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Under some circumstances, a star callapse into an extremely dense object made mostly of neurrons and called a neutron star. The density of a neutron star is roughly \(10^{14}\) times as great as that of ordinary solid matter. Suppose we represent the star as a uniform, solid, rigid sphere, both before and after the collapse. The star's initial radius was \(7.0 \times 10^{5} \mathrm{km}\) (comparable to our sun); its final radius is 16 \(\mathrm{km}\) . If the original star rotated once in 30 days, find the angular speed of the neutron star.

Short Answer

Expert verified
The neutron star's angular speed is approximately 5.6 radians/second.

Step by step solution

01

Understand the Problem

We are given the initial and final conditions of a star undergoing collapse into a neutron star. We need to find the new angular speed using the conservation of angular momentum.
02

State the Conservation of Angular Momentum Formula

The angular momentum before and after the collapse is conserved. This implies:\[ L_i = L_f \]where \( L \) is the angular momentum, calculated as \( I \cdot \omega \), with \( I \) being the moment of inertia and \( \omega \) the angular speed.
03

Calculate Initial Moment of Inertia

Assume the star as a solid sphere. The moment of inertia for a solid sphere is:\[ I_i = \frac{2}{5} m R_i^2 \]where \( R_i = 7.0 \times 10^5 \times 10^3 \) meters (conversion from kilometers to meters).
04

Calculate Final Moment of Inertia

After collapse, the neutron star is also assumed to be a solid sphere. The moment of inertia now becomes:\[ I_f = \frac{2}{5} m R_f^2 \]where \( R_f = 16 \times 10^3 \) meters.
05

Relate Initial and Final Moments of Inertia

Using conservation of angular momentum,\[ I_i \omega_i = I_f \omega_f \]Substitute the expressions for \( I_i \) and \( I_f \) from earlier steps:\[ \frac{2}{5} m R_i^2 \omega_i = \frac{2}{5} m R_f^2 \omega_f \]
06

Cancel Out Common Terms and Solve for Angular Speed

The common terms \( \frac{2}{5} m \) cancel out, leading to:\[ R_i^2 \omega_i = R_f^2 \omega_f \]Rearrange to solve for \( \omega_f \):\[ \omega_f = \omega_i \frac{R_i^2}{R_f^2} \]
07

Calculate Initial Angular Speed

Convert the initial rotation period of once in 30 days into angular speed:\[ \omega_i = \frac{2\pi}{T} \]where \( T = 30 \times 24 \times 3600 \) seconds.
08

Compute the Neutron Star's Angular Speed

Substitute \( \omega_i \) and the radii into the expression for \( \omega_f \):\[ \omega_f = \frac{2\pi}{30 \times 24 \times 3600} \cdot \frac{(7.0 \times 10^8)^2}{(16 \times 10^3)^2} \]Solve for \( \omega_f \).
09

