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A stiff uniform wire of mass \(M_{0}\) and length \(L_{0}\) is cut, bent, and the parts soldered together so that it forms a circular wheel having four identical spokes coming out from the center. None of the wire is wasted, and you can neglect the mass of the solder. (a) What is the moment of inertia of this wheel about an axle through its center perpendicular to the plane of the wheel? (b) If the wheel is given an initial spin with angular velocity \(\omega_{0}\) and stops uniformly in time \(T\) , what is the frictional torque at its axle?

Short Answer

Expert verified
The moment of inertia is computed by adding the inertia of the circle and spokes, and frictional torque is obtained using angular deceleration.

Step by step solution

01

Understand the Problem

We have a wire of mass \( M_0 \) and length \( L_0 \) reshaped into a circular wheel with four identical spokes. We need to find the moment of inertia about its center and the frictional torque if it stops uniformly in time \( T \).
02

Determine Lengths Used

The total length of wire \( L_0 \) is divided into the circumference of the circle and the four identical spokes. Let \( r \) be the radius of the circle. Then the circumference is \( 2\pi r \) and the length used for spokes is \( 4r \), thus, \( L_0 = 2\pi r + 4r \).
03

Solve for Radius

From the equation \( L_0 = 2\pi r + 4r \), solve for \( r \):\[ r = \frac{L_0}{2\pi + 4} \]
04

Calculate Mass Distribution

Assume the wire's mass is evenly distributed. Let \( m_s \) be the mass of the spokes and \( m_c \) the mass of the circle:\[ \frac{m_s}{4r} = \frac{m_c}{2\pi r} \rightarrow m_s = \frac{4r \times M_0}{L_0}, \, m_c = \frac{2\pi r \times M_0}{L_0} \]
05

Moment of Inertia of Spokes

For a spoke (treated as a rod rotating about one end): The moment of inertia is \( I_{s} = \frac{1}{3}m_s r^2 \) for each spoke, so total spoke inertia is \( I_{spokes} = 4 \cdot \frac{1}{3}m_s r^2 \).
06

Moment of Inertia of the Circle

The circular part's moment of inertia is \( I_{circle} = m_{c} r^2 \).
07

Total Moment of Inertia

Add the two inertias: \( I_{total} = I_{spokes} + I_{circle} = 4 \times \frac{1}{3}m_s r^2 + m_c r^2 \). Replace \( m_s \) and \( m_c \) with expressions from Step 4.
08

Calculate Frictional Torque

Use the angular deceleration formula \( \tau = I \cdot \alpha \), where \( \alpha = -\frac{\omega_0}{T} \). With \( \tau = I_{total} \cdot \left( -\frac{\omega_0}{T} \right) \), calculate \( \tau \).
09

