/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Light from an argon laser strike... [FREE SOLUTION] | 91Ó°ÊÓ

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Light from an argon laser strikes a diffraction grating that has 7020 grooves per centimeter. The central and firstorder principal maxima are separated by \(0.332 \mathrm{~m}\) on a wall \(1.00 \mathrm{~m}\) from the grating. Determine the wavelength of the laser light.

Short Answer

Expert verified
Answer: The wavelength of the laser light is approximately \(454 \mathrm{~nm}\).

Step by step solution

01

Find the Grating Separation (d)

The grating separation (d) can be determined by the formula: \(d = \frac{1}{N}\) Where N is the number of grooves per centimeter. In this case, N = 7020 grooves per centimeter. \(d = \frac{1}{7020}\) \(d = 1.42 \times 10^{-4} \mathrm{~cm}\)
02

Convert Grating Separation to Meters

To work with meters in the rest of the problem, convert the grating separation (d) to meters: \(d = 1.42\times10^{-4}\ \text{cm}\times\frac{1\text{ m}}{100\text{ cm}} = 1.42\times10^{-6}\ \text{m}\)
03

Calculate the Angle Between Central and First-Order Maxima (θ)

We are given the distance between the central and first-order maxima (y = 0.332 m) and the distance from the grating to the wall (L = 1.00 m). We can use the right triangle relationship to find the angle θ: \(\tan \theta = \frac{y}{L}\) \(\theta = \arctan{\left(\frac{0.332 \ \text{m}}{1.00 \ \text{m}}\right)}\) \(\theta \approx 18.56^{\circ}\)
04

Calculate the Wavelength Using the Grating Equation

Now, we can use the grating equation to find the wavelength (λ): \(m \lambda = d \sin \theta\) Where m is the order of the principal maximum (m = 1 for the first-order maximum). \(\lambda = \frac{d \sin \theta}{m}\) \(\lambda = \frac{1.42 \times 10^{-6} \ \text{m} \cdot \sin(18.56^{\circ})}{1}\) \(\lambda \approx 4.54 \times 10^{-7} \text{ m}\)
05

Convert Wavelength to Nanometers

To express the wavelength in nanometers, convert the result to nanometers: \(\lambda = 4.54\times10^{-7} \text{ m}\times\frac{10^9\text{ nm}}{1\text{ m}} \approx 454\ \text{nm}\) The wavelength of the laser light is approximately \(454 \mathrm{~nm}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength Calculation
Calculating the wavelength of light in a physics problem involves understanding the relationship between diffraction gratings and light behavior. A diffraction grating consists of many parallel grooves or slits that cause the light to interfere, creating a pattern of bright and dark areas known as maxima and minima.
In this exercise, knowing the groove density (7020 grooves per centimeter) allows us to find the grating spacing, denoted by \(d\). This spacing is crucial in applying the diffraction formula. To do so:
  • First, calculate the grating separation \(d\) using \(d = \frac{1}{N}\).
  • Convert the unit of \(d\) from centimeters to meters for consistency in calculations.
Next, the angle \(\theta\) between the central and first-order maxima needs to be determined, utilizing the formula \(\tan \theta = \frac{y}{L}\). This angle, along with the spacing \(d\) and the diffraction order \(m = 1\), is then used in the diffraction grating equation:
  • \(m \lambda = d \sin \theta\)
  • Rearrange to solve for the wavelength: \(\lambda = \frac{d \sin \theta}{m}\).
Finally, convert the wavelength from meters to nanometers for a standardized format.
Laser Light
Laser light is special because it is coherent and monochromatic, meaning the light waves are in phase and consist of a single wavelength. This uniqueness makes lasers ideal for diffraction experiments.
In this exercise, the laser light hitting the diffraction grating produces a diffraction pattern. The pattern includes bright and dark bands due to interference. The bright spots, known as maxima, occur at specific angles where the light waves constructively interfere.
Lasers emit light through a process called stimulated emission, where atoms or molecules emit coherent light. Understanding these properties helps grasp why lasers and grating experiments are commonly used in optical experiments and wavelength measurements. These consistent characteristics are advantageous to display predictable diffraction patterns necessary for precise calculations.
Optics
Optics is the branch of physics that studies how light behaves and interacts with various elements like mirrors, lenses, and diffraction gratings. In this topic, concepts such as reflection, refraction, and diffraction are pivotal to understanding how light changes direction and forms patterns.
Diffraction, specifically, involves the bending of light waves around the edges of an obstacle or aperture, which can only be effectively studied using the principles of wave optics. A diffraction grating is an optical component with a periodic structure that disperses light into several beams traveling in different directions. The angle and separation of these beams are essential in optical problem-solving.
Learning about optics enables students to delve into the principles governing actions like focusing light, analyzing light spectra, and understanding phenomena such as rainbows. It bridges theoretical aspects with practical applications in areas like spectroscopy, laser technology, and even eyeglass design.
Physics Problem Solving
Solving physics problems efficiently requires a structured approach that often involves identifying known values, applying relevant equations, and verifying the results. In the context of diffraction gratings, understanding each part of the problem is vital.
First, identify and convert the given values into consistent units, as seen in our conversion from grooves per centimeter to meters. Next, use geometric relationships, such as the right triangle in this problem, to find unknown variables like angles. Finally, apply the core physics formulas, such as the grating equation, to solve for the desired quantity, ensuring each step makes logical sense.
Important tips for physics problem-solving include:
  • Break down the problem step-by-step and focus on one section at a time.
  • Check units for consistency throughout the calculation.
  • Remember to interpret the physical significance of your final result.
By practicing these skills, students can build a strong foundation for tackling various physics challenges.

