Chapter 24: Problem 1
24.1. A capacitor has a capacitance of 7.28\(\mu \mathrm{F}\) . What amount of charge must be placed on each of its plates to make the potential difference between its plates equal to 25.0 \(\mathrm{V} ?\)
Short Answer
Expert verified
The charge on each plate is 182 μC.
Step by step solution
01
Identify Given Values
We are given the capacitance of the capacitor as \( C = 7.28 \mu \text{F} \) and the potential difference \( V = 25.0 \text{V} \). Convert the capacitance to farads: \( 7.28 \mu \text{F} = 7.28 \times 10^{-6} \text{F} \).
02
Apply the Capacitance Formula
The relationship between charge \( Q \), capacitance \( C \), and potential difference \( V \) is given by the formula: \( Q = C \times V \).
03
Substitute Values
Substitute the given values into the formula: \( Q = 7.28 \times 10^{-6} \text{F} \times 25.0 \text{V} \).
04
Calculate the Charge
Perform the calculation:\[Q = 7.28 \times 10^{-6} \times 25.0 = 1.82 \times 10^{-4} \text{C} = 182 \mu \text{C}.\]
05
Verify Units and Result
Ensure that the units are consistent and reasonable. The calculated charge is \( 182 \mu \text{C} \), which fits given that both the capacitance and potential difference are typical values.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Charge on Capacitor Plates
When a capacitor is charged, an equal amount of positive and negative charge accumulates on each of its plates. This charge is denoted by the symbol \(Q\). Essentially, a capacitor stores energy in the form of electrical charge. The charge is directly related to the capacitor's ability to hold this charge and the potential difference across its plates.
- To determine the charge on the plates, we rely on the relationship between charge \(Q\), capacitance \(C\), and potential difference \(V\).
- The charge on the plates is measured in coulombs, a unit that represents electric charge.
- In practical terms, this stored charge can be discharged later to power electrical devices.
Capacitance Formula
The capacitance formula is a fundamental equation used to relate three important components: charge \(Q\), capacitance \(C\), and potential difference \(V\). According to the formula:\[ Q = C \times V \]
- \(Q\) represents the charge stored in the capacitor measured in coulombs.
- \(C\) stands for capacitance, the ability of the capacitor to store charge, measured in farads (F).
- \(V\) is the potential difference across the capacitor's plates, measured in volts (V).
Potential Difference
The potential difference, also known as voltage, is the measure of work needed to move a unit charge from one point to another in an electric field. In the context of a capacitor, it refers to the voltage across the capacitor's plates. When we say a capacitor has a potential difference, we're talking about the energy per unit charge that's available to move charges between the plates.
- Potential difference is measured in volts (V).
- A higher potential difference implies more energy is stored in the capacitor.
- It determines, along with the capacitance, the total charge stored on the capacitor's plates.