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What is the escape speed from a \(300-\mathrm{km}\) -diameter asteroid with a density of 2500 \(\mathrm{kg} / \mathrm{m}^{3}\) ?

Short Answer

Expert verified
The escape speed from the asteroid is approximately 58.1 m/s.

Step by step solution

01

Understanding Escape Speed

Escape speed or escape velocity is the speed that an object must reach to break free from a planet or body's gravitational influence. The formula to find escape speed is given by \[ v_{e} = \sqrt{\frac{2GM}{r}} \] where: - \( v_{e} \) is the escape speed, - \( G \) is the universal gravitational constant \(6.674 \times 10^{-11} \, \mathrm{m}^{3}\, \mathrm{kg}^{-1} \, \mathrm{s}^{-2}\), - \( M \) is the mass of the body, - \( r \) is the radius of the body.
02

Calculate the Radius

The problem gives the diameter of the asteroid as \(300\, \mathrm{km}\). Since radius \( r \) is half of the diameter, convert the diameter to meters and divide by 2 to find the radius.Diameter = 300 km = 300,000 m. Therefore, \[ r = \frac{300,000}{2} = 150,000 \, \mathrm{m} \]
03

Calculate the Mass

Since the density \( \rho \) of the asteroid is given as \(2500 \, \mathrm{kg/m}^{3}\), we can use this to calculate the mass \( M \) of the asteroid using the volume of a sphere. The volume \( V \) of a sphere formula is \[ V = \frac{4}{3}\pi r^{3} \].First, calculate the volume:\[ V = \frac{4}{3}\pi (150,000)^3 \]. Then, use density \( \rho \) to find mass \( M \):\[ M = \rho \times V = 2500 \times V \].
04

Applying Mass to Escape Speed Formula

After calculating the mass, substitute this and the previously calculated radius into the escape speed formula: \[ v_{e} = \sqrt{\frac{2GM}{r}} \].Insert the values for \( G \), \( M \), and \( r \) to find \( v_{e} \).
05

Final Calculation

Solve the equation \[ v_{e} = \sqrt{\frac{2 \times 6.674 \times 10^{-11} \times M}{150,000}} \].First, calculate \( M \) using the volume and density formula, then substitute \( M \) into the equation above to find the numerical value for \( v_{e} \). Ensure all units are consistent and calculate to find approximately \( v_{e} = 58.1 \, \mathrm{m/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Constant
The gravitational constant, denoted as "G," is a fundamental constant in physics that plays a key role in the calculation of gravitational forces and escape velocities. Its value is approximately 6.674 × 10^{-11} m^{3} kg^{-1} s^{-2}. This constant helps determine the force of gravitational attraction between two masses separated by a certain distance.
A simple way to think about it is that "G" helps us quantify how strong the gravitational pull is in the universe. It acts as a proportionality factor in Newton's law of universal gravitation and is crucial in calculating escape speed, which is the speed needed for an object to leave a body's gravitational pull without any propulsion.
When dealing with escape velocity calculations, like those involving asteroids or planets, the gravitational constant becomes significant because it allows us to factor in the effect of mass and distance on gravity's grip. It ensures that calculations accurately reflect how mass and distance influence the speed necessary to overcome gravitational forces.
Mass Calculation
Mass calculation involves determining the total amount of matter contained within an object. In the context of escape speed, it is crucial because the mass of the celestial body directly affects the velocity required to escape its gravitational field.
To calculate the mass of an asteroid or similar spherical body, you need to know its volume and density. The density is typically given, as in the example of the asteroid with a density of 2500 kg/m^{3}. The volume is found using the formula for the volume of a sphere, which we'll cover next.
Once you calculate the volume using the asteroid's radius, you can find the mass (M) using the formula:
  • M = \( \rho \times V \), where \( \rho \) is the density and \( V \) is the volume.
After finding the volume, multiplying it by the given density will yield the asteroid's mass. This value is then used in subsequent calculations to find the escape velocity.
Volume of a Sphere
Understanding the volume of a sphere is essential for many physics calculations, such as determining the mass of an object like an asteroid. The formula to find the volume (V) of a sphere is:
  • \( V = \frac{4}{3}\pi r^{3} \)
This formula tells us that to find the volume, you must know the radius of the sphere. Remember, the radius is half of the diameter. For our asteroid, with a diameter of 300 km, we convert it to meters (300,000 m) and divide by two, giving a radius (r) of 150,000 m.
Once you have "r", substitute it into the formula to calculate the volume. The calculated volume is then used to determine the mass when multiplied by the density. This step is vital because understanding the object's volume provides necessary details about its structure and allows for precise mass calculation, impacting escape velocity computations.
Density of an Asteroid
Density provides the relationship between mass and volume of an object. It represents how much mass is contained within a specific volume and is expressed in kilograms per cubic meter (kg/m^{3}).
Density is significant when calculating the mass of an astronomical object like an asteroid, especially when its physical characteristics (like volume) are known. In our example, the asteroid's density is given as 2500 kg/m^{3}. By calculating the volume and knowing the density, we can find the mass using the simple relation:
  • \( M = \rho \times V \)
By multiplying the density by the volume, we arrive at the asteroid's total mass. This value is crucial for determining the escape speed, as it influences how strongly the asteroid's gravity pulls on objects nearby. Understanding these basic concepts allows you to appreciate how density impacts gravitational forces and the calculations of corresponding escape speeds.

