/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 You are walking on a moving walk... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 3: Problem 61

You are walking on a moving walkway in an airport. The length of the walkway is \(59.1 \mathrm{~m}\). If your velocity relative to the walkway is \(2.35 \mathrm{~m} / \mathrm{s}\) and the walkway moves with a velocity of \(1.77 \mathrm{~m} / \mathrm{s}\), how long will it take you to reach the other end of the walkway?

Short Answer

Expert verified
Answer: Approximately 14.3 seconds.

Step by step solution

01

Identify the given information

We are given the following information: - The length of the walkway is \(59.1\,\mathrm{m}\). - The person's velocity relative to the walkway is \(2.35\,\mathrm{m/s}\). - The walkway's velocity is \(1.77\,\mathrm{m/s}\).
02

Calculate the overall velocity

The overall velocity is the sum of the person's velocity relative to the walkway and the walkway's velocity. Therefore, we can denote the overall velocity, \(v\), as follows: \(v = 2.35\,\mathrm{m/s} + 1.77\,\mathrm{m/s}\) Now we can calculate the overall velocity: \(v = 4.12\,\mathrm{m/s}\)
03

Determine the time

To find the time it takes to reach the other end of the walkway, we will use the formula for distance, which is: \(t = \frac{d}{v}\) Here, \(t\) is the time, \(d\) is the distance (the length of the walkway), and \(v\) is the overall velocity. Plugging in the given values, we have: \(t = \frac{59.1\,\mathrm{m}}{4.12\,\mathrm{m/s}}\) Now we can calculate the time: \(t \approx 14.3\,\mathrm{s}\)
04

State the answer

It will take approximately \(14.3\) seconds for the person to reach the other end of the moving walkway.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Your friend's car is parked on a cliff overlooking the ocean on an incline that makes an angle of \(17.0^{\circ}\) below the horizontal. The brakes fail, and the car rolls from rest down the incline for a distance of \(29.0 \mathrm{~m}\) to the edge of the cliff, which is \(55.0 \mathrm{~m}\) above the ocean, and, unfortunately, continues over the edge and lands in the ocean. a) Find the car's position relative to the base of the cliff when the car lands in the ocean. b) Find the length of time the car is in the air.

A golf ball is hit with an initial angle of \(35.5^{\circ}\) with respect to the horizontal and an initial velocity of \(83.3 \mathrm{mph}\). It lands a distance of \(86.8 \mathrm{~m}\) away from where it was hit. \(\mathrm{By}\) how much did the effects of wind resistance, spin, and so forth reduce the range of the golf ball from the ideal value?

A projectile is launched at an angle of \(45^{\circ}\) above the horizontal. What is the ratio of its horizontal range to its maximum height? How does the answer change if the initial speed of the projectile is doubled?

A rabbit runs in a garden such that the \(x\) - and \(y\) components of its displacement as function of times are given by \(x(t)=-0.45 t^{2}-6.5 t+25\) and \(y(t)=0.35 t^{2}+8.3 t+34 .\) (Both \(x\) and \(y\) are in meters and \(t\) is in seconds.) a) Calculate the rabbit's position (magnitude and direction) at \(t=10 \mathrm{~s}\) b) Calculate the rabbit's velocity at \(t=10 \mathrm{~s}\). c) Determine the acceleration vector at \(t=10 \mathrm{~s}\).

In a three-dimensional motion, the \(x-, y-\), and \(z\) coordinates of the object as a function of time are given by \(x(t)=\frac{\sqrt{2}}{2} t, \quad y(t)=\frac{\sqrt{2}}{2} t,\) and \(z(t)=-4.9 t^{2}+\sqrt{3} t\) Describe the motion and the trajectory of the object in an \(x y z\) coordinate system.
See all solutions

Recommended explanations on Physics Textbooks

Mechanics and Materials

Read Explanation

Wave Optics

Read Explanation

Oscillations

Read Explanation

Further Mechanics and Thermal Physics

Read Explanation

Space Physics

Read Explanation

Quantum Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.