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Chapter 2: Problem 56

An airplane starts from rest and accelerates at \(12.1 \mathrm{~m} / \mathrm{s}^{2}\). What is its speed at the end of a \(500 .-\mathrm{m}\) runway?

Short Answer

Expert verified
Answer: The speed of the airplane at the end of the 500m runway is approximately 110 m/s.

Step by step solution

01

Write down the given values

We know the following values: - Initial velocity (u) = 0 m/s - Acceleration (a) = 12.1 m/s虏 - Distance (s) = 500 m
02

Use the equation of motion

Now, we will use the equation v虏 = u虏 + 2as to find the final velocity (v).
03

Substitute the values and solve for v

Substitute the given values into the equation: v虏 = (0)虏 + 2(12.1)(500) Calculating the result: v虏 = 0 + 2(12.1)(500) v虏 = 12100 Now, find the square root of 12100 to get the final velocity (v): v = 鈭�12100 v 鈮� 110 m/s
04

State the final answer

The speed of the airplane at the end of the 500m runway is approximately 110 m/s.

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