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Waves of Arbitrary Shape. (a) Explain why any wave described by a function of the form \(y(x, t)=f(x-v t)\) moves in the \(+x\) -direction with speed \(v\) . (b) Show that \(y(x, t)=f(x-v t)\) satisfies the wave equation, no matter what the functional form of \(f\) . To do this, write \(y(x, t)=f(u),\) where \(u=x-v t\) . Then, to take partial derivatives of \(y(x, t),\) use the chain rule: $$ \begin{array}{l}{\frac{\partial y(x, t)}{\partial t}=\frac{d f(u)}{d u} \frac{\partial u}{\partial t}=\frac{d f(u)}{d u}(-v)} \\ {\frac{\partial y(x, t)}{\partial x}=\frac{d f(u)}{d u} \frac{\partial u}{\partial x}=\frac{d f(u)}{d u}}\end{array} $$ (c) A wave pulse is described by the function \(y(x, t)=D e^{-(B x-C)^{2}}\) where \(B, C,\) and \(D\) are all positive constants. What is the speed of this wave?

Short Answer

Expert verified
The wave moves in the +x direction with speed \( v \); it satisfies the wave equation; the speed of the wave pulse is \( \frac{C}{B} \).

Step by step solution

01

Understand wave motion along +x

A wave function of the form \( y(x, t) = f(x - vt) \) moves in the \( +x \) direction because the argument of the function, \( x - vt \), represents a constant wave shape moving to the right as time \( t \) increases. The parameter \( v \) is the speed because for a fixed shape \( f \) to be at the same position as time changes, the position \( x \) must increase, indicating motion in the positive \( x \)-direction.
02

Confirm wave equation satisfaction

To show \( y(x, t) = f(x - vt) \) satisfies the wave equation, start by letting \( u = x - vt \), hence \( y(x, t) = f(u) \). Find the partial derivatives using the chain rule: \( \frac{\partial y}{\partial t} = \frac{df(u)}{du}(-v) \) and \( \frac{\partial y}{\partial x} = \frac{df(u)}{du} \). Next, compute the second derivatives: \( \frac{\partial^2 y}{\partial t^2} = -v \frac{d^2f(u)}{du^2} \cdot v = v^2 \frac{d^2f(u)}{du^2} \) and \( \frac{\partial^2 y}{\partial x^2} = \frac{d^2f(u)}{du^2} \). The wave equation \( \frac{\partial^2 y}{\partial t^2} = v^2 \frac{\partial^2 y}{\partial x^2} \) is satisfied because \( v^2 \frac{d^2f(u)}{du^2} = v^2 \frac{d^2f(u)}{du^2} \).
03