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Most popular questions from this chapter

Exploring Europa. There is strong evidence that Europa, a satellite of Jupiter, has a liquid ocean beneath its icy surface. Many scientists think we should land a vehicle there to search for life. Before launching it, we would want to test such a lander under the gravity conditions at the surface of Europa. One way to do this is to put the lander at the end of a rotating arm in an orbiting earth satellite. If the arm is \(4.25 \mathrm{~m}\) long and pivots about one end, at what angular speed (in rpm) should it spin so that the acceleration of the lander is the same as the acceleration due to gravity at the surface of Europa? The mass of Europa is \(4.8 \times 10^{22} \mathrm{~kg}\) and its diameter is \(3138 \mathrm{~km}\).

Your starship, the Aimless Wanderer, lands on the mysteri- ous planet Mongo. As chief scientist-engineer, you make the following measurements: A \(2.50-\mathrm{kg}\) stone thrown upward from the ground at 12.0 \(\mathrm{m} / \mathrm{s}\) returns to the ground in \(8.00 \mathrm{s} ;\) the circumference of Mongo at the equator is \(2.00 \times 10^{5} \mathrm{km}\) ; and there is no appreciable atmosphere on Mongo. The starship commander, Captain Confusion, asks for the following information: (a) What is the mass of Mongo? (b) If the Aimless Wanderer goes into a circular orbit \(30,000 \mathrm{km}\) above the surface of Mongo, how many hours will it take the ship to complete one orbit?

Titania, the largest moon of the planet Uranus, has \(\frac{1}{8}\) the radius of the earth and \(\frac{1}{100}\) the mass of the earth. (a) What is the acceleration due to gravity at the surface of Titania? (b) What is the average density of Titania? (This is less than the density of rock, which is one piece of evidence that Titania is made primarily of ice. \()\)

Deimos, a moon of Mars, is about 12 \(\mathrm{km}\) in diameter with mass \(2.0 \times 10^{15} \mathrm{kg}\) . Suppose you are stranded alone on Deimos and want to play a one-person game of baseball. You would be the pitcher, and you would be the batter! (a) With what speed would you have to throw a baseball so that it would go into a circular orbit just above the surface and return to you so you could hit it? Do you think you could actually throw it at this speed? (b) How long (in hours) after throwing the ball should you be ready to hit it? Would this be an action-packed bascball game?

A uniform, solid, \(1000.0-\mathrm{kg}\) sphere has a radius of 5.00 \(\mathrm{m}\) . (a) Find the gravitational force this sphere exerts on a \(2.00-\mathrm{kg}\) point mass placed at the following distances from the center of the sphere: ( i) \(5.01 \mathrm{m},\) and (ii) 2.50 \(\mathrm{m} .\) (b) Sketch a qualitative graph of the magnitude of the gravitational force this sphere exerts on a point mass \(m\) as a function of the distance \(r\) of \(m\) from the center of the sppere. Include the region from \(r=0\) to \(r \rightarrow \infty .\)

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