/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 With a wooden ruler you measure ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

With a wooden ruler you measure the length of a rectangular piece of sheet metal to be 12 \(\mathrm{mm}\) . You use micrometer calipers to measure the width of the rectangle and obtain the value 5.98 \(\mathrm{mm}\). Give your answers to the following questions to the correct number of significant figures. (a) What is the area of the rectangle? (b) What is the ratio of the rectangle's width to its length? (c) What is the perimeter of the rectangle? (d) What is the difference between the length and width? (e) What is the ratio of the length to the width?

Short Answer

Expert verified
Area: 72 mm²; Width/Length Ratio: 0.50; Perimeter: 36 mm; Difference: 6.0 mm; Length/Width Ratio: 2.0.

Step by step solution

01

Determine the Area of the Rectangle

To find the area of the rectangle, use the formula: \[ A = ext{length} \times ext{width} \]Substitute the given values:\[ A = 12 \, \mathrm{mm} \times 5.98 \, \mathrm{mm} \]Calculating the above gives:\[ A = 71.76 \, \mathrm{mm}^2 \]Since the least number of significant figures among the measurements is 2 (from the length, 12 mm), we round the area to 72 mm².
02

Calculate the Ratio of Width to Length

The ratio of the rectangle's width to its length is given by:\[ \text{Ratio} = \frac{\text{width}}{\text{length}} = \frac{5.98 \, \mathrm{mm}}{12 \, \mathrm{mm}} \]Compute the division:\[ \text{Ratio} \approx 0.4983 \]Since the length in the division has 2 significant figures, we round the ratio to 0.50.
03

Find the Perimeter of the Rectangle

The formula for the perimeter of a rectangle is:\[ P = 2(\text{length} + \text{width}) \]Plug in the given measurements:\[ P = 2(12 \, \mathrm{mm} + 5.98 \, \mathrm{mm}) \]Calculate:\[ P = 2(17.98 \, \mathrm{mm}) = 35.96 \, \mathrm{mm} \]Rounding to the least number of significant figures, 36 mm.
04

Determine the Difference Between Length and Width

The difference is found using:\[ \text{Difference} = \text{length} - \text{width} = 12 \, \mathrm{mm} - 5.98 \, \mathrm{mm} \]Perform the subtraction:\[ \text{Difference} = 6.02 \, \mathrm{mm} \]Round this to 6.0 mm using 2 significant figures.
05

Calculate the Ratio of Length to Width

The ratio of the rectangle's length to its width is:\[ \text{Ratio} = \frac{\text{length}}{\text{width}} = \frac{12 \, \mathrm{mm}}{5.98 \, \mathrm{mm}} \]Compute the division:\[ \text{Ratio} \approx 2.0067 \]Rounding to the least number of significant figures, the ratio is 2.0.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Measurement Accuracy
Measurement accuracy is crucial when determining values that will be multiplied or divided. It refers to how close a measured value is to the true value or an accepted standard, and is often expressed in terms of significant figures. Significant figures are the digits in a number that contribute to its precision. They include all non-zero digits, any zeros between significant digits, and any trailing zeros in the decimal part. In the exercise, the length measurement is 12 mm, which contains two significant figures. The width is measured at 5.98 mm with three significant figures. When performing calculations such as area, perimeter, or ratios, the result should be rounded to the least number of significant figures. This ensures the accuracy of the measurements is preserved throughout any calculations.
Unit Conversion
Unit conversion is the process of converting a measure to an equivalent value in a different unit. While the exercise focuses on measurements in millimeters, understanding unit conversions is vital for comprehensive learning. Let's say you needed to convert millimeters to centimeters. Since 1 cm equals 10 mm, you would divide a millimeter measure by 10 to convert it into centimeters. For instance, converting the length of 12 mm would result in 1.2 cm. Converting units also helps in understanding quantities in different contexts, which is especially useful in fields ranging from science and engineering to everyday situations. Remember to ensure consistency in units across all measurements when performing calculations.
Rectangular Area Calculation
Calculating the area of a rectangle involves multiplying its length by its width. The formula is straightforward and given by \( A = ext{length} \times ext{width} \). In our exercise, substituting the given values, the calculation becomes: \( A = 12 \, \text{mm} \times 5.98 \, \text{mm} \). This results in an unrounded area of 71.76 mm². However, due to the limitation of significant figures, we round the area to 72 mm² as it must conform to the smallest significant figure count, in this case, two from the length measurement. Understanding this concept aids in carrying out precise and accurate measurements in practical applications like engineering and carpentry.
Perimeter Calculation
The perimeter of a rectangle is calculated by summing twice its length and twice its width, formulated as \( P = 2( ext{length} + ext{width}) \). Using our exercise's measurements, the perimeter would be calculated as \( P = 2(12 \, \text{mm} + 5.98 \, \text{mm}) = 35.96 \, \text{mm} \). As perimeter must be communicated with the correct significant figures, we round it to 36 mm. Perimeter calculations are vital in situations where the boundary length is significant, such as fencing a garden or planning the layout for a floor. Accurate perimeter measurement allows for optimal planning and resource management, ensuring no wastage or shortage of materials.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You are hungry and decide to go to your favorite neighbor- hood fast-food restaurant. You leave your apartment and take the elevator 10 flights down (each flight is 3.0 \(\mathrm{m}\) ) and then go 15 \(\mathrm{m}\) south to the apartment exit. You then proceed 0.2 \(\mathrm{km}\) east, turn north, and go 0.1 \(\mathrm{km}\) to the entrance of the restaurant. (a) Determine the displacement from your apartment to the restaurant. Use unit vector notation for your answer, being sure to make clear your choice of coordinates. (b) How far did you travel along the path you took from your apartment to the restaurant, and what is the magnitude of the displacement you calculated in part (a)?

Getting Back. An explorer in the dense jungles of equatorial Africa leaves his hut. He takes 40 steps northeast, then 80 steps \(60^{\circ}\) north of west, then 50 steps due south. Assume his steps all have equal length. (a) Sketch, roughly to scale, the three vectors and their resultant, (b) Save the explorer from becoming hopelessly lost in the jungle by giving him the displacement, calculated using the method of components, that will return him to his hut.

A rectangular piece of aluminum is \(5.10 \pm 0.01 \mathrm{cm}\) long and \(1.90 \pm 0.01 \mathrm{cm}\) wide. (a) Find the area of the rectangle and the uncertainty in the area. (b) Verify that the fractional uncertainty in the area is equal to the sum of the fractional uncertainties in the length and in the width. (This is a general result; see Challenge Problem \(1.98 .\))

How many nanoseconds does it take light to travel 1.00 \(\mathrm{ft}\) in vacuum? (This result is a useful quantity to remember.)

(a) Use vector components to prove that two vectors commute for both addition and the scalar product. (b) Prove that two vectors anticommute for the vector product; that is, prove that \(\overrightarrow{\boldsymbol{A}} \times \overrightarrow{\boldsymbol{B}}=-\overrightarrow{\boldsymbol{B}} \times \overrightarrow{\boldsymbol{A}}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.