Solve for wave speed in given function

Given the wave function \( y(x, t) = D e^{-(Bx - Ct)^2} \), compare it with the general wave form \( y(x, t) = f(x - vt) \). Here, rewrite the expression inside the exponent as \( Bx - Ct = B(x - \frac{C}{B}t) \), which matches the form \( x - vt \) with \( v = \frac{C}{B} \). Thus, the speed \( v \) is \( \frac{C}{B} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
In calculus, the chain rule is a fundamental method used to differentiate composite functions. A composite function is essentially a function that is nested within another function.
For example, in the context of a wave equation represented as \( y(x, t) = f(x-vt) \), the term \( u = x-vt \) serves as our inner function, while \( f(u) \) acts as the outer function.
To solve for the partial derivatives of \( y(x, t) \) with respect to \( t \) and \( x \), we apply the chain rule.
  • Since \( y(x, t) = f(u) \), the derivative \( \frac{\partial y}{\partial t} \) requires us to differentiate \( f(u) \) with respect to \( u \), then multiply by the derivative of \( u = x-vt \) with respect to \( t \), which is \(-v\).
  • Similarly, the derivative \( \frac{\partial y}{\partial x} \) is the derivative of \( f(u) \) with respect to \( u \), multiplied by the derivative of \( u \) with respect to \( x \), which is simply \( 1 \).
This chain rule application ensures that both time and spatial dependencies of our wave function are correctly accounted for.
Wave Speed
Wave speed is crucial in describing how fast a wave travels through a medium. For a wave equation such as \( y(x, t) = f(x-vt) \), the speed is determined by the parameter \( v \).
This value \( v \) represents the speed at which the wave's shape moves in the positive \( x \)-direction. As time progresses, if we were to hold the wave's shape constant, the wave's position along the \( x \)-axis will shift, rendering \( v \) as the measure of this positional change per unit of time.
  • Consider a wave pulse defined by \( y(x, t) = D e^{-(Bx - Ct)^2} \). Here, identifying similarities with the wave form \( y(x, t) = f(x-vt) \) allows computation of speed \( v \).
  • In this specific form, expressing \( Bx - Ct \) instead as \( B(x - \frac{C}{B}t) \) aligns this with \( x-vt \), concluding that \( v = \frac{C}{B} \). Hence, \( \frac{C}{B} \) indicates the speed of the wave pulse.
Understanding and determining wave speed is vital in physics, closely tied to concepts like frequency and wavelength, serving as an essential parameter across many fields.
Partial Derivatives
Partial derivatives measure how a function changes as its input variables change incrementally, focusing on one variable at a time while the others remain constant. This idea is pivotal in multivariable calculus, especially in wave equations where changes in both space and time are considered.
For the wave function \( y(x, t) = f(x-vt) \), calculating partial derivatives helps understand wave behavior in both spatial and temporal dimensions.
  • First, the partial derivative \( \frac{\partial y}{\partial t} \) denotes how the wave amplitude changes over time, illustrating how the wave propagates or moves.
  • On the other hand, \( \frac{\partial y}{\partial x} \) indicates how the wave's shape alters along its path.
By determining these partial derivatives, we gain insights into the propagation dynamics without considering the interactions of other variables. Deriving these derivatives involves understanding and applying the chain rule to relate the changes with respect to \( u = x-vt \) back to \( x \) and \( t \), providing an elegant link between mathematics and real-world wave phenomena.

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Most popular questions from this chapter

Ultrasound Imaging. Sound having frequencies above the range of human hearing (about \(20,000 \mathrm{Hz}\) ) is called ultrasound. Waves above this frequency can be used to penetrate the body and to produce images by reflecting from surfaces. In a typical ultrasound scan, the waves travel through body tissue with a speed of 1500 \(\mathrm{m} / \mathrm{s}\) . For a good, detailed image, the wavelength should be no more than 1.0 \(\mathrm{mm}\) . What frequency sound is required for a good scan?

A piano wire with mass 3.00 \(\mathrm{g}\) and length 80.0 \(\mathrm{cm}\) is stretched with a tension of 25.0 \(\mathrm{N}\) . A wave with frequency 120.0 \(\mathrm{Hz}\) and amplitude 1.6 \(\mathrm{mm}\) travels along the wire. (a) Calculate the average power carried by the wave. (b) What happens to the average power if the wave amplitude is halved?

Tsunami! On December \(26,2004,\) a great earthquake occurred off the coast of Sumatra and triggered immense waves (tsunami) that killed some \(200,000\) people. Satellites observing these waves from space measured 800 \(\mathrm{kn}\) from one wave crest to the next and a period between waves of 1.0 hour. What was the speed of these waves in \(\mathrm{m} / \mathrm{s}\) and \(\mathrm{km} / \mathrm{h}\) ? Does your answer help you understand why the waves caused such devastation?

Energy in a Triangular Pulse. A triangular wave pulse on a taut string travels in the positive \(x\) -direction with speed \(v\) . The tension in the string is \(F,\) and the linear mass density of the string is \(\mu .\) At \(t=0,\) the shape of the pulse is given by $$ y(x, 0)=\left\\{\begin{array}{ll}{0} & {\text { if } x<-L} \\ {h(L+x) / L} & {\text { for }-LL}\end{array}\right. $$ (a) Draw the pulse at \(t=0 .\) (b) Determine the wave function \(y(x, t)\) at all times \(t\) (c) Find the instantancous power in the wave. Show that the power is zero except for \(-L<(x-v t)

One string of a certain musical instrument is 75.0 \(\mathrm{cm}\) long and has a mass of 8.75 \(\mathrm{g}\) . It is being played in a room where the speed of sound is 344 \(\mathrm{m} / \mathrm{s}\) . (a) To what tension must you adjust the string so that, when vibrating in its second overtone, it produces sound of wavelength 3.35 \(\mathrm{cm} ?\) (b) What frequency sound does this string produce in its fundamental mode of vibration?

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