/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 To solve problems involving proj... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 7: Problem 14

To solve problems involving projectiles traveling through the air by applying the law of conservation of momentum requires evaluating the momentum of the system immediately before and immediately after the collision or explosion. Why?

Short Answer

Expert verified
Answer: Evaluating the momentum of a projectile system immediately before and immediately after a collision or explosion is important because it allows us to apply the law of conservation of momentum accurately. This law states that the total momentum of an isolated system remains constant if no external forces are acting upon it. By analyzing the momentum at these specific instances, we can ignore the effect of any external forces that may be acting during the collision or explosion and efficiently solve challenges involving projectiles, collisions, and explosions.

Step by step solution

01

Law of Conservation of Momentum

The law of conservation of momentum states that the total momentum of an isolated system remains constant if no external forces are acting upon it. This means that the momentum before a collision or an explosion is equal to the momentum after the event.
02

Momentum Before and After Collision or Explosion

To analyze problems involving projectiles and momentum conservation, we should evaluate the momentum of the system immediately before and immediately after the event. This is because momentum is conserved only at these specific instances when considering collisions or explosions. During the collision or explosion, external forces might be acting on the system, altering the momentum. By studying the momentum immediately before and after, we can ignore the effect of these forces and apply the law of conservation of momentum.
03

Applying Conservation of Momentum

Given the initial conditions (speed, mass and direction) of the objects involved in the collision or explosion, calculate the total momentum of the system immediately before the event. Then, using the conservation of momentum, determine the possible outcomes after the event, which should maintain the total momentum conserved. This is the most reliable and efficient way to solve challenges involving projectiles traveling through the air, colliding, or exploding. In summary, evaluating the momentum of a projectile system immediately before and immediately after a collision or explosion is necessary to accurately apply the law of conservation of momentum and effectively solve these types of problems.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An automobile with a mass of \(1450 \mathrm{~kg}\) is parked on a moving flatbed railcar; the flatbed is \(1.5 \mathrm{~m}\) above the ground. The railcar has a mass of \(38,500 \mathrm{~kg}\) and is moving to the right at a constant speed of \(8.7 \mathrm{~m} / \mathrm{s}\) on a frictionless rail. The automobile then accelerates to the left, leaving the railcar at a speed of \(22 \mathrm{~m} / \mathrm{s}\) with respect to the ground. When the automobile lands, what is the distance \(D\) between it and the left end of the railcar? See the figure.

Stuck in the middle of a frozen pond with only your physics book, you decide to put physics in action and throw the 5.00 -kg book. If your mass is \(62.0 \mathrm{~kg}\) and you throw the book at \(13.0 \mathrm{~m} / \mathrm{s}\), how fast do you then slide across the ice? (Assume the absence of friction.)

Consider two carts, of masses \(m\) and \(2 m\), at rest on a frictionless air track. If you push the lower-mass cart for \(3 \mathrm{~s}\) and then the other cart for the same length of time and with the same force, which cart undergoes the larger change in momentum? a) The cart with mass \(m\) has the larger change b) The cart with mass \(2 m\) has the larger change. c) The change in momentum is the same for both carts. d) It is impossible to tell from the information given.

A billiard ball of mass \(m=0.250 \mathrm{~kg}\) hits the cushion of a billiard table at an angle of \(\theta_{1}=60.0^{\circ}\) at a speed of \(v_{1}=27.0 \mathrm{~m} / \mathrm{s}\) It bounces off at an angle of \(\theta_{2}=71.0^{\circ}\) and a speed of \(v_{2}=10.0 \mathrm{~m} / \mathrm{s}\). a) What is the magnitude of the change in momentum of the billiard ball? b) In which direction does the change of momentum vector point?

A 3.0 -kg ball of clay with a speed of \(21 \mathrm{~m} / \mathrm{s}\) is thrown against a wall and sticks to the wall. What is the magnitude of the impulse exerted on the ball?
See all solutions

Recommended explanations on Physics Textbooks

Geometrical and Physical Optics

Read Explanation

Electricity

Read Explanation

Measurements

Read Explanation

Electric Charge Field and Potential

Read Explanation

Scientific Method Physics

Read Explanation

Force

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.