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You want to construct a pendulum with a period of 4.00 \(\mathrm{s}\) at a location where \(g=\) 9.80 \(\mathrm{m} / \mathrm{s}^{2} .\) (a) What is the length of a simple pendulum having this period? (b) Suppose the pendulum must be mounted in a case that is not more than 0.50 \(\mathrm{m}\) high. Can you devise a pendulum having a period of 4.00 s that will satisfy this requirement?

Short Answer

Expert verified
(a) Length is 1.62 m. (b) No, it doesn't fit the height constraint.

Step by step solution

01

Understand the Formula for Pendulum Period

The period of a simple pendulum is given by the formula \( T = 2\pi \sqrt{\frac{L}{g}} \), where \( T \) is the period, \( L \) is the length of the pendulum, and \( g \) is the acceleration due to gravity. We know \( T = 4.00 \) s and \( g = 9.80 \) m/s². Our goal is to find the length \( L \).
02

Solve for the Length of the Pendulum

Start by rearranging the formula to solve for \( L \): \[ L = \frac{gT^2}{4\pi^2} \]Substitute \( T = 4.00 \) s and \( g = 9.80 \) m/s² into the formula:\[ L = \frac{9.80\text{ m/s}^2 \times (4.00\text{ s})^2}{4\pi^2} \]
03

Perform Calculations

Calculate \( L \) using the numerical values:1. Calculate \( 4.00^2 = 16.00 \).2. Compute \( 4\pi^2 = 39.478 \) (approximately).3. Compute \( L = \frac{9.80 \times 16.00}{39.478} \).4. Thus, \( L \approx 1.62 \) m.
04

Evaluate Height Constraint

Check if the calculated pendulum length ( \( L = 1.62 \) m) meets the height requirement of not more than 0.50 m. Since 1.62 m is greater than 0.50 m, it does not satisfy the height constraint.
05

Conclusion and Alternative Design

Since an ordinary simple pendulum of 1.62 m does not fit within the 0.50 m height, consider alternatives like a compact mechanical pendulum or altering the shape to fit within constraints. Simple pendulum traditional design can't meet height constraint with given period.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simple Pendulum
A simple pendulum is a fundamental concept that helps us understand periodic motion. It consists of a mass, called a "bob," which is suspended from a fixed point by a string or rod of length \( L \). This pendulum swings back and forth under the influence of gravity. Importantly, if the arc of the swing is small, we call it a "simple" pendulum. This assumption simplifies the analysis because it allows the use of the formula for the period of a simple pendulum:\[ T = 2\pi \sqrt{\frac{L}{g}} \]- **Period \( (T) \)**: It's the time taken for one complete cycle of the pendulum swing.- **Length \( (L) \)**: The distance from the fixed point to the center of the pendulum bob.- **Gravitational acceleration \( (g) \)**: The acceleration due to gravity, typically 9.80 m/s² on Earth.For a simple pendulum, the period depends only on \( L \) and \( g \), not on the mass of the bob or the amplitude of the swing, which is why this model is so useful in theoretical physics. Simple pendulums are commonly used in clocks and other timing devices.
Gravitational Acceleration
Gravitational acceleration, represented by \( g \), is a crucial factor in determining the motion of a pendulum. On the surface of Earth, \( g \) is approximately 9.80 m/s². This value can vary depending on location due to Earth's slightly oblate shape and varying density, but for many calculations, this is the standard assumption.- **Effect of Gravity on Pendulum**: The force of gravity is what keeps the pendulum moving. It's the gravitational pull on the bob that makes it accelerate as it swings down and decelerate as it climbs back up. This force results in the rhythmic, back-and-forth motion characteristic of pendulums.- **Role in Period Calculation**: In the equation for the simple pendulum's period, \( g \) appears in the denominator under the square root. This means that as gravity increases, the period decreases (the pendulum swings faster), and as gravity decreases, the period increases (the pendulum swings slower).Having a precise understanding of gravitational acceleration is essential for creating accurate pendulum models, especially in different locations or for precise scientific work.
Pendulum Design Constraints
When designing a pendulum for practical applications, constraints such as space and size can impact the feasibility of a simple pendulum's design. In the problem above, we have a requirement for the pendulum to fit in a case not taller than 0.50 m. This introduces a significant challenge since the straightforward calculation gives us a pendulum length \( L \) of approximately 1.62 m for a 4.00-second period.- **Space Limitation Challenges**: The traditional design of a simple pendulum does not fit into smaller spaces when specific periods are required, showing limitations when trying to fit a pendulum within a pre-defined size constraint.- **Alternative Designs**: To meet these constraints, alternative solutions like a mechanical or compound pendulum might be considered. This could mean using multiple bobs or altering the geometry of the pendulum to achieve the same period in a compact form.- **Modifying Parameters**: Adjusting variables within the design, such as bob weight distribution or suspension technique, can also help fit into spatial constraints without sacrificing performance.Ultimately, understanding these design constraints encourages innovation in pendulum design, blending physics principles with practical engineering solutions for real-world applications.

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Most popular questions from this chapter

A 5.00 kg partridge is suspended from a pear tree by an ideal spring of negligible mass. When the partridge is pulled down 0.100 \(\mathrm{m}\) below its equilibrium position and released, it vibrates with a period of 4.20 \(\mathrm{s}\) . (a) What is its speed as it passes through the equilibrium position? (b) What is its acceleration when it is 0.050 \(\mathrm{m}\) above the equilibrium position? (c) When it is moving upward, how much time is required for it to move from a point 0.050 \(\mathrm{m}\) below its equilibrium position to a point 0.050 \(\mathrm{m}\) above it? (d) The motion of the partridge is stopped, and then it is removed from the spring. How much does the spring shorten?

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Show that the expression for the period of a physical penduhm reduces to that of a simple pendulum if the physical pendulum consists of a particle with mass \(m\) on the end of a massless string of length \(L .\)

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