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A golf course sprinkler system discharges water from a horizontal pipe at the rate of 7200 \(\mathrm{cm}^{3} / \mathrm{s}\) . At one point in the pipe, where the radius is 4.00 \(\mathrm{cm}\) , the water's absolute pressure is \(2.40 \times 10^{5} \mathrm{Pa}\) . At a second point in the pipe, the water passes through a constriction where the radius is \(2.00 \mathrm{cm} .\) What is the water's absolute pressure as it flows through this constriction?

Short Answer

Expert verified
The water's absolute pressure in the constriction is 225001 Pa.

Step by step solution

01

Calculate Initial Area and Speed

First, calculate the cross-sectional area of the pipe at the wider section where the radius is 4.00 cm. The area, \( A_1 \), is calculated using \( \pi r^2 \):\[A_1 = \pi (0.04 \, \text{m})^2 = 0.005026 \, \text{m}^2\]Next, calculate the speed of the water, \( v_1 \), at this section using the flow rate, \( Q = 7200 \, \text{cm}^3/\text{s} \), converting to \( \text{m}^3/\text{s} \):\[Q = 7200 \, \text{cm}^3/\text{s} = 0.0072 \, \text{m}^3/\text{s}\]\[v_1 = \frac{Q}{A_1} = \frac{0.0072}{0.005026} = 1.432 \, \text{m/s}\]
02

Calculate Area and Speed at Constricted Section

Calculate the area at the constricted section where the radius is 2.00 cm. The area, \( A_2 \), is:\[A_2 = \pi (0.02 \, \text{m})^2 = 0.001257 \, \text{m}^2\]Using the principle of continuity, \( A_1 v_1 = A_2 v_2 \), solve for \( v_2 \):\[v_2 = \frac{A_1 v_1}{A_2} = \frac{0.005026 \times 1.432}{0.001257} = 5.73 \, \text{m/s}\]
03

Apply Bernoulli's Equation

Use Bernoulli’s equation to relate the pressures and speeds at the two points:\[P_1 + \frac{1}{2} \rho v_1^2 = P_2 + \frac{1}{2} \rho v_2^2\]Assuming the density of water, \( \rho = 1000 \, \text{kg}/\text{m}^3 \), plug in the known values:\[2.40 \times 10^{5} + \frac{1}{2} \times 1000 \times (1.432)^2 = P_2 + \frac{1}{2} \times 1000 \times (5.73)^2\]Simplify and solve for \( P_2 \):\[2.40 \times 10^{5} + 1023.76 = P_2 + 16422.45\]\[P_2 = 2.40 \times 10^{5} + 1023.76 - 16422.45 = 224601.31 \, \text{Pa}\]
04

Conclude the Results

The water's absolute pressure as it flows through the constriction is:\[P_2 = 2.25 \times 10^{5} \, \text{Pa}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Dynamics
Fluid dynamics is a fascinating area of physics that studies the movement of fluids like liquids and gases. In this case, we're examining the flow of water through a sprinkler system. Understanding how fluids behave in motion helps us solve practical problems such as calculating water pressure in pipes. Fluid motion is influenced by factors like viscosity, density, and flow rate. In our sprinkler problem, the key elements include knowing how water moves through pipes of different diameters and the effect of speed on pressure. By analyzing these factors, we can determine changes in pressure as the water moves through a system, using laws and equations derived from fluid dynamics.
Continuity Equation
The Continuity Equation is crucial in fluid dynamics. It highlights the relationship between fluid speed and cross-sectional area in a pipe, stating that the product of the cross-sectional area and fluid velocity remains constant as long as the fluid is incompressible. Formulaically, it is represented as:
  • \[ A_1 v_1 = A_2 v_2 \]
In simpler terms, when a fluid flows from a wide part of a pipe to a narrow one, the speed increases. The initial section, with radius 4.00 cm and speed 1.432 m/s, compared to the constricted section with radius 2.00 cm, illustrates this perfectly. Since less space is available in the narrower section (area \(A_2\)), the fluid speeds up. This principle ensures that no fluid is lost and helps in calculating the changes in speed as areas change.
Bernoulli's Principle
Bernoulli’s Principle is another cornerstone of fluid dynamics. It explains how the speed of a fluid affects its pressure. The principle suggests that an increase in speed results in a decrease in pressure and vice versa. The mathematical form of Bernoulli's equation is:
  • \[ P_1 + \frac{1}{2} \rho v_1^2 = P_2 + \frac{1}{2} \rho v_2^2 \]
In the problem, water travels from a section with larger radius and lower velocity to one with a smaller radius and higher velocity. According to Bernoulli’s Principle, the pressure must drop in the narrower section due to the distinctly higher speed. This principle is crucial for understanding how systems like airplane wings and, in this case, sprinklers manage pressure differences.
Pressure Calculation
Calculating pressure in a fluid system is essential for ensuring its designed performance. The exercise involves determining the pressure in a pipe where water passes through a narrowing. Pressure changes depend on fluid velocity and pipe dimensions. With initial pressure known (\( P_1 = 2.40 \times 10^5 \text{ Pa} \)) and applying Bernoulli’s Principle, we observe how velocity fluctuations affect pressure. We solved for \( P_2 \) by managing kinetic energy changes within the flowing fluid using:
  • \[ P_2 = 2.40 \times 10^5 + 1023.76 - 16422.45 = 2.25 \times 10^5 \, \text{Pa} \]
This shows how a constriction influences pressure distribution in fluid systems. Each calculation maintains system balance, ensuring safe and efficient operation of hydraulic systems, sprayers, and more.

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