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Chapter 17: Problem 22

Express each of the following temperatures in degrees Celsius and in kelvins. a) \(-19^{\circ} \mathrm{F}\) b) \(98.6^{\circ} \mathrm{F}\) c) \(52^{\circ} \mathrm{F}\)

Short Answer

Expert verified
Answer: The approximate Celsius and Kelvin equivalents are: - For -19掳F, it is about -28.33掳C and 244.82 K. - For 98.6掳F, it is about 37掳C and 310.15 K. - For 52掳F, it is about 11.11掳C and 284.26 K.

Step by step solution

01

Convert -19掳F to Celsius and Kelvin

a) To convert -19掳F to degrees Celsius, we'll use the conversion formula: \(C = \frac{5}{9} (-19 - 32)\) \(C = \frac{5}{9} (-51)\) C 鈮� -28.33 掳C Now, to convert -28.33 掳C to kelvins, we'll use the conversion formula: K = -28.33 + 273.15 K 鈮� 244.82 K The temperature -19掳F is approximately -28.33 掳C and 244.82 K.
02

Convert 98.6掳F to Celsius and Kelvin

b) To convert 98.6掳F to degrees Celsius, we'll use the conversion formula: \(C = \frac{5}{9} (98.6 - 32)\) C 鈮� 37 掳C Now, to convert 37掳C to kelvins, we'll use the conversion formula: K = 37 + 273.15 K = 310.15 K The temperature 98.6掳F is approximately 37 掳C and 310.15 K.
03

Convert 52掳F to Celsius and Kelvin

c) To convert 52掳F to degrees Celsius, we'll use the conversion formula: \(C = \frac{5}{9} (52 - 32)\) \(C = \frac{5}{9} (20)\) C 鈮� 11.11 掳C Now, to convert 11.11 掳C to kelvins, we'll use the conversion formula: K = 11.11 + 273.15 K 鈮� 284.26 K The temperature 52掳F is approximately 11.11 掳C and 284.26 K.

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Most popular questions from this chapter

a) Suppose a bimetallic strip is constructed of copper and steel strips of thickness \(1.0 \mathrm{~mm}\) and length \(25 \mathrm{~mm},\) and the temperature of the strip is reduced by \(5.0 \mathrm{~K}\). Determine the radius of curvature of the cooled strip (the radius of curvature of the interface between the two strips). b) If the strip is \(25 \mathrm{~mm}\) long, how far is the maximum deviation of the strip from the straight orientation?

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