/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 94 A rock with mass \(m=3.00 \mathr... [FREE SOLUTION] | 91影视

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A rock with mass \(m=3.00 \mathrm{kg}\) is suspended from the roof of an elevator by a light cord. The rock is totally immersed in a bucket of water that sits on the floor of the elevator, but the rock doesn't touch the bottom or sides of the bucket. (a) When the elevator is at rest, the tension in the cord is 21.0 \(\mathrm{N}\) . Calculate the volume of the rock. ( b) Derive an expression for the tension in the cord when the elevator is accelerating upward with an acceleration of magnitude a. Calculate the tension when \(a=2.50 \mathrm{m} / \mathrm{s}^{2}\) upward. (c) Derive an expression for the tension in the cord when the clevator is accelerating downwand with an acceleration of magnitude \(a\) . Calculate the tension when \(a=2.50 \mathrm{m} / \mathrm{s}^{2}\) downward. (d) What is the tension when the elevator is in free fall with a downward acceleration equal to \(g ?\)

Short Answer

Expert verified
The volume of the rock is 8.59脳10鈦烩伌 m鲁. Tension is 28.50 N upward and 13.50 N downward. During free fall, tension is 0 N.

Step by step solution

01

Calculate the Volume of the Rock at Rest

To find the volume of the rock, we use the fact that when the elevator is at rest, there is equilibrium of forces. The tension in the cord is given as 21.0 N, and the rock's weight can be found by multiplying its mass with the gravitational force: \\[ W = mg = 3.00 \, \text{kg} \times 9.81 \, \text{m/s}^2 = 29.43 \, \text{N} \] \The buoyant force acting upwards is the difference between the weight and tension: \\[ F_b = W - T = 29.43 \, \text{N} - 21.0 \, \text{N} = 8.43 \, \text{N} \] \Using the formula for buoyancy, \( F_b = \rho V g \), where \( \rho = 1000 \, \text{kg/m}^3 \) is the density of water, we solve for \( V \): \\[ V = \frac{F_b}{\rho g} = \frac{8.43 \, \text{N}}{1000 \, \text{kg/m}^3 \times 9.81 \, \text{m/s}^2} = 8.59 \times 10^{-4} \, \text{m}^3 \]
02

Find Tension When Accelerating Upward

When the elevator accelerates upward with acceleration \( a \), the apparent weight of the rock increases. The equation for tension is \\[ T = mg - F_b + ma = (3.00 \, \text{kg})(9.81 \, \text{m/s}^2) - 8.43 \, \text{N} + (3.00 \, \text{kg})(2.50 \, \text{m/s}^2) \] \This simplifies to: \\[ T = (29.43 \, \text{N} - 8.43 \, \text{N}) + 7.50 \, \text{N} = 28.50 \, \text{N} \]
03

Find Tension When Accelerating Downward

When the elevator accelerates downward with acceleration \( a \), the apparent weight decreases. The tension is given by: \\[ T = mg - F_b - ma = 29.43 \, \text{N} - 8.43 \, \text{N} - 7.50 \, \text{N} \] \This results in: \\[ T = 13.50 \, \text{N} \]
04

Find Tension During Free Fall

During free fall, the acceleration \( a = g \), meaning acceleration due to gravity equals the gravitational acceleration, resulting in weightlessness. Thus, \\[ T = mg - F_b - mg = 0 \, \text{N} \] \The tension is zero because the rock is in free fall and experiences no upward force against gravity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law is key in understanding how forces affect motion. It states that the force acting on an object is equal to the mass of that object multiplied by its acceleration, or \( F = ma \). This law is fundamental when examining motion in an elevator.
When you are in an elevator and it starts to move, either up or down, there is a change in the motion of the objects inside it. This is due to the acceleration of the elevator itself, which changes the tension in the cord holding the rock.
  • If the elevator is accelerating upwards, the force required is greater, thereby increasing the tension in the cord.
  • Conversely, if the elevator accelerates downward, the force needed is reduced, decreasing the tension.
Understanding the changes in tension due to acceleration is a direct application of Newton's Second Law. Calculating tension variations is essential to understanding how forces balance in various situations.
Buoyant Force
Buoyancy is the force that allows objects to float or rise in a fluid. The buoyant force is an upward force by the fluid that opposes the weight of an immersed object. It's described by Archimedes' Principle which states that the upward buoyant force is equal to the weight of the fluid displaced by the object.
In this exercise, buoyancy plays a crucial role in determining how the forces balance when the rock is fully immersed in water. To find the buoyant force, one calculates the difference between the weight of the rock and the tension in the cord while the elevator is at rest. The formula \[ F_b = \rho V g \]shows that the buoyant force \( F_b \) depends on the fluid's density \( \rho \), the volume of the object \( V \), and the gravitational acceleration \( g \). Understanding buoyant force helps in accurately determining the tension in situations of equilibrium.
Elevator Acceleration
Elevators change the apparent weight of objects due to acceleration. When the elevator accelerates, it feels like there's a change in gravity even though your actual weight remains constant.
The apparent increase or decrease in force affects the tension in any cords or cables attached to objects in the elevator. Consider:
  • When accelerating upward, the apparent weight of the object increases, making tension calculations like \( T = mg - F_b + ma \).
  • When accelerating downward, the apparent weight decreases, so the calculation becomes \( T = mg - F_b - ma \).
By examining these variations, one can see how the concept of acceleration directly influences the perceived forces acting on an object, a core part of analyzing such physics problems.
Free Fall
Free fall occurs when an object moves only under the influence of gravity, essentially without any other forces acting on it. In physics, this is often idealized, indicating that no friction or air resistance affects the object. In free fall, everything accelerates at \( 9.81 \, \text{m/s}^2 \), the standard gravitational acceleration.
For the rock in the elevator scenario, if the elevator were in free fall, it would mean all forces counteracting gravity, like tension, are removed. Thus, the tension would be effectively zero because no force is maintaining it against gravity. Hence, the rock floats freely and experiences no tension against its weight. During free fall, an object's effective weight becomes zero, known as weightlessness, even though its mass remains unchanged. Understanding free fall helps clarify how accelerative forces translate to different force equations, adding depth to the study of motion in physics.

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Most popular questions from this chapter

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