Chapter 1: Problem 40
Find the magnitude and direction of the vector represented by the following pairs of components: (a) \(A_{x}=-8.60 \mathrm{cm}\), \(A_{y}=5.20 \mathrm{cm}\) (b) \(A_{x}=-9.70 \mathrm{m}, A_{y}=-2.45 \mathrm{m};\) (b) \(A_{x}=-9.70 \mathrm{m}, A_{y}=-2.45 \mathrm{m};\) (c) \(A_{x}=7.75 \mathrm{km}\), \(A_{y}=-2.70 \mathrm{km}\).
Short Answer
Step by step solution
Calculate the Magnitude for Part a
Calculate the Direction for Part a
Calculate the Magnitude for Part b
Calculate the Direction for Part b
Calculate the Magnitude for Part c
Calculate the Direction for Part c
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude of a Vector
If you're given a vector with components \(A_x\) and \(A_y\), the magnitude \(|A|\) is determined using the Pythagorean theorem, which relates the square of the hypotenuse of a right triangle to the sum of the squares of its other two sides. The formula is:
- \(|A| = \sqrt{A_x^2 + A_y^2}\)
Direction of a Vector
To find the direction \(\theta\) of a vector with components \(A_x\) and \(A_y\), we use the arctangent function, denoted as \(\arctan\). The formula is:
- \(\theta = \arctan\left(\frac{A_y}{A_x}\right)\)
Pythagorean Theorem
For instance, if you have a vector that can be expressed by the components along the x-axis and y-axis, you essentially form a right triangle. The vector itself serves as the hypotenuse, and the relationship as stated by the Pythagorean theorem is:
- \(c^2 = a^2 + b^2\)
- Where \(c\) is the vector (hypotenuse), and \(a\) and \(b\) are its components (legs of the triangle).
Quadrant Analysis
- First Quadrant: \((+x, +y)\)
- Second Quadrant: \((-x, +y)\)
- Third Quadrant: \((-x, -y)\)
- Fourth Quadrant: \((+x, -y)\)