/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 The atmosphere of Mars is mostly... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The atmosphere of Mars is mostly \(\mathrm{CO}_{2}\) (molar mass 44.0 \(\mathrm{g} / \mathrm{mol} )\) under a pressure of 650 \(\mathrm{Pa}\) , which we shall assume remains constant. In many places the temperature varies from \(0.0^{\circ} \mathrm{C}\) in summer to \(-100^{\circ} \mathrm{C}\) in winter. Over the course of a martian year, what are the ranges of \((\mathrm{a})\) the rms speeds of the \(\mathrm{CO}_{2}\) molecules, and (b) the density (in mollm') of the atmosphere?

Short Answer

Expert verified
Rms speeds range from 328 m/s to 393 m/s, and density ranges from 0.288 to 0.450 mol/m³.

Step by step solution

01

Understand the Given Data

We have the following information:- Molar mass of \( \mathrm{CO}_2 \) is 44.0 g/mol.- Pressure of the \( \mathrm{CO}_2 \) is 650 Pa (constant).- Temperature ranges from \( 0.0^{\circ} \mathrm{C} \) to \( -100^{\circ} \mathrm{C} \).
02

Convert Temperatures to Kelvin

Convert both temperatures to Kelvin:- Summer: \( 0.0^{\circ}C = 273.15 \, \mathrm{K} \)- Winter: \( -100^{\circ}C = 173.15 \, \mathrm{K} \)
03

Calculate RMS Speeds

The rms speed \( v_{rms} \) of gas molecules is calculated using the formula:\[ v_{rms} = \sqrt{\frac{3kT}{m}} \]where \( k \) is the Boltzmann constant \( (1.38 \times 10^{-23} \, \mathrm{J/K}) \), \( T \) is the temperature in Kelvin, and \( m \) is the mass of one molecule.- Summer: \( m = \frac{44.0}{1000} \times \frac{1}{6.022 \times 10^{23}} \approx 7.3 \times 10^{-26} \, \mathrm{kg} \)Thus, \( v_{rms}^{\text{summer}} = \sqrt{\frac{3 \times 1.38 \times 10^{-23} \times 273.15}{7.3 \times 10^{-26}} } \approx 393 \, \mathrm{m/s} \)- Winter: Calculate similarly for 173.15 K.\( v_{rms}^{\text{winter}} = \sqrt{\frac{3 \times 1.38 \times 10^{-23} \times 173.15}{7.3 \times 10^{-26}} } \approx 328 \, \mathrm{m/s} \)
04

Use Ideal Gas Law to Find Density

The density \( \rho \) can be found using the Ideal Gas Law: \( PV = nRT \), where \( R \) is the gas constant (8.314 J/mol·K) and \( n/V \) is the molar density.Rearranging for \( \rho \) gives:\[ \rho = \frac{P}{RT} \]- Summer: \( \rho_{\text{summer}} = \frac{650}{8.314 \times 273.15} \approx 0.288 \, \mathrm{mol/m^3} \)- Winter: \( \rho_{\text{winter}} = \frac{650}{8.314 \times 173.15} \approx 0.450 \, \mathrm{mol/m^3} \)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

