/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 An approximate one-dimensional q... [FREE SOLUTION] | 91Ó°ÊÓ

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An approximate one-dimensional quantum well can be formed by surrounding a layer of GaAs with layers of \(\mathrm{Al}_{x} \mathrm{Ga}_{1-x}\) As. The GaAs layers can be fabricated in thicknesses that are integral multiples of the single-layer thickness, \(0.28 \mathrm{nm}\). Some electrons in the GaAs layer behave as if they were trapped in a box. For simplicity, treat the box as an infinite one-dimensional well and ignore the interactions between the electrons and the Ga and As atoms (such interactions are often accounted for by replacing the actual electron mass with an effective electron mass). Calculate the energy of the ground state in this well for these cases: a) 2 GaAs layers b) 5 GaAs layers

Short Answer

Expert verified
Answer: The ground state energy for a GaAs well surrounded by two GaAs layers is around \(15.94 eV\), and for the well surrounded by five GaAs layers, it is around \(2.26 eV\).

Step by step solution

01

Calculate the size of the well for both cases

Since the GaAs layers can be fabricated at thicknesses that are integral multiples of the single-layer thickness (\(0.28nm\)), we calculate the size of the well for both cases: a) \(L_a = 2 \times 0.28 nm = 0.56 nm\) b) \(L_b = 5 \times 0.28 nm = 1.4 nm\) Convert these lengths to meters: a) \(L_a = 0.56 \times 10^{-9} m\) b) \(L_b = 1.4 \times 10^{-9} m\)
02

Calculate the effective mass of the electron in GaAs

To find out the effective mass of the electron in GaAs, we need to multiply the effective mass ratio (\(m^* \approx 0.067 m_e\)) by the electron mass (\(m_e \approx 9.11 \times 10^{-31} kg\)): \(m^* = 0.067 \times 9.11 \times 10^{-31} kg \approx 6.1 \times 10^{-32} kg\)
03

Calculate the ground state energy for both cases using the formula

Now we are ready to use the formula for the energy levels of an infinite potential well to calculate the ground state energy (\(n = 1\)) for both cases: a) \(E_{1a} = \frac{1^2 \pi^2 \hbar^2}{2 m^* L_a^2}\) b) \(E_{1b} = \frac{1^2 \pi^2 \hbar^2}{2 m^* L_b^2}\) a) \(E_{1a} = \frac{1^2 \pi^2 (6.58 \times 10^{-16} eV \cdot s)^2}{2 (6.1 \times 10^{-32} kg) (0.56 \times 10^{-9} m)^2} \approx 15.94 eV\) b) \(E_{1b} = \frac{1^2 \pi^2 (6.58 \times 10^{-16} eV \cdot s)^2}{2 (6.1 \times 10^{-32} kg) (1.4 \times 10^{-9} m)^2} \approx 2.26 eV\) Thus, the ground state energy for a GaAs well surrounded by two GaAs layers is around \(15.94 eV\), and for the well surrounded by five GaAs layers, it is around \(2.26 eV\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

GaAs
Gallium Arsenide, often abbreviated as GaAs, is a compound semiconductor made of gallium and arsenic. It is widely used in the creation of quantum wells because of its exceptional electronic properties. Unlike silicon, GaAs has a direct band gap, which means electrons can emit light efficiently. This makes it ideal for optoelectronic applications like laser diodes and LEDs.
GaAs is particularly noted for its high electron mobility, which allows for faster electron movement than in silicon. This leads to quicker semiconductor devices. The material can be grown in layers using methods such as molecular beam epitaxy, allowing for the precise fabrication of quantum well structures.
In a GaAs quantum well, impacts such as confinement and interband transitions become significant, which influence the electronic and optical properties of the structure. Thus, GaAs layers serve as excellent materials for studying and creating semiconductor devices at the quantum mechanical level.
Effective Mass
In semiconductor physics, the concept of effective mass is used to simplify the complex interactions between electrons and the crystal lattice of the semiconductor. The effective mass of an electron in a material like GaAs is not the same as the mass of a free electron. This is because the electron interacts with the periodic electric fields produced by the atomic lattice.
The effective mass is a theoretical value that reflects how the electron responds to external forces, accounting for these interactions. In the case of GaAs, the effective mass is typically much smaller than the free electron mass. It’s given by the relationship:
  • \( m^* \approx 0.067 \, m_e \),
where \( m_e \) is the mass of a free electron, approximately \( 9.11 \times 10^{-31} \, kg \).
This lower effective mass in GaAs results in higher electron mobility, typically leading to better performance in semiconductor devices like transistors, as it allows electrons to accelerate more easily under the influence of an electric field.
Infinite Potential Well
The infinite potential well is a fundamental model in quantum mechanics. It is used to illustrate how particles like electrons behave when confined in a region with impenetrable boundaries. Think of it as a very small box where an electron can move freely, but cannot escape.
This idealized situation has perfectly rigid walls which means the potential energy is zero inside the well and infinite outside. Because of this setup, the electron cannot have just any energy value; instead, its energy is quantized.
The energy levels of an electron in an infinite potential well are determined by the equation:
  • \( E_n = \frac{n^2 \pi^2 \hbar^2}{2 m^* L^2} \),
where:
  • \( n \) is the quantum number (n = 1, 2, 3,...),
  • \( \hbar \) is the reduced Planck's constant,
  • \( m^* \) is the effective mass of the electron,
  • \( L \) is the width of the well.
As the quantum number \( n \) increases, the energy level of the electron also increases. This means electrons in a smaller well (small \( L \)) will have larger energy gaps, and quantization effects will be more significant, affecting device properties when scaled down to small dimensions.

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Most popular questions from this chapter

Two long, straight wires that lie along the same line have a separation at their tips of \(2.00 \mathrm{nm}\). The potential energy of an electron in the gap is about \(1.00 \mathrm{eV}\) higher than it is in the conduction band of the two wires. Conduction-band electrons have enough energy to contribute to the current flowing in the wire. What is the probability that a conduction electron in one wire will be found in the other wire after arriving at the gap?

For a particle trapped in an infinite square well of length \(L\), what happens to the probability that the particle is found between 0 and \(L / 2\) as the particle's energy increases?

State whether each of the following statements is true or false a) In a one-dimensional quantum harmonic oscillator, the energy levels are evenly spaced. b) In an infinite one-dimensional potential well, the energy levels are evenly spaced. c) The minimum total energy possible for a classical harmonic oscillator is zero. d) The correspondence principle states that because the minimum possible total energy for the classical simple harmonic oscillator is zero, the expected value for the fundamental state \((n=0)\) of the one-dimensional quantum harmonic oscillator should also be zero. e) The \(n=0\) state of the one-dimensional quantum harmonic oscillator is the state with the minimum possible uncertainty \(\Delta x \Delta p\)

A surface is examined using a scanning tunneling microscope (STM). For the range of the working gap, \(L\), between the tip and the sample surface, assume that the electron wave function for the atoms under investigation falls off exponentially as \(|\Psi|=e^{-\left(10.0 \mathrm{nm}^{-1}\right) a}\). The tunneling current through the STM tip is proportional to the tunneling probability. In this situation, what is the ratio of the current when the STM tip is \(0.400 \mathrm{nm}\) above a surface feature to the current when the tip is \(0.420 \mathrm{nm}\) above the surface?

37.2 In an infinite square well, for which of the following states will the particle never be found in the exact center of the well? a) the ground state b) the first excited state c) the second excited state d) any of the above e) none of the above

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