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Most popular questions from this chapter

What is the largest slit width for which there are no minima when the wavelength of the incident light on the single slit is \(600 . \mathrm{nm} ?\)

In a single-slit diffraction pattern, there is a bright central maximum surrounded by successively dimmer higher-order maxima. Farther out from the central maximum, eventually no more maxima are observed. Is this because the remaining maxima are too dim? Or is there an upper limit to the number of maxima that can be observed, no matter how good the observer's eyes, for a given slit and light source?

The thermal stability of a Michelson interferometer can be improved by submerging it in water. Consider an interferometer that is submerged in water, measuring light from a monochromatic source that is in air. If the movable mirror moves a distance of \(d=0.200 \mathrm{~mm},\) exactly \(N=800\) fringes move by the screen. What is the original wavelength (in air) of the monochromatic light?

A laser beam with wavelength \(633 \mathrm{nm}\) is split into two beams by a beam splitter. One beam goes to Mirror \(1,\) a distance \(L\) from the beam splitter, and returns to the beam splitter, while the other beam goes to Mirror \(2,\) a distance \(L+\Delta x\) from the beam splitter, and returns to the same beam splitter. The beams then recombine and go to a detector together. If \(L=1.00000 \mathrm{~m}\) and \(\Delta x=1.00 \mathrm{~mm},\) which best describes the kind of interference at the detector? (Hint: To doublecheck your answer, you may need to use a formula that was originally intended for combining two beams in a different geometry, but which still is applicable here.) a) purely constructive b) purely destructive c) mostly constructive d) mostly destructive e) neither constructive nor destructive

A Newton's ring apparatus consists of a convex lens with a large radius of curvature \(R\) placed on a flat glass disc. (a) Show that the distance \(x\) from the center to the air, thickness \(d,\) and the radius of curvature \(R\) are given by \(x^{2}=2 R d\) (b) Show that the radius of nth constructive interference is given by \(x_{\mathrm{n}}=\left[\left(n+\frac{1}{2}\right) \lambda R\right]^{1 / 2} .\) (c) How many bright fringes may be seen if it is viewed by red light of wavelength 700\. \(\mathrm{nm}\) for \(R=10.0 \mathrm{~m},\) and the plane glass disc diameter is \(5.00 \mathrm{~cm} ?\)

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