/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 The two vectors \(\overrightarro... [FREE SOLUTION] | 91Ó°ÊÓ

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The two vectors \(\overrightarrow{\boldsymbol{A}}\) and \(\overrightarrow{\boldsymbol{B}}\) are drawn from a common point, and \(\overrightarrow{\boldsymbol{C}}=\overrightarrow{\boldsymbol{A}}+\overrightarrow{\boldsymbol{B}},\) (a) Show that if \(\boldsymbol{C}^{2}=\boldsymbol{A}^{2}+\boldsymbol{B}^{2},\) the angle between the vectors \(\overrightarrow{\boldsymbol{A}}\) and \(\overrightarrow{\boldsymbol{B}}\) is \(90^{\circ} .\) (b) Show that if \(C^{2}< A^{2}+B^{2},\) the angle between the vectors \(\vec{A}\) and \(\vec{B}\) is greater than \(90^{\circ}\) (c) Show that if \(C^{2}>A^{2}+B^{2},\) the angle between the vectors \(\vec{A}\) and \(\vec{B}\) is between \(0^{\circ}\) and \(90^{\circ} .\)

Short Answer

Expert verified
(a) Angle is 90°; (b) Angle > 90°; (c) Angle is between 0° and 90°.

Step by step solution

01

Vector Sum Expression

Recall that the magnitude of the vector sum \( \boldsymbol{C} \) is expressed as \( C^2 = (\boldsymbol{A} + \boldsymbol{B})^2 \). This expands to \( A^2 + B^2 + 2 \boldsymbol{A} \cdot \boldsymbol{B} \).
02

Applying Condition (a)

For part (a), we know \( C^2 = A^2 + B^2 \). Substituting this into our previous expression, \( A^2 + B^2 = A^2 + B^2 + 2 \boldsymbol{A} \cdot \boldsymbol{B} \). Simplifying, we get \( 0 = 2 \boldsymbol{A} \cdot \boldsymbol{B} \), which implies \( \boldsymbol{A} \cdot \boldsymbol{B} = 0 \). When the dot product is zero, the angle between \( \overrightarrow{\boldsymbol{A}} \) and \( \overrightarrow{\boldsymbol{B}} \) is \( 90^{\circ} \).
03

Condition (b) - Negative Dot Product

In part (b), given \( C^2 < A^2 + B^2 \), substitute this into our expanded sum: \( A^2 + B^2 + 2 \boldsymbol{A} \cdot \boldsymbol{B} < A^2 + B^2 \). Simplifying, we obtain \( 2 \boldsymbol{A} \cdot \boldsymbol{B} < 0 \), which indicates \( \boldsymbol{A} \cdot \boldsymbol{B} < 0 \). A negative dot product implies an angle greater than \( 90^{\circ} \).
04

Condition (c) - Positive Dot Product

For part (c), given \( C^2 > A^2 + B^2 \), we substitute this into \( A^2 + B^2 + 2 \boldsymbol{A} \cdot \boldsymbol{B} > A^2 + B^2 \). Simplifying gives \( 2 \boldsymbol{A} \cdot \boldsymbol{B} > 0 \), hence \( \boldsymbol{A} \cdot \boldsymbol{B} > 0 \). This means the angle is less than \( 90^{\circ} \) but greater than \( 0^{\circ} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dot Product
The dot product is an essential operation in vector analysis, often used to determine angles between vectors or project one vector onto another. It is defined for two vectors, \( \overrightarrow{\boldsymbol{A}} \) and \( \overrightarrow{\boldsymbol{B}} \), and is calculated using the formula:
\( \overrightarrow{\boldsymbol{A}} \cdot \overrightarrow{\boldsymbol{B}} = A_xB_x + A_yB_y + A_zB_z \),
where \( A_x, A_y, A_z \) and \( B_x, B_y, B_z \) are the components of the two vectors.

The dot product also has a geometric interpretation, and it can be expressed as:
\( \overrightarrow{\boldsymbol{A}} \cdot \overrightarrow{\boldsymbol{B}} = |\overrightarrow{\boldsymbol{A}}| |\overrightarrow{\boldsymbol{B}}| \cos \theta \)
where \( |\overrightarrow{\boldsymbol{A}}| \) and \( |\overrightarrow{\boldsymbol{B}}| \) are the magnitudes of the vectors, and \( \theta \) is the angle between them.

When the dot product is zero, it indicates that the vectors are perpendicular. If it is positive, the vectors point in a similar direction, and if negative, they point in opposite directions. This property helps us understand the angles formed between vectors.
Vector Magnitude
The magnitude of a vector, also known as its length or norm, is a measure of its size. It's a scalar quantity, meaning it only has size and no direction. For a vector \( \overrightarrow{\boldsymbol{A}} = (A_x, A_y, A_z) \), the magnitude is calculated using:
\[ |\overrightarrow{\boldsymbol{A}}| = \sqrt{A_x^2 + A_y^2 + A_z^2} \]

This formula is derived from the Pythagorean theorem and represents the distance of the vector from the origin in Cartesian coordinates. The importance of vector magnitude lies in its ability to scale vectors. When you want to compare vectors or use them in equations, knowing their magnitude is crucial.

Vector magnitudes are used in various applications like calculating the speed of objects, analyzing forces, or evaluating changes in physical systems. They provide a clear, quantitative measure of how much of something a vector represents.
Angle between Vectors
The angle between vectors is a crucial concept in understanding their relative orientation in space. It refers to the measure of separation between two vectors when drawn from a common point. This angle is determined using the dot product formula:
\[ \cos \theta = \frac{\overrightarrow{\boldsymbol{A}} \cdot \overrightarrow{\boldsymbol{B}}}{|\overrightarrow{\boldsymbol{A}}| |\overrightarrow{\boldsymbol{B}}|} \]

Here, \( \theta \) represents the angle between \( \overrightarrow{\boldsymbol{A}} \) and \( \overrightarrow{\boldsymbol{B}} \).

Key points about angles between vectors:
  • If \( \theta = 0^\circ \), the vectors are pointing in the same direction.
  • If \( \theta = 90^\circ \), the vectors are perpendicular.
  • If \( \theta > 90^\circ \), the vectors point in opposite hemispheres.

The angle reveals information about the spatial relationship of vectors. For example, in engineering, knowing these angles helps design components that must interact at specific orientations. In physics, it aids in analyzing vector fields and forces.

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Most popular questions from this chapter

Starting with the definition 1 in. \(=2.54 \mathrm{cm},\) find the number of (a) kilometers in 1.00 mile and (b) feet in 1.00 \(\mathrm{km}\) .

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