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(a) Calculate the specific heat capacity at constant volume of water vapor, assuming the nonlinear triatomic molecule has three translational and three rotational degrees of freedom and that vibrational motion does not contribute. The molar mass of water is 18.0 g/mol. (b) The actual specific heat capacity of water vapor at low pressures is about 2000 \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{K}\) . Compare this with your calculation and comment on the actual role of vibrational motion.

Short Answer

Expert verified
The calculated specific heat capacity (1385.67 J/kg·K) is less than the actual value (2000 J/kg·K), indicating the importance of vibrational motion.

Step by step solution

01

Understanding the Degrees of Freedom

Water vapor is a nonlinear triatomic molecule. For such molecules, there are 3 translational and 3 rotational degrees of freedom. In this context, we assume that vibrational motion does not contribute.
02

Calculating Molar Specific Heat Capacity

The specific heat capacity at constant volume for an ideal gas is given by the expression: \[ c_v = \left( \frac{f}{2} \right) R \] where \(f\) is the number of degrees of freedom and \(R = 8.314 \ \mathrm{J/mol \cdot K} \) is the universal gas constant. Since \(f = 6\) for water vapor,\[ c_v = \left( \frac{6}{2} \right) \cdot 8.314 = 3 \cdot 8.314 = 24.942 \ \mathrm{J/mol \cdot K} \]
03

Converting to Specific Heat Capacity per Kilogram

The mass of one mole of water is 18 g or 0.018 kg. Knowing the molar specific heat capacity, we convert it to the specific heat capacity per kilogram:\[ c_v = \frac{24.942 \ \mathrm{J/mol \cdot K}}{0.018 \ \mathrm{kg/mol}} = 1385.67 \ \mathrm{J/kg \cdot K} \]
04

Comparison with Actual Specific Heat Capacity

The calculated specific heat capacity \(1385.67 \ \mathrm{J/kg \cdot K}\) is less than the actual value \(2000 \ \mathrm{J/kg \cdot K}\). This suggests that vibrational motion, which was neglected in the calculation, plays a significant role, especially as temperature increases or at low pressures where interactions allow additional modes to be active.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
Degrees of freedom in molecules help describe how particles can move in three-dimensional space. For water vapor, a nonlinear triatomic molecule, we consider different types of movements:

- **Translational Motion:** These are straight-line movements. Molecules can move in three directions (x, y, and z axes), corresponding to three translational degrees of freedom.
- **Rotational Motion:** This is the spinning of molecules around their own axes. For nonlinear molecules like water vapor, there are also three rotational degrees of freedom.

In the calculation of specific heat capacity of water vapor, it's assumed that only translational and rotational motions contribute. This is why six degrees of freedom are used in the formula. Vibrational degrees of freedom are ignored as they become significant only at higher energies or different conditions.

Understanding degrees of freedom helps in predicting energy distribution within a molecule and its response to temperature changes. It aids in calculating physical properties like specific heat capacity, vital for engineering and scientific applications.
Molar Mass
Molar mass is the mass of one mole of a substance. For molecules, it allows us to relate mass with amount in moles, crucial for stoichiometric calculations.

- **Definition:** Water has a molar mass of 18.0 g/mol. This tells us that one mole of water molecules weighs 18.0 grams.
- **Use in Calculations:** In the example, molar mass is used to convert between molar specific heat capacity and specific heat capacity per kilogram. This conversion is essential because scientific data on specific heat is often expressed per mole or per mass unit.

The ability to switch between these units using molar mass is critical in thermodynamics. It helps understand how molecular structure and interactions are experienced on a global scale, like in gases, whether in laboratory conditions or natural processes.
Rotational and Translational Motion
Molecules can exhibit both rotational and translational motions, which contribute to their energy and affect properties like specific heat capacity.

- **Translational Motion:** All types of molecules experience translational motion where they move in linear paths. This motion is fundamentally linked to temperature and gas pressure as it represents kinetic energy.
- **Rotational Motion:** Molecules spin around different axes. In gases, rotation also adds to their internal energy. Nonlinear molecules like water have three rotational degrees of freedom, enriching their energy dynamics.

These motions are pivotal in energy exchange processes and in defining molecular behavior. In the exercise, they form the basis of calculating the theoretical specific heat capacity of water vapor. Recognizing the precise role of rotational and translational movements helps in developing accurate models of physical phenomena, which is indispensable for both scientific exploration and practical technology advancements.

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Most popular questions from this chapter

The conditions of standard temperature and pressure (STP) are a temperature of \(0.00^{\circ} \mathrm{C}\) and a pressure of 1.00 \(\mathrm{atm}\) . (a) How many liters does 1.00 \(\mathrm{mol}\) of any ideal gas occupy at STP? (b) For a scientist on Venus, an absolute pressure of 1 Venusian-atmosphere is 92 Earth- atmospheres. Of course she would use the Venusian-atmosphere to define STP. Assuming she kept the same temperature, how many liters would 1 mole of ideal gas occupy on Venus?

You have several identical balloons. You experimentally determine that a balloon will break if its volume exceeds 0.900 \(\mathrm{L}\). The pressure of the gas inside the balloon equals air pressure \((1.00 \mathrm{atm} \). (a) If the air inside the balloon is at a constant temperature of \(22.0^{\circ} \mathrm{C}\) and behaves as an ideal gas, what mass of air can you blow into one of the balloons before it bursts? (b) Repeat part (a) if the gas is helium rather than air.

Consider 5.00 mol of liquid water. (a) What volume is occupied by this amount of water? The molar mass of water is 18.0 \(\mathrm{g} / \mathrm{mol}\) (b) Imagine the molecules to be, on average, uniformly spaced, with each molecule at the center of a small cube. What is the length of an edge of each small cube if adjacent cubes touch but don't overlap? (c) How does this distance compare with the diameter of a molecule?

(a) A process called gaseous diffusion is often used to separate isotopes of uranium-that is, atoms of the elements that have different inasses, such as \(^{235} \mathrm{U}\) and \(^{238} \mathrm{U}\) . The only gaseous compound of uranium at ordinary temperatures is uranium hexafluoride, \(\mathrm{UF}_{6}\) . Speculate on how 235 \(\mathrm{UF}_{6}\) and \(^{238} \mathrm{UF}_{6}\) inolecules might be separated by diffusion. (b) The molar masses for \(^{235} \mathrm{UF}_{6}\) and \(^{238} \mathrm{UF}_{6}\) molecules are 0.349 \(\mathrm{kg} / \mathrm{mol}\) and \(0.352 \mathrm{kg} / \mathrm{nol},\) respectively. If uranium hexafluoride acts as an ideal gas, what is the ratio of the root-mean- square speed of \(^{235} \mathrm{UF}_{6}\) molecules to that of \(^{238} \mathrm{UF}_{6}\) molecules if the temperature is uniform?

A \(3.00-\mathrm{L}\) tank contains air at 3.00 \(\mathrm{atm}\) and \(20.0^{\circ} \mathrm{C} .\) The tank is sealed and cooled until the pressure is 1.00 atm. (a) What is the temperature then in degrees Celsius? Assume the volume of the tank is constant. (b) If the temperature is kept at the value found in part (a) and the gas is compressed, what is the vohme when the pressure again becomes 3.00 \(\mathrm{atm} ?\)

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