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The potential difference across the terminals of a battery is 8.4 \(\mathrm{V}\) when there is a current of 1.50 \(\mathrm{A}\) in the battery from the negative to the positive terminal. When the current is 3.50 \(\mathrm{A}\) in the reverse direction, the potential difference becomes 9.4 \(\mathrm{V}\) . (a) What is the internal resistance of the battery? (b) What is the emf of the battery?

Short Answer

Expert verified
The internal resistance is 0.2 ohms, and the emf is 8.7 V.

Step by step solution

01

Identify Given Values

We are given the following: \( V_1 = 8.4 \, \text{V} \), \( I_1 = 1.50 \, \text{A} \), \( V_2 = 9.4 \, \text{V} \), \( I_2 = 3.50 \, \text{A} \). These represent the potential differences and currents in two different scenarios.
02

Write Equations for Potential Difference with Internal Resistance

The potential difference across a battery with internal resistance \( r \) and electromotive force (emf) \( \mathcal{E} \) is given by: \[ V_1 = \mathcal{E} - I_1 r \]\[ V_2 = \mathcal{E} + I_2 r \] This accounts for the direction of the current relative to the battery's emf.
03

Set Up a System of Equations

Using the equations from Step 2, we have two simultaneous equations: 1. \( 8.4 = \mathcal{E} - 1.5r \) 2. \( 9.4 = \mathcal{E} + 3.5r \)These are based on the two different scenarios provided in the problem.
04

Solve the System of Equations

Subtract the first equation from the second to eliminate \( \mathcal{E} \): \[ (9.4 - 8.4) = (\mathcal{E} + 3.5r) - (\mathcal{E} - 1.5r) \] Simplify to find \( r \): \[ 1.0 = 5r \] \[ r = 0.2 \text{ ohms} \]
05

Find the Electromotive Force (emf)

Substitute \( r = 0.2 \) back into one of the original equations, for instance, the first:\[ 8.4 = \mathcal{E} - 1.5 \times 0.2 \] Solve for \( \mathcal{E} \): \[ 8.4 = \mathcal{E} - 0.3 \] \[ \mathcal{E} = 8.7 \, \text{V} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromotive Force (EMF)
Electromotive Force (EMF) is the term used to describe the voltage generated by a battery or power source when no current is flowing. It is essentially the ideal voltage that the battery can provide, as if it had no internal resistance.

In practical terms, the EMF is the total potential difference across a power source when the current is zero. You can think of it as the peak ability of the battery to cause a current to flow through an external circuit.

The EMF, denoted as \( \mathcal{E} \), is measured in volts (V). It is not influenced by the actual flow of electrons within the battery but represents the battery's open-circuit voltage.
  • The EMF of a battery remains constant when the battery is not discharging or charging any load.
  • It differs from the measured terminal voltage because of the energy losses associated with the internal resistance of the battery.
To determine the EMF, we rely on other electrical equations, like Ohm's Law, and compensate for the battery's internal resistance.
Ohm's Law
Ohm's Law is a fundamental principle in electronics relating voltage, current, and resistance in a simple linear equation: \( V = IR \).

Here, \( V \) represents the voltage across a component, \( I \) is the current flowing through it, and \( R \) is its resistance. Ohm’s Law helps us predict how a device will behave under different voltages and currents, making it a crucial tool in both circuits analysis and design.
  • This equation implies a direct proportionality: as the voltage across a component increases, the current through it also increases if the resistance remains constant.
  • It's important to note that this law assumes the behavior of linear, ohmic materials where current is directly proportional to the applied voltage.
With real-world batteries, we apply Ohm's Law in a modified form to account for internal resistance, which can alter the effective voltage experienced across connected terminals.
Potential Difference
Potential difference, often referred to simply as voltage, is the measure of the electrical potential energy per unit charge between two points in a circuit. It indicates how much energy is available to push the charges through the circuit.

This is measured in volts (V), the same unit as EMF, but unlike EMF, it directly depends on the current flowing and includes losses from internal resistance.

In our exercise, potential difference shifts with current changes; it was 8.4 V under one condition and 9.4 V under the other.
  • This variance results from changes in internal voltage drops due to internal resistance in the battery.
  • Potential difference across a battery's terminals is universally lower than the EMF when current flows in the battery's natural direction due to said internal resistance.
Understanding potential difference helps us recognize how much of the battery's stored energy is available for use in the circuit at any given moment.

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Most popular questions from this chapter

A carbon resistor is to be used as a thermometer. On a winter day when the temperature is \(4.0^{\circ} \mathrm{C}\) , the resistance of the carbon resistor is 217.3\(\Omega\) . What is the temperature on a spring day when the resistance is 215.8\(\Omega ?\) (Take the reference temperature \(T_{0}\) to be \(4.0^{\circ} \mathrm{C} . )\)

In an experiment conducted at room temperature, a current of 0.820 A flows through a wire 3.26 \(\mathrm{mm}\) in diameter. Find the magnitude of the electric field in the wire if the wire is made of (a) tungsten; and (b) aluminum.

You apply a potential difference of 4.50 \(\mathrm{V}\) between the ends of a wire that is 2.50 \(\mathrm{m}\) in length and 0.654 \(\mathrm{mm}\) in radius. The resulting current through the wire is 17.6 \(\mathrm{A}\) . What is the resistivity of the wire?

A typical cost for electric power is 12.0\(\phi\) per kilowatt-hour. (a) Some people leave their porch light on all the time. What is the yearly cost to keep a \(75-\mathrm{W}\) bulb burning day and night? (b) Suppose your refrigerator uses 400 \(\mathrm{W}\) of power when it's running, and it runs 8 hours a day. What is the yearly cost of operating your refrigerator?

The average bulk resistivity of the human body (apart from surface resistance of the skin) is about 5.0\(\Omega \cdot \mathrm{m}\) . The conducting path between the hands can be represented approximately as a cylinder 1.6 \(\mathrm{m}\) long and 0.10 \(\mathrm{m}\) in diameter. The skin resistance can be made negligible by soaking the hands in salt water. (a) What is the resistance between the hands if the skin resistance is negligible? (b) What potential difference between the hands is needed for a lethal shock current of 100 \(\mathrm{mA}\) A? (Note that your result shows that small potential differences produce dangerous currents when the skin is damp.) (c) With the current in part (b), what power is dissipated in the body?

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