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Vector \(\vec{A}\) has components \(A_{x}=1.30 \mathrm{cm}, A_{y}=2.25 \mathrm{cm} ;\) vector \(\vec{B}\) has components \(B_{x}=4.10 \mathrm{cm}, B_{y}=-3.75 \mathrm{cm} .\) Find \((\mathrm{a})\) the components of the vector sum \(\overrightarrow{\boldsymbol{A}}+\overrightarrow{\boldsymbol{B}} ;\) (b) the magnitude and direction of \(\overrightarrow{\boldsymbol{A}}+\overrightarrow{\boldsymbol{B}} ;\) (c) the components of the vector difference \(\overrightarrow{\boldsymbol{B}}-\overrightarrow{\boldsymbol{A}}\) (d) the magnitude and direction of \(\overrightarrow{\boldsymbol{B}}-\overrightarrow{\boldsymbol{A}}\)

Short Answer

Expert verified
(a) \(5.40\text{ cm}, -1.50\text{ cm}\); (b) \(5.60\text{ cm}, -15.5^\circ\); (c) \(2.80\text{ cm}, -6.00\text{ cm}\); (d) \(6.62\text{ cm}, -64.0^\circ\).

Step by step solution

01

Calculate the Components of Vector Sum

To find the components of the vector sum \( \vec{A} + \vec{B} \), you need to add the corresponding components of vectors \( \vec{A} \) and \( \vec{B} \). \[ A_x + B_x = 1.30 \text{ cm} + 4.10 \text{ cm} = 5.40 \text{ cm} \]\[ A_y + B_y = 2.25 \text{ cm} + (-3.75 \text{ cm}) = -1.50 \text{ cm} \]Therefore, the components of \( \vec{A} + \vec{B} \) are \( 5.40 \text{ cm} \) in the x-direction and \( -1.50 \text{ cm} \) in the y-direction.
02

Calculate Magnitude of Vector Sum

The magnitude of the vector sum \( \vec{A} + \vec{B} \) can be calculated with the formula:\[\text{Magnitude} = \sqrt{(A_x + B_x)^2 + (A_y + B_y)^2}\]Substitute the values from Step 1:\[\text{Magnitude} = \sqrt{(5.40)^2 + (-1.50)^2} = \sqrt{29.16 + 2.25} = \sqrt{31.41} \approx 5.60 \text{ cm}\]
03

Calculate Direction of Vector Sum

The direction of \( \vec{A} + \vec{B} \) can be found using the tangent function:\[\text{Direction} = \tan^{-1}\left(\frac{A_y + B_y}{A_x + B_x}\right)\]Substitute the known values:\[\text{Direction} = \tan^{-1}\left(\frac{-1.50}{5.40}\right) \approx \tan^{-1}(-0.278) \approx -15.5^\circ\]
04

Calculate Components of Vector Difference

To find the components of the vector difference \( \vec{B} - \vec{A} \), subtract the components of \( \vec{A} \) from those of \( \vec{B} \):\[ B_x - A_x = 4.10 \text{ cm} - 1.30 \text{ cm} = 2.80 \text{ cm} \]\[ B_y - A_y = -3.75 \text{ cm} - 2.25 \text{ cm} = -6.00 \text{ cm} \]Thus, the components of \( \vec{B} - \vec{A} \) are \( 2.80 \text{ cm} \) in the x-direction and \( -6.00 \text{ cm} \) in the y-direction.
05

Calculate Magnitude of Vector Difference

The magnitude of the vector difference \( \vec{B} - \vec{A} \) is calculated using:\[\text{Magnitude} = \sqrt{(B_x - A_x)^2 + (B_y - A_y)^2}\]Plug in the values from Step 4:\[\text{Magnitude} = \sqrt{(2.80)^2 + (-6.00)^2} = \sqrt{7.84 + 36.00} = \sqrt{43.84} \approx 6.62 \text{ cm}\]
06

Calculate Direction of Vector Difference

The direction of \( \vec{B} - \vec{A} \) can be determined by the formula:\[\text{Direction} = \tan^{-1}\left(\frac{B_y - A_y}{B_x - A_x}\right)\]Substitute the known values:\[\text{Direction} = \tan^{-1}\left(\frac{-6.00}{2.80}\right) \approx \tan^{-1}(-2.143) \approx -64.0^\circ\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Components
Vectors are often broken down into their components to simplify calculations. Each vector can be represented in terms of an x-component and a y-component. These components correspond to the projections of the vector along the x-axis and y-axis of a coordinate system. In the given example, vector \(\vec{A}\) is broken into components \(A_x=1.30 \text{ cm}\) and \(A_y=2.25 \text{ cm}\), while vector \(\vec{B}\) has components \(B_x=4.10 \text{ cm}\) and \(B_y=-3.75 \text{ cm}\).

To find the components of a vector sum like \(\vec{A} + \vec{B}\), simply add the corresponding components:
  • \(x\)-components: \(A_x + B_x = 5.40 \text{ cm}\)
  • \(y\)-components: \(A_y + B_y = -1.50 \text{ cm}\)
Similarly, to find the components of a vector difference \(\vec{B} - \vec{A}\), subtract the components:
  • \(x\)-components: \(B_x - A_x = 2.80 \text{ cm}\)
  • \(y\)-components: \(B_y - A_y = -6.00 \text{ cm}\)
This method creates a straightforward way to do vector addition and subtraction using vector components.
Magnitude and Direction
After determining the components of a vector, calculating the magnitude and direction gives a complete description of the vector's effect. The magnitude is a scalar value representing the vector's size or length. It can be found using the Pythagorean theorem on the vector's components.

For the vector sum \(\vec{A} + \vec{B}\) with components \((5.40, -1.50)\), the magnitude is computed as:
\[\text{Magnitude} = \sqrt{(5.40)^2 + (-1.50)^2} \approx 5.60 \text{ cm}\]

The direction is the angle the vector makes with the positive x-axis, calculated using the inverse tangent function (\(\tan^{-1}\)). For \(\vec{A} + \vec{B}\), this angle is:
\[\text{Direction} = \tan^{-1}\left(\frac{-1.50}{5.40}\right) \approx -15.5^\circ\]

Understanding both magnitude and direction allows us to fully interpret where a vector points and how strong its effect is in a physical system.
Vector Algebra
Vector algebra involves mathematical operations that focus on vectors. These operations include addition, subtraction, and multiplication (by scalars or other vectors). Instead of dealing with vectors as arrows, vector algebra treats them as mathematical entities with components.

Addition and subtraction are performed by component-wise operations. This means manipulating each component of the vectors separately, as shown in the example:
  • For the sum of vectors \(\vec{A} + \vec{B}\), add corresponding components to get the result quickly.
  • For the difference \(\vec{B} - \vec{A}\), subtract the components directly to achieve the result.
These operations are crucial in physics and engineering since they simplify how forces, velocities, and other vector quantities interact in multi-dimensional spaces.

Mastering vector algebra is essential for solving real-world problems involving motion, forces, and other phenomena that require handling multiple directions simultaneously.

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Most popular questions from this chapter

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