/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 You are driving down a straight ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

You are driving down a straight highway at a speed of \(v=50.0 \mathrm{~m} / \mathrm{s}\) relative to the ground. An oncoming car travels with the same speed in the opposite direction. With what relative speed do you observe the oncoming car?

Short Answer

Expert verified
Answer: The relative speed between the two cars is 100.0 m/s.

Step by step solution

01

Given values

The given values are: - Speed of car 1 relative to the ground, \(v_1 = 50.0 \mathrm{~m/s}\) - Speed of car 2 relative to the ground, \(v_2 = 50.0 \mathrm{~m/s}\)
02

Calculate relative speed between the two cars

Since both cars are moving in opposite directions, we simply add their individual speeds relative to the ground to determine the combined relative speed between them. $$v_\text{relative} = v_1 + v_2$$ Plugging in the given values, we get: $$v_\text{relative} = 50.0 \mathrm{~m/s} + 50.0 \mathrm{~m/s}$$
03

Solve for relative speed

Adding the speeds together, we find the relative speed between the two cars: $$v_\text{relative} = 100.0 \mathrm{~m/s}$$ This means the oncoming car is observed to be traveling at a relative speed of \(100.0 \mathrm{~m/s}\) with respect to the other car.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Kinematics
Kinematics is a branch of physics that deals with motion. It helps us understand how objects move, describing their velocity, acceleration, and displacement without considering the forces that cause them to move. In this problem, kinematics allows us to analyze the motion of two cars on a highway.
  • Velocity describes how fast an object moves and in what direction.
  • Speed is the magnitude of velocity and ignores direction.
By focusing on speed and direction, kinematics makes it easier for us to understand how objects behave when in motion, such as our cars traveling in opposite directions.
Exploring Relative Motion
Relative motion refers to how the motion of one object is perceived from another's point of view. It highlights that motion isn't absolute; instead, it's always related to something else. Imagine standing on the highway while two cars zoom past one another. Each driver sees the other car moving faster than their own speed relative to the ground.
  • When two objects move towards each other, their speeds are added.
  • When moving in the same direction, their relative speed is the difference between their speeds.
In our example, each car sees the other approaching at a relative speed much greater than their individual ground speed. This concept of relative motion helps us describe how fast objects move in relation to one another.
The Principle of Velocity Addition
The principle of velocity addition allows us to determine the combined speed of two moving objects as seen from one another. Using this, we can simplify calculations involving relative speeds.

In our exercise, each car's speed is 50.0 m/s relative to the ground. As they are moving in opposite directions, we apply the velocity addition principle to compute their relative velocity:
\[v_\text{relative} = v_1 + v_2 = 50.0 \, \text{m/s} + 50.0 \, \text{m/s} = 100.0 \, \text{m/s}\]
  • The cars' speeds are summed because they move towards each other.
  • This method provides a straightforward way to understand how quickly they approach one another.
Velocity addition simplifies problems by offering a clear way to determine combined speeds, making it easier to understand interactions in relative terms.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

At what speed will the length of a meter stick look \(90.0 \mathrm{~cm} ?\)

A spacecraft travels along a straight line from Earth to the Moon, a distance of \(3.84 \cdot 10^{8} \mathrm{~m}\). Its speed measured on Earth is \(0.50 c\). a) How long does the trip take, according to a clock on Earth? b) How long does the trip take, according to a clock on the spacecraft? c) Determine the distance between Earth and the Moon if it were measured by a person on the spacecraft.

A HeNe laser onboard a spaceship moving toward a remote space station emits a beam of red light toward the space station. The wavelength of the beam, as measured by a wavelength meter on board the spaceship, is \(632.8 \mathrm{nm}\). If the astronauts on the space station see the beam as a blue beam of light with a measured wavelength of \(514.5 \mathrm{nm},\) what is the relative speed of the spaceship with respect to the space station? What is the shift parameter \(z\) in this case?

In the age of interstellar travel, an expedition is mounted to an interesting star 2000.0 light-years from Earth. To make it possible to get volunteers for the expedition, the planners guarantee that the round trip to the star will take no more than \(10.000 \%\) of a normal human lifetime. (At that time the normal human lifetime is 400.00 years.) What is the minimum speed the ship carrying the expedition must travel?

Consider motion in one spatial dimension. For any velocity \(v,\) define parameter \(\theta\) via the relation \(v=c \tanh \theta\) where \(c\) is the vacuum speed of light. This quantity is variously called the velocity parameter or the rapidity corresponding to velocity \(v\). a) Prove that for two velocities, which add according to the Lorentzian rule, the corresponding velocity parameters simply add algebraically, that is, like Galilean velocities. b) Consider two reference frames in motion at speed \(v\) in the \(x\) -direction relative to one another, with axes parallel and origins coinciding when clocks at the origin in both frames read zero. Write the Lorentz transformation between the two coordinate systems entirely in terms of the velocity parameter corresponding to \(v\), and the coordinates.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.