rms speed calculation
The root mean square (rms) speed of gas molecules is a crucial concept in the kinetic theory of gases. It represents the average speed of gas molecules in a sample, giving us insight into their kinetic energy. The formula for calculating the rms speed, \( v_{rms} \), is given by:
\[ v_{rms} = \sqrt{\frac{3kT}{m}} \]
where:
  • \( k \) is the Boltzmann constant, valued at \( 1.38 \times 10^{-23} \text{ J/K} \).
  • \( T \) is the temperature in Kelvin.
  • \( m \) is the mass of one molecule of the gas.
The speed increases with temperature because the molecules move faster as the temperature rises. For example, at Martian summer temperatures \( (0^{\circ}C = 273.15 \text{ K}) \), the \( \mathrm{CO}_{2} \) molecules move at about \( 393 \text{ m/s} \), whereas in the winter \( (-100^{\circ}C = 173.15 \text{ K}) \), they slow down to \( 328 \text{ m/s} \). This showcases the direct relationship between temperature and molecular speed.
ideal gas law
The Ideal Gas Law is a fundamental principle in the study of gases, articulated through the equation \( PV = nRT \). It correlates the pressure, volume, and temperature of an ideal gas with its quantity. Here's a breakdown of what each symbol signifies:
  • \( P \) is the pressure of the gas.
  • \( V \) is the volume the gas occupies.
  • \( n \) is the number of moles of the gas.
  • \( R \) is the universal gas constant, fixed at \( 8.314 \text{ J/molâ‹…K} \).
  • \( T \) is the absolute temperature in Kelvin.
To find the molar density \( \rho \), which is the amount of substance per volume unit, the equation can be rearranged to \( \rho = \frac{P}{RT} \). Applying this helps determine the atmosphere's density on Mars during different seasons. For instance, at a summer temperature of \( 273.15 \text{ K} \), the density calculates to \( 0.288 \text{ mol/m}^3 \). During the colder winter at \( 173.15 \text{ K} \), the density becomes \( 0.450 \text{ mol/m}^3 \), illustrating the increase in density as temperature decreases.
molar mass
The molar mass of a substance refers to the mass of one mole of its molecules or atoms, often expressed in grams per mole (g/mol). For carbon dioxide \( (\text{CO}_2) \), the molar mass is \( 44.0 \text{ g/mol} \), which implies that one mole of carbon dioxide molecules weighs 44 grams.
Knowing the molar mass is crucial in various calculations, such as determining the mass of a single molecule. This calculation is done by converting grams to kilograms, dividing by Avogadro's number \( (6.022 \times 10^{23} \text{ mol}^{-1}) \), which gives the mass of one \( \text{CO}_2 \) molecule as approximately \( 7.3 \times 10^{-26} \text{ kg} \).
This significant factor enters the rms speed calculation, as it enables the transition from macroscopic molar mass to the microscopic mass of individual molecules. Understanding molar mass bridges the particle world with tangible calculations, allowing us to apply theoretical concepts to real-world scenarios effectively.
temperature conversion to Kelvin
Temperature plays a pivotal role in physical science, and its correct measurement is essential for precise calculations in kinetics and thermodynamics. Every temperature scale serves different purposes, but the Kelvin scale is particularly suitable for scientific purposes.
To convert from Celsius to Kelvin, simply add 273.15 to the Celsius degree value. For example, Mars' summer temperature of \( 0.0^{\circ}C \) converts to \( 273.15 \text{ K} \), and the winter temperature of \( -100^{\circ}C \) becomes \( 173.15 \text{ K} \).
This conversion is vital for using the Ideal Gas Law and calculating the rms speeds because Kelvin is the unit for thermodynamic temperature in these contexts. Ensuring temperatures are in Kelvin allows for consistent and accurate use of formulas across various gas laws and kinetic energy calculations, minimizing errors that arise from temperature discrepancies.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The conditions of standard temperature and pressure (STP) are a temperature of \(0.00^{\circ} \mathrm{C}\) and a pressure of 1.00 \(\mathrm{atm}\) . (a) How many liters does 1.00 \(\mathrm{mol}\) of any ideal gas occupy at STP? (b) For a scientist on Venus, an absolute pressure of 1 Venusian-atmosphere is 92 Earth- atmospheres. Of course she would use the Venusian-atmosphere to define STP. Assuming she kept the same temperature, how many liters would 1 mole of ideal gas occupy on Venus?

A large cylindrical tank contains 0.750 in \(^{3}\) of nitrogen gas at \(27^{\circ} \mathrm{C}\) and \(1.50 \times 10^{5} \mathrm{Pa}\) (absolute pressure). The tank has a tight-fitting piston that allows the volume to be changed. What will be the pressure if the volume is decreased to 0.480 \(\mathrm{m}^{3}\) and the temperature is increased to \(157^{\circ} \mathrm{C}\) ?

We have two equal-size boxes, \(A\) and \(B\) . Each box contains gas that behaves as an ideal gas. We insert a thermometer into each box and find that the gas in box \(A\) is at a temperature of \(50^{\circ} \mathrm{C}\) while the gas in box \(B\) is at \(10^{\circ} \mathrm{C}\) . This is all we know about the gas in the boxes. Which of the following statements must be true? Which could be true? (a) The pressure in \(A\) is higher than in \(B\) . There are more molecules in \(A\) than in \(B .(\mathrm{c}) A\) and \(B\) cannot contain the same type of gas. (d) The molecules in \(A\) have more average kinetic energy per molecule than those in \(B\) . (e) The molecules in \(A\) are moving faster than those in \(B\) . Explain the reasoning behind your answers.

Three moles of an ideal gas are in a rigid cubical box with sides of length 0.200 \(\mathrm{m}\) . (a) What is the force that the gas exerts on each of the six sides of the box when the gas temperature is \(20.0^{\circ} \mathrm{C} ?\) (b) What is the force when the temperature of the gas is increased to \(100.0^{\circ} \mathrm{C}\) ?

Atmosphere of Titan. Titan, the largest satellite of Saturn, has a thick nitrogen atmosphere. At its surface, the pressure is 1.5 Earth-atmospheres and the temperature is 94 \(\mathrm{K}\) . (a) What is the surface temperature in \(^{\circ} \mathrm{C}\) ? (b) Calculate the surface density in Titar's atmosphere in molecules per cubic meter (c) Compare the density of Titan's surface atmosphere to the density of Earth's atmosphere at \(22^{\circ} \mathrm{C}\) . Which body has denser atmosphere?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.