/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 A uniform, solid metal disk of m... [FREE SOLUTION] | 91Ó°ÊÓ

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A uniform, solid metal disk of mass 6.50 \(\mathrm{kg}\) and diameter 24.0 \(\mathrm{cm}\) hangs in a horizontal plane, supported at its center by a vertical metal wire. You find that it requires a horizontal force of 4.23 \(\mathrm{N}\) tangent to the rim of the disk to turn it by \(3.34^{\circ},\) thus twisting the wire. You now remove this force and release the disk from rest. (a) What is the torsion constant for the metal wire? (b) What are the frequency and period of the torsional oscillations of the disk? (c) Write the equation of motion for \(\theta(t)\) for the disk.

Short Answer

Expert verified
(a) \(\kappa \approx 8.70 \, \text{Nm/rad}\); (b) \(f \approx 2.16 \, \text{Hz}, T \approx 0.463 \, \text{s}\); (c) \(\theta(t) = 0.0583 \cos(13.58t)\).

Step by step solution

01

Convert given angle from degrees to radians

First, we need to convert the given angle \(3.34^{\circ}\) to radians because the torsion in physics typically uses radians. To do this, use the formula: \( \text{Radians} = \text{Degrees} \times \frac{\pi}{180}\)So we have:\(3.34^{\circ} \times \frac{\pi}{180} = 0.0583 \, \text{radians}\)
02

Calculate the Torsion Constant

The torsion constant \(\kappa\) can be determined using the formula:\[\tau = \kappa \cdot \theta\]where \(\tau\) is the torque and can be calculated as \(\tau = F \cdot r\).Here, \(F = 4.23 \, \text{N}\) and the radius \(r = \frac{24.0 \, \text{cm}}{2} = 0.12 \, \text{m}\).So, \(\tau = 4.23 \, \text{N} \times 0.12 \, \text{m} = 0.5076 \, \text{Nm}\).Now, solve for \(\kappa\):\(\kappa = \frac{\tau}{\theta} = \frac{0.5076 \, \text{Nm}}{0.0583 \, \text{radians}} \approx 8.70 \, \text{Nm/rad}\).
03

Calculate Moment of Inertia

The moment of inertia \(I\) for a solid disk is calculated by the formula:\[I = \frac{1}{2} M r^2\]where \(M = 6.50 \, \text{kg}\) and \(r = 0.12 \, \text{m}\).Thus,\[I = \frac{1}{2} \times 6.50 \, \text{kg} \times (0.12 \, \text{m})^2 = 0.0468 \, \text{kg} \cdot \text{m}^2\]
04

Calculate Frequency

The frequency \(f\) of the oscillations is found using the formula:\[f = \frac{1}{2\pi} \sqrt{\frac{\kappa}{I}}\]Substitute \(\kappa = 8.70 \, \text{Nm/rad}\) and \(I = 0.0468 \, \text{kg} \cdot \text{m}^2\):\[f = \frac{1}{2\pi} \sqrt{\frac{8.70}{0.0468}} \approx 2.16 \, \text{Hz}\]
05

Calculate Period

The period \(T\) is the inverse of frequency:\[T = \frac{1}{f} = \frac{1}{2.16 \, \text{Hz}} \approx 0.463 \, \text{s}\]
06

Write Equation of Motion

The equation of motion for torsional oscillation is given by:\[\theta(t) = \theta_0 \cos(\omega t + \phi)\]where \(\omega = 2\pi f = 2\pi \times 2.16 \approx 13.58 \, \text{rad/s}\).Assuming it starts from rest, then \(\phi = 0\). If we suspect initial displacement is equal to the force-induced turn, \(\theta_0 = 0.0583 \, \text{radians}\), thus:\[\theta(t) = 0.0583 \cos(13.58 t)\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Torsion Constant
The torsion constant, often denoted as \(\kappa\), is a fundamental property of a wire or rod involved in torsional oscillations. It measures how resistant the wire is to being twisted. In simple terms, it tells us the torque needed to twist the wire by a specific angle. This constant is crucial for understanding the stiffness of the wire when a force is applied tangentially.
The formula that relates torque and torsion constant is given by:
  • \(\tau = \kappa \cdot \theta\)
where \(\tau\) is the torque (in Nm) and \(\theta\) is the angular displacement in radians.
To find \(\kappa\), you can rearrange the equation:
  • \(\kappa = \frac{\tau}{\theta}\)
In this exercise, with a torque of \(0.5076 \, \text{Nm}\) and an angular displacement of \(0.0583 \, \text{radians}\), the torsion constant calculates to approximately \(8.70 \, \text{Nm/rad}\). This tells us the wire is relatively stiff, requiring substantial torque for a small angular twist.
Moment of Inertia
The concept of moment of inertia, symbolized as \(I\), plays a vital role in torsional and rotational motion. It provides a measure of how much resistance an object exhibits to changes in its rotational motion. It's akin to mass in linear motion but applies to rotation.
For a solid disk, the moment of inertia can be computed using the formula:
  • \(I = \frac{1}{2} M r^2\)
where \(M\) is the mass of the disk, and \(r\) is the radius. In our scenario:
  • Mass, \(M = 6.50 \, \text{kg}\)
  • Radius, \(r = 0.12 \, \text{m}\)
  • Thus, \(I = \frac{1}{2} \times 6.50 \times (0.12)^2 = 0.0468 \, \text{kg} \cdot \text{m}^2\)
This moment of inertia is essential for predicting how the disk responds to applied torques and relates directly to the subsequent frequency of oscillations.
Frequency and Period of Oscillations
In oscillatory systems, specifically torsional oscillations, understanding frequency and period is key. The frequency \(f\) indicates how many cycles of oscillation occur per second and is given in hertz (Hz). Meanwhile, the period \(T\) is the time taken for one complete cycle of oscillation.
Frequency is calculated using the equation:
  • \(f = \frac{1}{2\pi} \sqrt{\frac{\kappa}{I}}\)
where \(\kappa\) is the torsion constant and \(I\) the moment of inertia. For our disk:
  • \(f \approx 2.16 \, \text{Hz}\)
On the other hand, the period \(T\) is simply the reciprocal of frequency:
  • \(T = \frac{1}{f} \approx 0.463 \, \text{s}\)
These values illustrate how quickly the disk vibrates back and forth around its horizontal resting position.
Equation of Motion
The equation of motion for torsional oscillation describes how the angular position \(\theta(t)\) of the disk changes over time. It tells us the behavior of the oscillating system.
This equation typically takes the form:
  • \(\theta(t) = \theta_0 \cos(\omega t + \phi)\)
where \(\theta_0\) is the initial angular displacement, \(\omega = 2\pi f\) is the angular frequency, and \(\phi\) represents the phase angle. Assuming the disk starts from rest:
  • Phase angle \(\phi = 0\)
  • Initial displacement \(\theta_0 = 0.0583 \, \text{radians}\)
Given our frequency calculation, \(\omega \approx 13.58 \, \text{rad/s}\), leading to:
  • \(\theta(t) = 0.0583 \cos(13.58 t)\)
This equation encapsulates the dynamics of the disk's motion, oscillating harmonically about its equilibrium position.

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