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Three point charges are placed on the \(y\) -axis: a charge \(q\) at \(y=a,\) a charge \(-2 q\) at the origin, and a charge \(q\) at \(y=-a\) . Such an arrangement is called an electric quadrupole. (a) Find the magnitude and direction of the electric field at points on the positive \(x\) -axis. (b) Use the binomial expansion to find an approximate expression for the electric field valid for \(x \gg a\) . Contrast this behavior to that of the electric field of a point charge and that of the electric field of a dipole.

Short Answer

Expert verified
The electric field magnitude at positive x-axis is approx. \( -\frac{3kqa^2}{x^4} \) for \(x\gg a\), showing quartic decrease.

Step by step solution

01

Identify Charge Positions and Configuration

We have three point charges: a charge \( q \) at position \( (0, a) \), a charge \( -2q \) at the origin \( (0, 0) \), and a charge \( q \) at position \( (0, -a) \). This setup forms an electric quadrupole along the \( y \)-axis.
02

Determine the Electric Field Expressions

The electric field due to a point charge is given by \( \mathbf{E} = \frac{kq}{r^2} \hat{r} \). The total electric field on the positive \( x \)-axis from all three charges will be a vector sum of the fields from each charge. For a point \( (x, 0) \), the distances to each charge are \( r_1 = \sqrt{x^2 + a^2} \), \( r_2 = x \), and \( r_3 = \sqrt{x^2 + a^2} \), for the charges at \( y = a, 0, -a \) respectively.
03

Calculate Electric Field from Each Charge at Positive x-axis

For the charge \( q \) at \( y = a \), the x-component of its electric field at \( (x, 0) \) is \( E_{1,x} = \frac{kq(x)}{(x^2 + a^2)^{3/2}} \). Similarly, for the charge \( q \) at \( y = -a \), the x-component is given by the same expression: \( E_{3,x} = \frac{kq(x)}{(x^2 + a^2)^{3/2}} \). For the charge \( -2q \) at the origin, the x-component is \( E_{2,x} = \frac{-2kq}{x^2} \).
04

Sum up the x-components of Electric Field

The total electric field at \( x \) is the sum of the x-components: \[ E_{\text{total, x}} = \frac{kq(x)}{(x^2 + a^2)^{3/2}} + \frac{kq(x)}{(x^2 + a^2)^{3/2}} - \frac{2kq}{x^2} \]. Simplifying, \[ E_{\text{total, x}} = \frac{2kqx}{(x^2 + a^2)^{3/2}} - \frac{2kq}{x^2} \].
05

