/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 An air-filled toroidal solenoid ... [FREE SOLUTION] | 91Ó°ÊÓ

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An air-filled toroidal solenoid has a mean radius of 15.0 \(\mathrm{cm}\) and a cross-sectional area of \(5.00 \mathrm{cm}^{2} .\) When the current is 12.0 \(\mathrm{A}\) , the energy stored is 0.390 \(\mathrm{J}\) . How many turns does the winding have?

Short Answer

Expert verified
The toroidal solenoid has approximately 160 turns.

Step by step solution

01

Identify relevant formulas

To solve the problem, we need two key formulas: the formula for the energy stored in an inductor, \( E = \frac{1}{2} L I^2 \), and the formula for the inductance of a toroidal solenoid, \( L = \frac{\mu_0 N^2 A}{2\pi r} \), where \( N \) is the number of turns, \( A \) is the cross-sectional area, \( r \) is the mean radius, and \( \mu_0 \) is the permeability of free space, \( 4\pi \times 10^{-7} \text{ T}\cdot\text{m/A} \).
02

Rearrange the energy formula for inductance

Rearrange the energy formula to solve for inductance \( L \):\[ L = \frac{2E}{I^2} \]Plug in the given values (\( E = 0.390 \text{ J} \) and \( I = 12.0 \text{ A} \)) to find \( L \).
03

Calculate the inductance

Substitute the given values to calculate inductance:\[ L = \frac{2 \times 0.390}{12.0^2} = \frac{0.780}{144} = 0.00542 \text{ H} \]
04

Rearrange inductance formula to solve for turns

Using the inductance formula, rearrange it to solve for the number of turns \( N \): \[ N^2 = \frac{L \cdot 2\pi r}{\mu_0 A} \]Plug the calculated \( L \), given \( r = 0.15 \text{ m} \), \( A = 5.00 \times 10^{-4} \text{ m}^2 \), and \( \mu_0 = 4\pi \times 10^{-7} \text{ T}\cdot\text{m/A} \) into the equation.
05

Solve for the number of turns

Calculate \( N \):\[ N^2 = \frac{0.00542 \cdot 2\pi \cdot 0.15}{4\pi \times 10^{-7} \cdot 5.00 \times 10^{-4}} \]Simplify this to find:\[ N^2 = \frac{0.00542 \times 0.942}{2 \times 10^{-10}} = \frac{0.00510644}{2 \times 10^{-10}} = 25532.2 \]\[ N \approx \sqrt{25532.2} \approx 159.8 \]Thus, the number of turns \( N \approx 160 \).
06

Finalize the result

The calculation shows that the number of turns for the toroidal solenoid is approximately 160 turns. Make sure to round to the nearest whole number as fractional turns are not feasible.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy stored in an inductor
When you run an electric current through an inductor, such as a coil, energy is stored in its magnetic field. This stored energy can be useful in various applications, such as in transformers or inductors in circuits where energy needs to be temporarily stored. Understanding how this energy is stored and calculated is crucial, especially when working with components like solenoids or coils.
To find out how much energy is stored in an inductor, you can use the formula:
  • \[ E = \frac{1}{2} L I^2 \]
Where:
  • \( E \) is the energy stored (in joules),
  • \( L \) is the inductance of the coil (in henries),
  • \( I \) is the current flowing through the coil (in amperes).
The more current you pump through your inductor and the greater the inductance, the more energy gets stored.
For a given problem, if you already know the energy stored and the current used, you can rearrange this equation to solve for the inductance \( L \):
  • \[ L = \frac{2E}{I^2} \]
By calculating \( L \), you lay the groundwork for further calculations, such as finding the number of turns in a coil.
Toroidal solenoid
A toroidal solenoid is a type of inductor with a coil shaped like a donut. This shape helps in efficiently containing the magnetic field inside its core, making it useful in various electronic applications like transformers and other electromagnetic devices. Because of its design, it minimizes the magnetic field exposure outside the coil, thus reducing electromagnetic interference.
To calculate the inductance of a toroidal solenoid, you use the formula:
  • \[ L = \frac{\mu_0 N^2 A}{2\pi r} \]
Where:
  • \( \mu_0 \) is the permeability of free space ( \( 4\pi \times 10^{-7} \text{ T}\cdot\text{m/A} \) ),
  • \( N \) is the number of turns,
  • \( A \) is the cross-sectional area of the core (in square meters),
  • \( r \) is the mean radius of the coil (in meters).
This formula shows that the inductance depends on the coil's physical characteristics: the number of turns, its size, and the area through which the magnetic field passes. The inherent nature of a toroidal solenoid always attempts to balance these variables to maintain efficiency and functionality.
Number of turns calculation
Calculating the number of turns in a coil helps determine how the inductor will perform. In our problem, once the inductance \( L \) is known, you need to solve for the number of turns \( N \) using the equation for inductance:
  • \[ N^2 = \frac{L \cdot 2\pi r}{\mu_0 A} \]
To find \( N \) from this equation, follow these steps:
  • Calculate the right side of the equation, which involves substituting known values for \( L \), \( r \), \( A \), and \( \mu_0 \).
  • Take the square root of the result to solve for \( N \).
You should always round your answer to the nearest whole number. This is because a coil can't have a fraction of a turn; it needs to be a whole number for practical construction.
After these calculations, you have the number of turns, and thus one of the key variables required to analyze or design circuits involving your toroidal solenoid. Understanding these basics equips you with the knowledge to apply similar calculations to other electromagnetic devices.

