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Why do light bulbs typically burn out just as they are turned on rather than while they are lit?

Short Answer

Expert verified
Answer: Light bulbs typically burn out just as they are turned on due to the combination of increased electrical resistance, rapid thermal expansion, and the stress on the weakened or brittle points of the filament at the turn-on stage.

Step by step solution

01

Understand the basic structure of a light bulb

A light bulb consists of a thin filament, often made of tungsten, enclosed in a glass bulb filled with inert gas. When an electric current passes through the filament, it heats up and emits light as a result.
02

Understand electrical resistance in a filament

As the filament heats up due to the electrical current passing through it, its resistance increases. This is due to the increase in the temperature resulting in an increased agitation of the atoms and electrons in the filament. The increased resistance means that more energy is converted into heat, making the filament even hotter, and ultimately resulting in the filament glowing and emitting light.
03

Understand thermal expansion

When the filament heats up, it undergoes thermal expansion. This means that the material expands as its temperature increases. When the material cools down again, it contracts. This expansion and contraction can eventually lead to the material becoming weakened or brittle, particularly at the points where the filament is attached to its supports.
04

Understand turn-on moment for light bulbs

When a light bulb is turned on, there is a sudden surge of electrical current passing through the filament that rapidly increases its temperature. This results in a sharp increase in electrical resistance and a corresponding increase in temperature, causing rapid thermal expansion.
05

Identify the reason for light bulbs burning out at turn-on

The rapid thermal expansion that occurs at the turn-on moment causes stress on the already weakened or brittle points of the filament. This additional stress can cause the filament to break, consequently resulting in the light bulb burning out. Since this process is more likely to occur when the filament is rapidly heated during the turn-on stage, light bulbs typically burn out just as they are turned on rather than while they are lit. In conclusion, the reason why light bulbs typically burn out just as they are turned on, rather than while they are lit, is due to the combination of increased electrical resistance, rapid thermal expansion, and the stress on the weakened or brittle points of the filament at the turn-on stage.

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Most popular questions from this chapter

The most common material used for sandpaper, silicon carbide, is also widely used in electrical applications. One common device is a tubular resistor made of a special grade of silicon carbide called carborundum. A particular carborundum resistor (see the figure) consists of a thick-walled cylindrical shell (a pipe) of inner radius \(a=\) \(1.50 \mathrm{~cm},\) outer radius \(b=2.50 \mathrm{~cm},\) and length \(L=60.0 \mathrm{~cm} .\) The resistance of this carborundum resistor at \(20 .{ }^{\circ} \mathrm{C}\) is \(1.00 \Omega\). a) Calculate the resistivity of carborundum at room temperature. Compare this to the resistivities of the most commonly used conductors (copper, aluminum, and silver). b) Carborundum has a high temperature coefficient of resistivity: \(\alpha=2.14 \cdot 10^{-3} \mathrm{~K}^{-1} .\) If, in a particular application, the carborundum resistor heats up to \(300 .{ }^{\circ} \mathrm{C},\) what is the percentage change in its resistance between room temperature \(\left(20 .{ }^{\circ} \mathrm{C}\right)\) and this operating temperature?

A current of \(0.123 \mathrm{~mA}\) flows in a silver wire whose cross-sectional area is \(0.923 \mathrm{~mm}^{2}\) a) Find the density of electrons in the wire, assuming that there is one conduction electron per silver atom. b) Find the current density in the wire assuming that the current is uniform. c) Find the electron's drift speed.

Two cylindrical wires, 1 and \(2,\) made of the same material, have the same resistance. If the length of wire 2 is twice that of wire 1 , what is the ratio of their cross-sectional areas, \(A_{1}\) and \(A_{2} ?\) a) \(A_{1} / A_{2}=2\) c) \(\mathrm{A}_{1} / \mathrm{A}_{2}=0.5\) b) \(A_{1} / A_{2}=4\) d) \(A_{1} / A_{2}=0.25\)

What would happen to the drift velocity of electrons in a wire if the resistance due to collisions between the electrons and the atoms in the crystal lattice of the metal disappeared?

Before bendable tungsten filaments were developed, Thomas Edison used carbon filaments in his light bulbs. Though carbon has a very high melting temperature \(\left(3599^{\circ} \mathrm{C}\right)\) its sublimation rate is high at high temperatures. So carbonfilament bulbs were kept at lower temperatures, thereby rendering them dimmer than later tungsten-based bulbs. A typical carbon-filament bulb requires an average power of \(40 \mathrm{~W}\), when 110 volts is applied across it, and has a filament temperature of \(1800^{\circ} \mathrm{C}\). Carbon, unlike copper, has a negative temperature coefficient of resistivity: \(\alpha=-0.0005^{\circ} \mathrm{C}^{-1}\) Calculate the resistance at room temperature \(\left(20^{\circ} \mathrm{C}\right)\) of this carbon filament.

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