Use Binomial Expansion for Approximation

For \( x \gg a \), approximate \( (x^2 + a^2)^{-3/2} \approx x^{-3} (1 - \frac{3a^2}{2x^2}) \) using binomial expansion. Substitute this back into the expression for \( E_{\text{total, x}} \): \[ E_{\text{total, x}} \approx \frac{2kqx}{x^3}(1 - \frac{3a^2}{2x^2}) - \frac{2kq}{x^2} = \frac{2kq}{x^2}(-\frac{3a^2}{2x^2}) \]. The dominant term as \( x \rightarrow \infty \) behaves as \( -\frac{3kqa^2}{x^4} \), indicating a quartic decrease with distance, unlike the monopole \( (\frac{kq}{x^2}) \) or dipole \( (\frac{kqa}{x^3}) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Field
An electric field is a fundamental concept in physics that describes the region around a charged object where electric forces operate. If a charge is placed within an electric field, it will experience a force. The strength and direction of this force depend on both the charge creating the field and the charge being influenced by it.
  • The electric field \( \mathbf{E} \) due to a point charge is calculated using Coulomb's law: \( \mathbf{E} = \frac{kq}{r^2} \hat{r} \), where \( k \) is Coulomb's constant, \( q \) is the magnitude of the charge, and \( r \) is the distance from the charge.
  • The direction of the electric field is away from positive charges and towards negative charges.
In the context of an electric quadrupole, which involves three-point charges, the electric field is determined by calculating the contributions from each charge and summing them. This involves understanding vector components because the field has both magnitude and direction.
Binomial Expansion
Binomial expansion is a mathematical method used for approximating expressions that involve terms raised to a power, especially useful when the terms involve large or small values.
  • The binomial theorem declares that \( (1 + x)^n = 1 + nx + \frac{n(n-1)}{2}x^2 + \ldots \), where \( n \) is a real number and \( x \) is small compared to 1.
  • In physics, we often use binomial expansion to simplify terms like \( (x^2 + a^2)^{-3/2} \) when \( x \) is much larger than \( a \).
For the electric quadrupole, using the binomial expansion helps find an approximate expression for the electric field when the observation point is far from the charge configuration. This approximation shows how the electric field behaves differently compared to simpler systems like monopoles or dipoles.
Point Charge
A point charge refers to a charged entity that is considered to be infinitesimally small, allowing us to analyze electric fields as if the charge is centralized at a single point. This simplification is essential for mathematical computations and theoretical physics.
  • Point charges are hypothetical but useful in calculations where the actual size of the charge does not affect the problem.
  • The electric field around a point charge decreases with the square of the distance from the charge, in accordance with the equation \( \mathbf{E} = \frac{kq}{r^2}\hat{r} \).
In the given exercise, the charges \( q \) and \( -2q \) are considered as point charges, which allows us to apply the formula for the electric field to each charge individually and then sum the results to find the total field.
Dipole
An electric dipole consists of two equal and opposite charges separated by some fixed distance. The significance of a dipole lies in its ability to model complex charge systems simply and analyze fields and potentials. Helpful in understanding molecules and more complex charge interactions.
  • The electric field of a dipole at a point in space diminishes with the cube of the distance from the dipole rather than with the square, as seen in monopoles.
  • The field is expressed by the formula \( \mathbf{E} = \frac{kqa}{r^3} \hat{p} \), where \( a \) is the separation distance and \( \hat{p} \) is the vector pointing from negative to positive charge.
In an electric quadrupole, the dipole model is extended by adding another pair of charges, further complicating the field behavior and making the use of approximations such as binomial expansions more important to understand the drop-off with distance as different from both dipoles and monopoles. This explains why the electric field drops off more rapidly (\( x^4 \) compared to \( x^3 \) or \( x^2 \) for simpler configurations).

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Most popular questions from this chapter

A positive point charge \(q\) is placed at \(x=a,\) and a negative point charge \(-q\) is placed at \(x=-a\) . (a) Find the magnitude and direction of the electric field at \(x=0\) .(b) Derive an expression for the electric field at points on the \(x\) - axis. Use your result to graph the \(x\) -component of the electric field as a function of \(x\) , for values of \(x\) between \(-4 a\) and \(+4 a\) .

(a) An electron is moving east in a uniform electric field of 1.50 \(\mathrm{N} / \mathrm{C}\) directed to the west. At point \(A,\) the velocity of the electron is \(4.50 \times 10^{5} \mathrm{m} / \mathrm{s}\) toward the east. What is the speed of the electron when it reaches point \(B, 0.375 \mathrm{m}\) east of point \(A ?(\mathrm{b}) \mathrm{A}\) proton is moving in the uniform electric field of part (a). At point \(A .\) the velocity of the proton is \(1.90 \times 10^{4} \mathrm{m} / \mathrm{s}\) , east. What is the speed of the proton at point \(B ?\)

Two particles having charges \(q_{1}=0.500 \mathrm{nC}\) and \(q_{2}=8.00 \mathrm{nC}\) are separated by a distance of 1.20 \(\mathrm{m}\) . At what point along the line connecting the two charges is the total electric field due to the two charges equal to zero?

Lightning occurs when there is a flow of electric charge (principally electrons) between the ground and a thundercloud. The maximum rate of charge flow in a lightning bolt is about \(20,000 \mathrm{C} / \mathrm{s} ;\) this lasts for 100\(\mu \mathrm{s}\) or less. How much charge flows between the ground and the cloud in this time? How many electrons flow during this time?

In a rectangular coordinate system a positive point charge \(q=6.00 \times 10^{-9} \mathrm{C}\) is placed at the point \(x=+0.150 \mathrm{m}, y=0,\) and an identical point charge is placed at \(x=-0.150 \mathrm{m}, y=0\) . Find the \(x\) - and \(y\) -components, the magnitude, and the direction of the electric field at the following points: \((a)\) the origin; \((b) x=\) \(0.300 \mathrm{m}, y=0 ;(\mathrm{c}) x=0.150 \mathrm{m}, y=-0.400 \mathrm{m} ;(\mathrm{d}) x=0\) \(y=0.200 \mathrm{m} .\)

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