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Calculate the force \(F(y)\) associated with each of the following potential energies: a) \(U=a y^{3}-b y^{2}\) b) \(U=U_{0} \sin (c y)\)

Short Answer

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Question: Calculate the force, \(F(y)\), associated with the following potential energies: a) \(U = a y^{3} - b y^{2}\) b) \(U = U_{0} \sin (c y)\) Answer: a) \(F(y) = -3 a y^{2} + 2 b y\) b) \(F(y) = -U_{0} c \cos (c y)\)

Step by step solution

01

Calculate Force for Potential Energy a) \(U=a y^{3}-b y^{2}\)

First, we need to find the derivative of the potential energy: \(\frac{dU}{dy}\). So, differentiate the given potential energy \(U = a y^{3} - b y^{2}\) with respect to \(y\). \(\frac{dU}{dy} = \frac{d}{dy}(a y^{3} - b y^{2}) = 3 a y^{2} - 2 b y.\) To find the force, we simply multiply this result by \(-1\): \(F(y) = -\frac{dU}{dy} = -(3 a y^{2} - 2 b y) = -3 a y^{2} + 2 b y\).
02

Calculate Force for Potential Energy b) \(U=U_{0} \sin (c y)\)

Again, we need to find the derivative of the potential energy: \(\frac{dU}{dy}\). So, differentiate the given potential energy \(U = U_{0} \sin (c y)\) with respect to \(y\). \(\frac{dU}{dy} = \frac{d}{dy}(U_{0} \sin (c y)) = U_{0} c \cos (c y).\) To find the force, we multiply this result by \(-1\): \(F(y) = -\frac{dU}{dy} = -U_{0} c \cos (c y)\). The force associated with each potential energy is: a) \(F(y) = -3 a y^{2} + 2 b y\) b) \(F(y) = -U_{0} c \cos (c y)\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force Calculation
Calculating force from potential energy is a fundamental concept in physics. When you understand that potential energy can be expressed as a function of position, you can calculate the force exerted by this energy. The force is essentially the negative of the gradient (or the derivative) of potential energy with respect to its position variable.

For example, if you have a potential energy function, say, in terms of the variable position - denoted by \( y \), you find the derivative with respect to \( y \). This derivative gives you the rate of change of potential energy. The resulting derivative represents how the potential energy changes across different positions. By multiplying this derivative by -1, you finally get the force \( F(y) \), as force tends to oppose the direction of increasing potential energy.

Key Points to Remember for Force Calculation from Potential Energy:
  • Express potential energy as a function of position \( U(y) \).
  • Differentiate \( U(y) \) with respect to \( y \) to find the rate of change.
  • Multiply by -1 to determine the force \( F(y) \) that opposes the energy change.
Derivative in Physics
Derivatives play a pivotal role in physics, especially in problems involving motion and forces. A derivative essentially measures how a function changes as its input changes. In the context of physics, derivatives help us understand how physical quantities change over time or position.

Let's consider a simple example in the realm of potential energy. For a potential energy function \( U(y) \), the derivative with respect to \( y \) is \( \frac{dU}{dy} \). This derivative helps to calculate the force exerted by that potential, as it tells us the rate at which the potential energy changes as the position \( y \) changes.

Why Derivatives Matter in Physics:
  • They provide the rate of change in quantities like position or energy.
  • Derivatives help convert complex physical relationships into more manageable forms.
  • They are fundamental in determining motion and understanding forces.
Sinusoidal Potential
Sinusoidal potential refers to potential energy expressed as a sine function. It's a common way to describe oscillating systems where energy changes periodically, such as springs or waves.

A common form is \( U(y) = U_{0} \sin (cy) \), where \( U_{0} \) is the amplitude and \( c \) is a constant that affects the frequency of oscillation. The force derived from a sinusoidal potential, after differentiation and multiplication by -1, is \( F(y) = -U_{0}c \cos (cy) \). The cosine function results naturally because the derivative of sine is cosine.

Features of Sinusoidal Potential in Physical Systems:
  • Commonly models periodic or oscillatory systems.
  • Easy to compute force due to simple derivatives.
  • Useful in studying wave mechanics and harmonic motions.

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Most popular questions from this chapter

A father exerts a \(2.40 \cdot 10^{2} \mathrm{~N}\) force to pull a sled with his daughter on it (combined mass of \(85.0 \mathrm{~kg}\) ) across a horizontal surface. The rope with which he pulls the sled makes an angle of \(20.0^{\circ}\) with the horizontal. The coefficient of kinetic friction is \(0.200,\) and the sled moves a distance of \(8.00 \mathrm{~m}\). Find a) the work done by the father, b) the work done by the friction force, and c) the total work done by all the forces.

A child throws three identical marbles from the same height above the ground so that they land on the flat roof of a building. The marbles are launched with the same initial speed. The first marble, marble \(\mathrm{A}\), is thrown at an angle of \(75^{\circ}\) above horizontal, while marbles \(\mathrm{B}\) and \(\mathrm{C}\) are thrown with launch angles of \(60^{\circ}\) and \(45^{\circ}\), respectively. Neglecting air resistance, rank the marbles according to the speeds with which they hit the roof. a) \(A

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A projectile of mass \(m\) is launched from the ground at \(t=0\) with a speed \(v_{0}\) and at an angle \(\theta_{0}\) above the horizontal. Assuming that air resistance is negligible, write the kinetic, potential, and total energies of the projectile as explicit functions of time.

You have decided to move a refrigerator (mass \(=81.3 \mathrm{~kg}\), including all the contents) to the other side of the room. You slide it across the floor on a straight path of length \(6.35 \mathrm{~m}\), and the coefficient of kinetic friction between floor and fridge is \(0.437 .\) Happy about your accomplishment, you leave the apartment. Your roommate comes home, wonders why the fridge is on the other side of the room, picks it up (you have a strong roommate!), carries it back to where it was originally, and puts it down. How much net mechanical work have the two of you done together?

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