Simplifying and Finishing Calculation

Substitute values into the torque equation to find final numerical results.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is a measure of how quickly an object rotates or spins around its axis. It is denoted by the Greek letter omega (\(\omega\)). Angular velocity is often given in units like radians per second (rad/s). This concept is crucial when analyzing rotational dynamics, such as the spinning wheel in our exercise.
For the wheel, the angular velocity (\(\omega_0\)) is the speed at which the wheel is initially spinning. Understanding angular velocity helps in determining how the wheel's motion changes over time, especially if there's friction slowing it down.
Angular velocity is closely related to linear velocity through the equation:
  • \(v = r\omega\)
where \(v\) is the linear velocity and \(r\) is the radius of the circular path.
This relationship emphasizes that a point farther from the center moves faster linearly even if the angular velocity is constant.
Frictional Torque
Torque is the rotational equivalent of force. It causes objects to rotate around an axis and is fundamentally important in analyzing rotational motion. Frictional torque specifically refers to the torque that opposes rotation, often due to frictional forces at the axle or bearings.
In the example of the circular wheel, the wheel comes to a stop due to frictional torque. The initial angular velocity \(\omega_0\) decreases to zero over the time period \(T\).
To find frictional torque \(\tau\), we utilize the equation that connects angular deceleration (\(\alpha\)) with torque and moment of inertia (\(I\)):
  • \(\tau = I \cdot \alpha \)
This equation is crucial as it allows us to compute the frictional torque by understanding how angular velocity changes with time. The angular deceleration \(\alpha\) is given by:
  • \(\alpha = -\frac{\omega_0}{T} \)
Negative sign denotes decreasing velocity. Inserting the computed \(\alpha\) into the torque equation provides a complete picture of the rotational dynamics involved.
Rotational Dynamics
Rotational dynamics is the study of the motion of rotating objects, focusing on the forces and torques that cause this motion. It extends the concepts of linear dynamics into a rotational context. Just like in linear motion, where forces create accelerations, in rotational motion, torques create angular accelerations.
Key quantities in rotational dynamics include moment of inertia and angular momentum. The moment of inertia refers to the "rotational mass" of an object, dictating its resistance to changes in rotational motion.
For a wheel made from shaped wire, each part contributes to the moment of inertia. The rim and spokes each have their own formula to calculate inertia:
  • Spokes: \(I_{spokes} = 4 \times \frac{1}{3}m_s r^2\)
  • Rim: \(I_{circle} = m_{c} r^2\)
These are combined to find the total moment of inertia. This total inertia directly influences how the wheel spins and stops, demonstrating the practical application of rotational dynamics in engineering and everyday phenomena. Understanding these principles helps in predicting the behavior of rotating systems, ranging from simple wheels to complex machinery.

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Most popular questions from this chapter

A target in a shooting gallery consists of a vertical square wooden board, 0.250 \(\mathrm{m}\) on a side and with mass 0.750 \(\mathrm{kg}\) , that pivots on a horizontal axis along its top edge. The board is struck face-on at its center by a bullet with mass 1.90 \(\mathrm{g}\) that is traveling at 360 \(\mathrm{m} / \mathrm{s}\) and that remains embedded in the board. (a) What is the angular speed of the board just after the bullet's impact? (b) What maximum height above the equilibrium position does the center of the board reach before starting to swing down again? (c) What minimum bullet speed would be required for the board to swing all the way over after impact?

A thin rod of length \(l\) lies on the \(+x\) -axis with its left end at the origin. A string pulls on the rod with a force \(\overrightarrow{\boldsymbol{F}}\) directed toward a point \(P\) a distance \(h\) above the rod. Where along the rod should you attach the string to get the greatest torque about the origin if point \(P\) is (a) above the right end of the rod? (b) Above the left end of the rod? (c) Above the center of the rod?

A grindstone in the shape of a solid disk with diameter \(0.520 \mathrm{m},\) and a mass of 50.0 \(\mathrm{kg}\) is rotating at 850 rev/min. You press an ax against the rim with a normal force of 160 \(\mathrm{N}\) press an ax against the rim with a normal force of 160 \(\mathrm{N}\) \((\mathrm{Fig} .10 .43),\) and the grindstone comes to rest in 7.50 \(\mathrm{s}\) . Find the coefficient of friction between the ax and the grindstone. You can ignore friction in the bearings.

A horizontal plywood disk with mass 7.00 \(\mathrm{kg}\) and diameter 1.00 \(\mathrm{m}\) pivots on frictionless bearings about a vertical axis through its center. You attach a circular model-railroad track of negligible mass and average diameter 0.95 \(\mathrm{m}\) to the disk. A \(1.20-\mathrm{kg}\) , battery-driven model train rests on the tracks. To demonstrate conservation of angular momentum, you switch on the train's engine. The train moves counterclockwise, soon attaining a constant speed of 0.600 \(\mathrm{m} / \mathrm{s}\) relative to the tracks. Find the magnitude and direction of the angular velocity of the disk relative to the earth.

A machine part has the shape of a solid uniform sphere of mass 225 \(\mathrm{g}\) and diameter 3.00 \(\mathrm{cm} .\) It is spinning about a frictionless axle through its center, but at one point on its equator it is scraping against metal, resulting in a friction force of 0.0200 \(\mathrm{N}\) at that point. (a) Find its angular acceleration. (b) How long will it take to decrease its rotational speed by 22.5 \(\mathrm{rad} / \mathrm{s} ?\)

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