/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 (a) Sketch the electric field li... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) Sketch the electric field lines for an infinite line of charge. You may find it helpful to show the field lines in a plane containing the line of charge in one sketch and the field lines in a a plane perpendicular to the line of charge in a second sketch. (b) Explain how your sketches show (i) that the magnitude \(E\) of the electric field depends only on the distance \(r\) from the line of charge and (ii) that \(E\) decreases like \(1 / r .\)

Short Answer

Expert verified
The electric field lines radiate outward and show that the field strength depends on \(r\) and decreases as \(1/r\).

Step by step solution

01

Visualize the Geometry

Understand that an infinite line of charge can be imagined as an endless string of charge extending in both directions. This means our line of charge has symmetry along its length, making our analysis focused on radial distance from the line only.
02

Sketch the Electric Field Lines in a Plane Containing the Line

In a plane containing the line of charge, the electric field lines originate radially outward from the line. Because of symmetry, these lines are straight and extend perpendicular to the line of charge indefinitely. Remember, field lines never cross each other.
03

Sketch the Electric Field Lines in a Perpendicular Plane

In a plane perpendicular to the line of charge, you can imagine the field lines radiating out from a series of points along the line. The sketch would appear as radial lines uniformly spaced like the spokes of a wheel all pointing away from where the line charge intersects the plane.
04

Explain Dependence of Magnitude on Distance

Since field lines are straight and the same at all points equidistant from the line of charge, the pattern shows that the magnitude of the electric field depends only on the distance from the line. Greater density of lines (closer to the line) indicates a stronger field, supporting the notion that the field varies with distance.
05

Show Decrease of Electric Field as 1/r

For an infinite line of charge, the density of the electric field lines illustrates that the field strength decreases as you move away from the line. The spacing between lines increases linearly with distance, demonstrating mathematically that the electric field decreases as the inverse of the distance, or as \(1/r\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Infinite Line of Charge
Imagine an infinite line of charge as a line that stretches endlessly in both directions. This concept is crucial because it introduces the idea of symmetry. A key feature of an infinite line of charge is that it exhibits continuous uniform charge distribution along its length. This symmetry simplifies our analysis, allowing us to focus solely on the radial aspects of the electric field around it. You won't need to worry about what happens at the "ends" of the line, because there are no ends. By assuming the line of charge is infinite, we can conclude that the electric field has the same characteristics at any point along the line. The nature of the infinite line of charge forms the basis of understanding how electric fields behave in its vicinity, and why the problem narrows to radial considerations alone.
Electric Field Magnitude
The electric field magnitude around an infinite line of charge is essential to understanding how strong the electric force is at any given point in space. To visualize this, imagine the electric field lines radiating outwards from the line of charge. These lines are straight and problematically extend infinitely in radial directions. The magnitude of the electric field at any point depends on how densely packed these field lines are. Closer to the line, the lines are denser, indicating a stronger electric field. This is the clue that tells us the magnitude depends on proximity to the charge. The mathematical relationship can be expressed using the formula: \[ E = \frac{\lambda}{2 \pi \varepsilon_0 r} \] where \( \lambda \) is the linear charge density, \( \varepsilon_0 \) is the permittivity of free space, and \( r \) is the radial distance from the line.
Electric Field and Distance
When it comes to understanding how the electric field interacts with distance, it's crucial to recognize the inverse relationship it holds. As you move further away from the infinite line of charge, the electric field's strength diminishes. This dependency is visualized through the increasing spacing between electric field lines as one moves away from the line. The field's decrease with distance follows an inverse relationship with the radial distance \( r \). In simpler terms, if you double your distance from the line, the electric field strength decreases by half. This follows the expression \[ E \propto \frac{1}{r} \] which signifies that the electric field strength is inversely proportional to the radial distance from the line of charge. Observing this interaction gives us an insightful view of how electric fields behave over varying distances from a linear charge source.
Electric Field Symmetry
Electric field symmetry is a powerful concept that simplifies analyzing complex electric field problems. In the case of an infinite line of charge, symmetry plays a pivotal role. The symmetry here refers to the fact that the electric field is the same at any point at a given radial distance from the line, regardless of the angle around the line. This uniformity arises due to the infinite length and uniform charge distribution. Consequently, when we draw electric field lines in a plane perpendicular to the line, they appear evenly spaced, like spokes on a wheel. The radial nature of the electric field lines showcases this perfect symmetry, which arises due to the consistent charge distribution along the length. This understanding of symmetry not only helps with visualization but also simplifies the mathematical treatment of the electric field near an infinite line of charge.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Estimate how many electrons there are in your body. Make any assumptions you feel are necessary, but clearly state what they are. (Hint: Most of the atoms in your body have equal numbers of electrons, protons, and neutrons.) What is the combined charge of all these electrons?

\(A+2.00-n C\) point charge is at the origin, and a second \(-5.00-n C\) point charge is on the \(x\) -axis at \(x=0.800 \mathrm{m}\) . (a) Find the electric field (magnitude and direction) at each of the following points on the \(x\) -axis: \((\text { i) } x=0.200 \mathrm{m} ; \text { (ii) } x=1.20 \mathrm{m} ; \text { (iii) } x=\) \(-0.200 \mathrm{m} .\) (b) Find the net electric force that the two charges would exert on an electron placed at each point in part (a).

A negative point charge \(q_{1}=-4.00 \mathrm{nC}\) is on the \(x\) -axis at \(x=0.60 \mathrm{m} .\) A second point charge \(q_{2}\) is on the \(x\) -axis at \(x=\) \(-1.20 \mathrm{m} .\) What must the sign and magnitude of \(q_{2}\) be for the net electric field at the origin to be (a) 50.0 \(\mathrm{N} / \mathrm{C}\) in the \(+x\) -direction and \((b) 50.0 \mathrm{N} / \mathrm{C}\) in the \(-x\) -direction?

Infinite sheet \(A\) carries a positive uniform charge density \(\sigma\) , and sheet \(B\) , which is to the right of \(A\) and parallel to it, carries a uniform negative charge density \(-2 \sigma .\) (a) Sketch the electric field lines for this pair of sheets. Include the region between the sheets as well as the regions to the left of \(A\) and to the right of \(B\) . (b) Repeat part (a) for the case in which sheet \(B\) carries a charge density of \(+2 \sigma .\)

An electron is released from rest in a uniform electric field. The electron accelerates vertically upward, traveling 4.50 \(\mathrm{m}\) in the first 3.00\(\mu\) s after it is released. (a) What are the magnitude and direction of the electric field? (b) Are we justified in ignoring the effects of gravity? Justify your answer quantitatively.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.