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Jerk. A guitar string vibrates at a frequency of 440 \(\mathrm{Hz}\) . A point at its center moves in SHM with an amplitude of 3.0 \(\mathrm{mm}\) and a phase angle of zero. (a) Write an equation for the position of the center of the string as a function of time. (b) What are the maximum values of the magnitudes of the velocity and acceleration of the center of the string? (c) The derivative of the acceleration with respect to time is a quantity called the jerk. Write an equation for the jerk of the center of the string as a function of time, and find the maximum value of the magnitude of the jerk.

Short Answer

Expert verified
(a) \( x(t) = 3.0 \cos(880\pi t) \); (b) max velocity is \( 2640\pi \ mm/s \), max acceleration is \( 2640^2\pi^2 \ mm/s^2 \); (c) max jerk is \( 2640^3\pi^3 \ mm/s^3 \).

Step by step solution

01

Write the equation for the position function

The position of an object in simple harmonic motion (SHM) can be described by the equation \( x(t) = A \cos(\omega t + \phi) \), where \( A \) is the amplitude, \( \omega \) is the angular frequency, and \( \phi \) is the phase angle. Given that the amplitude \( A = 3.0 \ \mathrm{mm} \), phase angle \( \phi = 0 \), and frequency \( f = 440 \ \mathrm{Hz} \), we calculate the angular frequency as \( \omega = 2\pi f = 2\pi \times 440 \). Thus, the equation becomes \( x(t) = 3.0 \cos(880\pi t) \).
02

Find maximum velocity

Velocity is the derivative of position with respect to time. So, we differentiate \( x(t) = 3.0 \cos(880\pi t) \) with respect to \( t \), which gives \( v(t) = -3.0 \times 880\pi \sin(880\pi t) \). The maximum velocity occurs when \( \sin(880\pi t) = \pm 1 \), so the maximum velocity magnitude is \( |v_{\text{max}}| = 3.0 \times 880\pi \).
03

Find maximum acceleration

Acceleration is the derivative of velocity with respect to time. Differentiate \( v(t) = -3.0 \times 880\pi \sin(880\pi t) \) with respect to \( t \), which gives \( a(t) = -3.0 \times (880\pi)^2 \cos(880\pi t) \). The maximum acceleration occurs when \( \cos(880\pi t) = \pm 1 \), so the maximum acceleration magnitude is \( |a_{\text{max}}| = 3.0 \times (880\pi)^2 \).
04

Write the equation for jerk and find maximum jerk

Jerk is the derivative of acceleration with respect to time. Differentiate \( a(t) = -3.0 \times (880\pi)^2 \cos(880\pi t) \) with respect to \( t \), which gives \( j(t) = 3.0 \times (880\pi)^3 \sin(880\pi t) \). The maximum jerk occurs when \( \sin(880\pi t) = \pm 1 \), so the maximum jerk magnitude is \( |j_{\text{max}}| = 3.0 \times (880\pi)^3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

angular frequency
Angular frequency is a crucial concept in the study of simple harmonic motion (SHM). It helps us understand how quickly an object oscillates back and forth. The angular frequency, denoted by the symbol \( \omega \), is expressed in radians per second.

To find the angular frequency, we use the formula \( \omega = 2\pi f \), where \( f \) is the frequency of oscillation in Hertz. In the case of the vibrating guitar string in the exercise, the frequency is given as 440 Hz.
  • Calculate \( \omega \) by plugging in the frequency: \( \omega = 2\pi \times 440 \).
  • This results in an angular frequency of \( 880\pi \) radians per second.
Understanding angular frequency is key because it allows us to write the position equation for SHM as \( x(t) = A \cos(\omega t + \phi) \), where the motion is described by how \( \omega \) influences the rate of oscillation.
velocity in SHM
In simple harmonic motion, velocity refers to how fast an object is moving through its cycle. This helps describe how rapidly the object's position is changing over time. We find the velocity by taking the derivative of the position function concerning time.

For the guitar string, the position function is \( x(t) = 3.0 \cos(880\pi t) \). To find the velocity, we differentiate this with respect to \( t \), yielding:
  • \( v(t) = -3.0 \times 880\pi \sin(880\pi t) \)
Since velocity varies sinusoidally, its maximum magnitude occurs when \( \sin(880\pi t) = \pm 1 \).
  • This gives the maximum velocity as \(|v_{\text{max}}| = 3.0 \times 880\pi \).
Velocities in SHM are not constant; they vary over time, showing the dynamic nature of harmonic motion.
acceleration in SHM
Acceleration in SHM measures how quickly the object's velocity changes. It gives insight into the forces at play within the system.

To find acceleration, differentiate the velocity function concerning time. Given:
  • Velocity function: \( v(t) = -3.0 \times 880\pi \sin(880\pi t) \), differentiate to obtain:
  • \( a(t) = -3.0 \times (880\pi)^2 \cos(880\pi t) \)
Acceleration reaches its maximum when \( \cos(880\pi t) = \pm 1 \).
  • This results in a maximum acceleration magnitude of \( |a_{\text{max}}| = 3.0 \times (880\pi)^2 \).
The fluctuating nature of acceleration in SHM is key to understanding the periodic and restoring forces sustaining harmonic motion.
jerk in physics
Jerk, rarely spoken of, plays an integral role in describing complex motion events in physics. Jerk is the rate of change of acceleration.

To find jerk, differentiate the acceleration function with respect to time. From the previous steps:
  • Acceleration function: \( a(t) = -3.0 \times (880\pi)^2 \cos(880\pi t) \), differentiate to get:
  • \( j(t) = 3.0 \times (880\pi)^3 \sin(880\pi t) \)
Jerk reaches its maximum when \( \sin(880\pi t) = \pm 1 \).
  • This gives a maximum jerk magnitude of \( |j_{\text{max}}| = 3.0 \times (880\pi)^3 \).
Comprehending jerk helps engineers and physicists understand the smoothness and comfort of mechanisms involving acceleration changes, such as cars or amusement rides.

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