/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 A long, straight wire made of a ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A long, straight wire made of a type-I superconductor carries a constant current \(I\) along its length. Show that the current cannot be uniformly spread over the wire's cross section but instead must all be at the surface.

Short Answer

Expert verified
The current in a type-I superconducting wire must flow on the surface to maintain zero internal magnetic field.

Step by step solution

01

Understanding the Properties of Type-I Superconductors

Type-I superconductors exhibit zero electrical resistance and perfect diamagnetism. This means that when placed in a magnetic field, they expel the magnetic field entirely from their interior, a phenomenon known as the Meissner effect. As a result, the magnetic field inside a Type-I superconductor is zero.
02

Applying Ampere's Law Inside the Superconductor

For a long, straight wire carrying a current uniformly inside, the current density would be constant through its cross section. However, according to the Meissner effect, the internal magnetic field must be zero. Using Ampere’s Law, which states that the line integral of the magnetic field around a closed loop is equal to the current passing through that loop multiplied by the permeability \( \oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 I \), we see that if the magnetic field inside specifically is zero, the current inside must be zero because any non-zero current would induce a magnetic field.
03

Relating Meissner Effect to Current Distribution

The Meissner effect implies that all the current in a Type-I superconducting wire must flow in such a way as to ensure no magnetic field penetrates the wire. This means that the current cannot be spread uniformly throughout the cross section as it would introduce a magnetic field depth into the material. To keep the field expelled, the current has to flow only on the surface.
04

Surface Current and Magnetic Field

By restricting the current to the surface, the magnetic field does not penetrate into the superconductor due to the expulsion of the field. Any internal penetration by a magnetic field is naturally eliminated, maintaining zero field throughout the superconducting wire due to its characteristic magnetic properties.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Meissner effect
The Meissner effect is a hallmark characteristic of superconductors, particularly Type-I superconductors. It occurs when a material transitions into a superconducting state below a critical temperature. At this point, the material exhibits perfect diamagnetism, meaning it completely expels all interior magnetic fields. This is quite extraordinary, as it signifies not only zero electrical resistance but also the absence of any magnetic field within the superconductor itself. This effect suggests that the magnetic fields are pushed out of the superconducting material, leading to phenomena such as magnetic levitation. Often, students associate the Meissner effect with simply having no resistance; however, it's crucial to understand that it is specifically about expelling magnetic fields. This implies that if there is any external magnetic field, it will be effectively canceled out within the interior of a superconductor, preserving a magnetic-free environment inside.
Ampere's Law
Ampere's Law is a fundamental concept in electromagnetism which helps us calculate the magnetic field generated by electric current. Mathematically, it is expressed as \( \oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 I \), where the left-hand side represents the closed loop integral of the magnetic field \( \mathbf{B} \) around a loop, and \( I \) is the total current passing through that loop. The permeability of free space is represented by \( \mu_0 \). For a superconductor, particularly when applying Ampere's Law, the interesting situation arises when the internal magnetic field \( \mathbf{B} \) is zero due to the Meissner effect. If there were any current inside the superconductor, it would generate a magnetic field. Hence, in the context of a superconductor, if the magnetic field inside is zero, according to Ampere's Law, the current distribution must also lead to a zero internal magnetic field, meaning that the current cannot be present inside but must flow on the surface.
magnetic field expulsion
Magnetic field expulsion is a direct implication of the Meissner effect, where a superconducting material does not just block magnetic fields but actively pushes them out. This expulsion ensures that no magnetic flux can pass through the interior of the superconductor. For a Type-I superconductor, the boundary between the superconducting state and the surrounding environment plays a crucial role. The expulsion occurs at this boundary, leading to a situation where the magnetic field is expelled up to the surface, but not further inside.
For the wire in the exercise, this means that the current must flow only on its surface. The interior of the wire remains perfectly field-free. Any deeper penetration of the magnetic field is counteracted by rearranging where the current flows, shifting it to the outer regions thus ensuring the superconductor's unique property of perfect magnetic field expulsion is maintained.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A circular wire loop of radius \(a\) and resistance \(R\) initially has a magnetic flux through it due to an external magnetic field. The extermal field then decreases to zero. A current is induced in the loop while the external field is changing; however, this current does not stop at the instant that the external field stops changing. The reason is that the current itself generates a magnetic field, which gives rise to a flux through the loop. If the current changes, the flux through the loop changes as well, and an induced emf appears in the loop to oppose the change. (a) The magnetic field at the center of the loop of radius a produced by a current i in the loop is given by \(B=\mu_{0} i / 2 a\) . If we use the crode approximation that the field has this same value at all points within the loop, what is the flux of this field through the loop? (b) By using Faraday's law, Eq. \((29.3),\) and the relationship \(\mathcal{E}=i R,\) show that after the external field has stopped changing, the current in the loop obeys the differential equation $$ \frac{d i}{d t}=-\left(\frac{2 R}{\pi \mu_{0} a}\right) i $$ (c) If the current has the value \(i_{0}\) at \(t=0\) , the instant that the external field stops changing. snive the equation in part \((b)\) to find \(i\) as a function of time for \(t>0 .\) (Hint: In Section 26.4 we encountered a similar differential equation, Eq. \((26.15),\) for the quantity \(q .\) This equation for \(i\) may be solved in the same way. (d) If the loop has radius \(a=50 \mathrm{cm}\) and resistance \(R=0.10 \Omega,\) how long after the external field stops changing will the current be equal to 0.010 \(\mathrm{o}\) (that is, \(\frac{1}{100}\) of its initial value)? (e) In solving the examples in this chapter, we ignored the effects described in this problem. Explain why this is a good approximation.

A circular loop of wire with a radius of 12.0 \(\mathrm{cm}\) and oriented in the horizontal \(x y\) -plane is located in a region of uniform magnetic field. A field of 1.5 \(\mathrm{T}\) is directed along the positive z-direction, which is upward. (a) If the loop is removed from the field region in a time interval of 2.0 \(\mathrm{ms}\) , find the average emf that will be induced in the wire loop during the extraction process. (b) If the coil is viewed looking down on it from above, is the induced current in the loop clockwise or counterclockwise?

A long, thin solenoid has 900 turns per meter and radius \(2.50 \mathrm{cm} .\) The current in the solenoid is increasing at a uniform rate of 60.0 \(\mathrm{A} / \mathrm{s}\) . What is the magnitude of the induced electric field at a point near the center of the solenoid and (a) 0.500 \(\mathrm{cm}\) from the axis of the solenoid; (b) 1.00 \(\mathrm{cm}\) from the axis of the solenoid?

A flat, rectangular coil consisting of 50 tums measures 25.0 \(\mathrm{cm}\) by 30.0 \(\mathrm{cm}\) . It is in a uniform, \(1.20-\mathrm{T}\) , magnetic field, with the plane of the coil parallel to the field. In 0.222 s, it is rotated so that the plane of the coil is perpendicular to the field. (a) What is the change in the magnetic flux through the coil due to this rotation? (b) Find the magnitude of the average emf induced in the coil during this rotation.

An airplane propeller of total length \(L\) rotates around its center with angular spced \(\omega\) in a magnctic ficld that is perpcndicular to the plane of rotation. Modeling the propeller as a thin, uniform bar, find the potential difference between (a) the center and either end of the propeller and (b) the two ends. (c) If the field is the earth's field of 0.50 \(\mathrm{G}\) and the propeller turns at 220 \(\mathrm{rpm}\) and is 2.0 \(\mathrm{m}\) long, what is the potential difference between the middle and either end? It this large enough to be concemed about?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.