/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 What is the impedance of a serie... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

What is the impedance of a series RLC circuit when the frequency of time- varying emf is set to the resonant frequency of the circuit?

Short Answer

Expert verified
Answer: At the resonant frequency of an RLC circuit, the impedance is equivalent to the resistance (R) of the resistor in the circuit.

Step by step solution

01

Calculate the resonant frequency

In a series RLC circuit, the resonant frequency (f_r) is given by the formula: f_r = \frac{1}{2\pi\sqrt{LC}} Where L is the inductance (measured in Henries) and C is the capacitance (measured in Farads).
02

Calculate the inductive reactance at resonant frequency

Inductive reactance (X_L) is the opposition offered by the inductor coil at a specific frequency (f) and is given by the formula: X_L = 2\pi f L At the resonant frequency, replace f with f_r: X_L = 2\pi f_r L
03

Calculate the capacitive reactance at resonant frequency

Capacitive reactance (X_C) is the opposition offered by the capacitor at a specific frequency (f) and is given by the formula: X_C = \frac{1}{2\pi f C} At the resonant frequency, replace f with f_r: X_C = \frac{1}{2\pi f_r C}
04

Find the net reactance at resonant frequency

The net reactance (X_net) of the RLC circuit is the difference between inductive reactance and capacitive reactance: X_net = X_L - X_C At the resonant frequency, we know that the inductive and capacitive reactance are equal: X_L = X_C Therefore, X_net = 0
05

Calculate the impedance at resonant frequency

In a series RLC circuit, the impedance (Z) is given by the formula: Z = \sqrt{R^2 + X_{net}^2} At the resonant frequency, the net reactance is zero (X_net = 0), so the impedance is solely determined by the resistor: Z = R In conclusion, at the resonant frequency of an RLC circuit, the impedance is equivalent to the resistance (R) of the resistor in the circuit.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A common configuration of wires has twisted pairs as opposed to straight, parallel wires. What is the technical advantage of using twisted pairs of wires versus straight, parallel pairs?

A 75,000 -W light bulb (yes, there are such things!) operates at \(I_{\mathrm{rms}}=200 . \mathrm{A}\) and \(V_{\mathrm{rms}}=440 . \mathrm{V}\) in a \(60.0-\mathrm{Hz} \mathrm{AC}\) circuit. Find the resistance, \(R\), and self- inductance, \(L\), of this bulb. Its capacitive reactance is negligible.

Design an RC high-pass filter that rejects \(60.0 \mathrm{~Hz}\) line noise from a circuit used in a detector. Your criteria are reduction of the amplitude of the line noise by a factor of 1000 . and total impedance at high frequencies of \(2.00 \mathrm{k} \Omega\) a) What components will you use? b) What is the frequency range of the signals that will be passed with at least \(90.0 \%\) of their amplitude?

a) A loop of wire \(5.00 \mathrm{~cm}\) in diameter is carrying a current of \(2.00 \mathrm{~A}\). What is the energy density of the magnetic field at its center? b) What current has to flow in a straight wire to produce the same energy density at a point \(4.00 \mathrm{~cm}\) from the wire?

A circuit contains a \(100 .-\Omega\) resistor, a \(0.0500-\mathrm{H}\) inductor, a \(0.400-\mu \mathrm{F}\) capacitor, and a source of time-varying emf connected in series. The time-varying emf corresponds to \(V_{\mathrm{rms}}=50.0 \mathrm{~V}\) at a frequency of \(2000 . \mathrm{Hz}\). a) Determine the current in the circuit. b) Determine the voltage drop across each component of the circuit. c) How much power is drawn from the source of emf?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.