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An \(R-C\) circuit has a time constant \(R C\) . (a) If the circuit is discharging, how long will it take for its stored energy to be reduced to 1\(/ e\) of its initial value? (b) If it is charging, how long will it take for the stored energy to reach 1\(/ e\) of its maximum value?

Short Answer

Expert verified
(a) \( t = \frac{RC}{2} \); (b) \( t \approx 0.72 RC \).

Step by step solution

01

Identify Given Information

The exercise involves analyzing an R-C circuit with a time constant given as \( \tau = RC \). We are asked to determine the time it takes for the stored energy to reach different states while discharging and charging.
02

Understand the Discharging Formula

The voltage across a capacitor during discharging is given by \( V(t) = V_0 e^{-t/RC} \), where \( V_0 \) is the initial voltage. The stored energy is proportional to the square of the voltage, so the energy \( E(t) = E_0 e^{-2t/RC} \).
03

Solve for Discharging Time

We need the energy to be \( \frac{1}{e} \) of its initial value. Set \( E(t) = \frac{1}{e}E_0 = E_0 e^{-2t/RC} \). Solving \( \frac{1}{e} = e^{-2t/RC} \) gives \( -1 = -\frac{2t}{RC} \) which simplifies to \( t = \frac{RC}{2} \).
04

Understand the Charging Formula

During charging, the voltage across the capacitor is given by \( V(t) = V_{max}(1 - e^{-t/RC}) \). The energy stored \( E(t) = E_{max}(1 - e^{-t/RC})^2 \).
05

Solve for Charging Time

We need the energy to reach \( \frac{1}{e} \) of its maximum value, so \( E(t) = \frac{E_{max}}{e} = E_{max}(1 - e^{-t/RC})^2 \). Solving \( \frac{1}{e} = (1 - e^{-t/RC})^2 \), we first take the square root: \( \frac{1}{\sqrt{e}} = 1 - e^{-t/RC} \). This gives us \( e^{-t/RC} = 1 - \frac{1}{\sqrt{e}} \), solving this gives \( t = RC \ln(\sqrt{e}/(\sqrt{e} - 1)) \).
06

Simplify the Charging Solution

The expression \( t = RC \ln(\sqrt{e}/(\sqrt{e} - 1)) \) can be simplified using \( \sqrt{e} = e^{0.5} \), so \( \ln(\sqrt{e}) = 0.5 \ln(e) = 0.5 \) and further simplification yields \( t \approx 0.72 RC \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discharging RC Circuit
In an RC circuit, discharging refers to the process of a charged capacitor releasing its stored energy over time. The discharging behavior is characterized by a decreasing voltage across the capacitor, following an exponential decay model.
The general formula for the voltage across a discharging capacitor is expressed as:
\[ V(t) = V_0 e^{-t/RC} \]
where:
  • \( V(t) \) is the voltage at time \( t \).
  • \( V_0 \) is the initial voltage.
  • \( RC \) is the time constant of the circuit.
The energy stored in the capacitor is proportional to the square of the voltage. This means that as the voltage decreases, the energy does too.
The equation for the energy stored is:
\[ E(t) = E_0 e^{-2t/RC} \]
To find out how long it takes for the energy to decrease to \( \frac{1}{e} \) of its initial value, you set the energy equation to \( \frac{1}{e}E_0 \) and solve for \( t \), leading to:
\[ t = \frac{RC}{2} \]
This result showcases that the time taken for the energy to reach \( \frac{1}{e} \) of its initial value is half of the time constant.
Charging RC Circuit
Charging an RC circuit involves increasing the energy stored in the capacitor as an external voltage is applied across its plates. As it charges, the voltage across the capacitor rises and gradually approaches its maximum value.
The voltage across a charging capacitor can be represented by:
\[ V(t) = V_{max}(1 - e^{-t/RC}) \]
where:
  • \( V(t) \) is the voltage at time \( t \).
  • \( V_{max} \) is the maximum voltage it can reach.
  • \( e^{-t/RC} \) represents the exponential growth factor.
The stored energy follows this growth and can be expressed as the square of the voltage's growth:
\[ E(t) = E_{max}(1 - e^{-t/RC})^2 \]
To determine when the energy reaches \( \frac{1}{e} \) of its maximum possible value, solve the equation \( E(t) = \frac{E_{max}}{e} \). This involves the square root transformation, simplifying the equation, and eventually solving:
\[ t \approx 0.72 RC \]
This means the time taken for the capacitor energy to reach \( \frac{1}{e} \) of its maximum during charging is approximately \( 0.72 \) times the time constant.
Capacitor Energy in RC Circuit
The energy stored in a capacitor is a crucial component in RC circuits, which helps in smoothing, filtering, and various timing applications. The energy can be mathematically defined based on the voltage across its terminals.
The energy stored in a capacitor is given by:
\[ E = \frac{1}{2} C V^2 \]
Here:
  • \( E \) is the energy stored in the capacitor.
  • \( C \) is the capacitance of the capacitor.
  • \( V \) is the voltage across the capacitor.
As the RC circuit charges or discharges, the capacitor’s energy changes according to the \( V(t) \) behavior dictated by exponential laws.
In practical terms, RC time constant \( RC \) defines how quickly these dynamic changes occur, whether it's supplying energy while discharging or storing energy while charging. Understanding this energy behavior is key to designing efficient circuits that rely on capacitors for energy management.
The efficiency and performance of applications using RC circuits depend on accurate predictions of energy transition times and amounts, making these principles vital for electronic designs.

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