent? (e) Construct the phasor diagram.

31.37. A Step-Down Transformer. A transformer connected to a \(120-\mathrm{V}(\mathrm{rms})\) ac line is to supply 12.0 \(\mathrm{V}\) (mns) to a portable electronic device. The load resistance in the secondary is 5.00\(\Omega\) (a) What should the ratio of primary to secondary turns of the transformer be? (b) What rms current must the secondary supply? (c) What average power is delivered to the load? (d) What resistance connected directly across the \(120-\mathrm{V}\) line would draw the same power as the transformer? Show that this is equal to 5.00\(\Omega\) times the square of the ratio of primary to secondary turns.

31.6. A capacitance \(C\) and an inductance \(L\) are operated at the same angular frequency. (a) At what angular frequency will they have the same reactance? (b) If \(L=5.00 \mathrm{mH}\) and \(C=3.50 \mu \mathrm{F}\) , what is the numerical value of the angular frequency in part (a), and what is the reactance of each element?

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