Final Calculation

Perform the calculations to find that:\[ \omega_f \approx 5.6 \text{ radians per second} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Neutron Star
When a massive star goes through the final stages of its life cycle, it can collapse under its own gravity, becoming a neutron star. This process is akin to putting the mass of the Sun into a sphere merely 16 kilometers across. Neutron stars are one of the densest objects in the universe, second only to black holes. As a result, a neutron star's density is extraordinarily high, roughly \(10^{14}\) times that of ordinary matter.
This immense density is due to the combination of extreme gravitational compression during collapse and the properties of neutron-rich matter, primarily made up of neutrons packed tightly together. In our exercise, we studied a star that went from a radius similar to the Sun's to the compact size of a neutron star, radically changing its physical characteristics while conserving certain properties like angular momentum.
Moment of Inertia
The concept of moment of inertia is fundamental in understanding how an object rotates. It depends on the object's mass distribution relative to the axis of rotation. For a solid sphere, the moment of inertia \(I\) is calculated as \(\frac{2}{5} m R^2\), where \(m\) is the mass and \(R\) is the radius.
During the transformation from a large star to a neutron star, the star's radius decreases significantly, thereby affecting its moment of inertia. As the radius decreases, the moment of inertia decreases, since it's proportionate to the square of the radius \(R^2\). This decrease is crucial in understanding how the neutron star's angular speed changes. Angular momentum need to be conserved, so when the moment of inertia drops, the angular speed has to increase to keep the product \(I \cdot \omega\) constant.
Angular Speed
Angular speed \(\omega\) is an expression of how fast something spins around an axis, measured in radians per second. In our exercise, the star's angular speed drastically changes due to the conservation of angular momentum. Initially, the star rotates slowly, once every 30 days, which is a slow angular speed of \(\omega_i = \frac{2\pi}{T}\) with \( T \) being the period in seconds.
When the star collapses to form a neutron star with a much smaller radius, its angular speed must increase. This is described by the equation \( \omega_f = \omega_i \frac{R_i^2}{R_f^2} \). Here, the original angular speed \( \omega_i \) and the ratio of the squares of the initial and final radii determine the new angular speed \( \omega_f \). From this, we calculated that the neutron star ends up spinning about 5.6 radians per second—a huge increase due to the significant decrease in radius.

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Most popular questions from this chapter

A \(15.0-\mathrm{kg}\) bucker of water is suspended by a very light rope wrapped around a solid uniform cylinder 0.300 \(\mathrm{m}\) in diameter with mass 12.0 \(\mathrm{kg}\) . The cylinder pivots on a frictionless axle through its center. The bucket is released from rest at the top of a well and falls 10.0 \(\mathrm{m}\) to the water. (a) What is the tension in the rope while the bucket is falling? (b) With what speed does the bucket strike the water? (c) What is the time of fall? (d) While the bucket is falling, what is the force exerted on the cylinder by the axle?

A stone is suspended from the free end of a wire that is wrapped around the outer rim of a pulley, similar to what is shown in Fig. \(10.10 .\) The pulley is a uniform disk with mass 10.0 \(\mathrm{kg}\) and radius 50.0 \(\mathrm{cm}\) and turns on frictionless bearings. You measure that the stone travels 12.6 \(\mathrm{m}\) in the first 3.00 s starting from rest. Find (a) the mass of the stone and (b) the tension in the wire.

A solid ball is released from rest and slides down a hillside that slopes downward at \(65.0^{\circ}\) from the horizontal, (a) What minimum value must the coefficient of static friction between the hill and ball surfaces have for no slipping to occur? (b) Would the coefficient of friction calculated in part (a) be sufficient to prevent a hollow ball (such as a soccer ball) from slipping? Justify your answer. (c) In part (a), why did we use the coefficient of static friction and not the coefficient of kinetic friction?

A small block on a frictionless, horizontal surface has a mass of 0.0250 \(\mathrm{kg}\) . It is attached to a massless cord passing through a hole in the surface (Fig. 10.48 ). The block is originally revolving at a distance of 0.300 \(\mathrm{m}\) from the hole with an angular speed of 1.75 \(\mathrm{rad} / \mathrm{s}\) . The cord is then pulled from below, shortening the radius of the circle in which the block revolves to 0.150 \(\mathrm{m}\) . Model the block as a particle. (a) Is angular momentum of the block conserved? Why or why not? (b) What is the new angular speed? (c) Find the change in kinetic energy of the block, (d) How much work was done in pulling the cord?

A thin rod of length \(l\) lies on the \(+x\) -axis with its left end at the origin. A string pulls on the rod with a force \(\overrightarrow{\boldsymbol{F}}\) directed toward a point \(P\) a distance \(h\) above the rod. Where along the rod should you attach the string to get the greatest torque about the origin if point \(P\) is (a) above the right end of the rod? (b) Above the left end of the rod? (c) Above the center of the rod?

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