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Most popular questions from this chapter

A \(0.250-\mathrm{H}\) inductor carries a time-varying current given by the expression \(i=(124 \mathrm{mA}) \cos [(240 \pi / \mathrm{s}) t] .\) (a) Find an expression for the induced emf as a function of time. Graph the current and induced emf as functions of time for \(t=0\) to \(t=\frac{1}{60} \mathrm{s}\) . (b) What is the maximum emf? What is the current when the induced emf is a maximum? (c) What is the maximum current? What is the induced emf when the current is a maximum?

Two coils have mutual inductance \(M=3.25 \times 10^{-4} \mathrm{H}\) . The current \(i_{1}\) in the first coil increases at a uniform rate of 830 \(\mathrm{A} / \mathrm{s}\) . (a) What is the magnitude of the induced emf in the second coil? Is it constant? (b) Suppose that the current described is in the second coil rather than the first. What is the magnitude of the induced emf in the first coil?

A \(18.0-\mu F\) capacitor is placed across a \(22.5-\mathrm{V}\) battery for several seconds and is then connected across a 12.0 -mH inductor that has no appreciable resistance. (a) After the capacitor and inductor are connected together, find the maximum current in the circuit. When the current is a maximum, what is the charge on the capacitor? (b) How long after the capacitor and inductor are connected together does it take for the capacitor to be completely discharged for the first time? For the second time? (c) Sketch graphs of the charge on the capacitor plates and the current through the inductor as functions of time.

L-C Oscillations. A capacitor with capacitance \(6.00 \times\) \(10^{-5} \mathrm{F}\) is charged by connecting it to a \(12.0-\mathrm{V}\) battery. The capacitor is disconnected from the battery and connected across an inductor with \(L=1.50 \mathrm{H}\) (a) What are the angular frequency \(\omega\) of the electrical oscillations and the period of these oscillations (the time for one oscillation \() ?(\text { b) What is the initial charge on the }\) capacitor? (c) How much energy is initially stored in the capacitor? (d) What is the charge on the capacitor 0.0230 \(\mathrm{s}\) after the connection to the inductor is made? Interpret the sign of your answer.(e) At the time given in part (d), what is the current in the inductor? Interpret the sign of your answer. (f) At the time given in part (d), how much electrical energy is stored in the capacitor and how much is stored in the inductor?

A \(15.0-\Omega\) resistor and a coil are connected in series with a 6.30-V battery with negligible internal resistance and a closed switch. (a) At 200 ms after the switch is opened the current has decayed to 0.210 A. Calculate the inductance of the coil. (b) Calculate the time constant of the circuit. (c) How long after the switch is closed will the current reach 1.00\(\%\) of its original value?

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