/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 A rocket in deep space (zero gra... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A rocket in deep space (zero gravity) accelerates by firing hot gas out of its thrusters. Does the rocket constitute a closed system? Explain.

Short Answer

Expert verified
No, the rocket does not constitute a closed system as it is releasing matter (hot gas) into its surroundings. A closed system only allows the exchange of energy, not matter.

Step by step solution

01

Understanding the Concept

Firstly, a closed system is a system that doesn't allow matter to exchange with its surroundings. It only allows energy to be transferred. It's necessary to understand this concept fully before applying it to the given scenario.
02

Analyzing The Rocket Scenario

The rocket in this instance is releasing hot gas into space. This means matter (the hot gas) is being expelled from the rocket and is being transferred to its surroundings (space).
03

Conclusion

Applying the definition of a closed system to the analyzed rocket scenario, it's evident that the rocket is not a closed system. This is because it is releasing matter (hot gas) into its surroundings which violates the definition of a closed system that doesn't allow transfer of matter to its surroundings.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Thermodynamics in Physics
Thermodynamics is a branch of physics that deals with the relationships between heat and other forms of energy. It is vital in explaining how thermal energy is converted to and from other forms of energy and how heat affects matter. The study of thermodynamics revolves around the laws that govern these energy transformations and is essential in a wide range of scientific and engineering applications.

In the context of our rocket, thermodynamics comes into play when we consider how the rocket's fuel is used to generate the hot gas that propels it through space. The fuel's stored chemical energy is converted into thermal energy, which then expands and escapes as hot gas, propelling the rocket forward. This process is guided by the first law of thermodynamics, also known as the law of energy conservation, which states that energy cannot be created or destroyed, only converted from one form to another. In the rocket's case, the chemical energy of the fuel is ultimately converted into kinetic energy as the rocket accelerates.
Conservation of Mass and its Relevance
The conservation of mass is a fundamental concept in physics and chemistry stating that mass cannot be created or destroyed in an isolated system. Throughout any process, the mass of the system will remain constant over time. This principle is closely related to the first law of thermodynamics but specifically pertains to the mass aspect of a system.

In the example of the rocket in space, when the rocket burns fuel and expels gas, the total mass of the rocket and its expelled gas remains constant. The mass of the fuel decreased inside the rocket, is equal to the mass of the gas expelled. It's important to clarify that a closed system in terms of mass means no mass is exchanged with the environment. Here the rocket clearly demonstrates the conservation of mass principle; yet it does not constitute a closed system, because it does exchange mass with its surroundings by emitting gas.
Rocket Propulsion and its Underlying Principles
Rocket propulsion is a clear illustration of Newton's third law of motion, which states that for every action, there's an equal and opposite reaction. When a rocket expels hot gas at high speed (the action), it produces a thrust force in the opposite direction (the reaction), which propels the rocket forward.

The effectiveness of rocket propulsion depends on several factors, including the mass and speed of the expelled gas—this is known as the momentum principle of rocket propulsion. Rockets are designed to achieve high velocity exhaust which, through the momentum exchanged, propels the craft.

Efficiency in Rocket Propulsion

For a rocket to be efficient, the chemicals used (typically as propellants) should react in such a way that produces maximal energy and leads to the expulsion of gas at supersonic speeds, thus maximizing the thrust according to the momentum equation \( F = \frac{dp}{dt} \), where \( F \) is the thrust force, and \( \frac{dp}{dt} \) is the rate of change of momentum.

Rocket propulsion in a zero-gravity environment such as space is particularly fascinating because, in the absence of external forces, the propulsion system must work in a vacuum and against no atmospheric resistance, which is very different from terrestrial conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two particles of masses \(m_{1}\) and \(m_{2}\) move uniformly in different circles of radii \(R_{1}\) and \(R_{2}\) about the origin in the \(x, y\) -plane. The coordinates of the two particles in meters are given as follows \((z=0 \text { for both). Here } t\) is in seconds: \(x_{1}(t)=4 \cos (2 t)\) \(y_{1}(t)=4 \sin (2 t)\) \(x_{2}(t)=2 \cos \left(3 t-\frac{\pi}{2}\right)\) \(y_{2}(t)=2 \sin \left(3 t-\frac{\pi}{2}\right)\) a. Find the radii of the circles of motion of both particles. b. Find the \(x\) - and \(y\) -coordinates of the center of mass. c. Decide if the center of mass moves in a circle by plotting its trajectory.

It is possible for the velocity of a rocket to be greater than the exhaust velocity of the gases it ejects. When that is the case, the gas velocity and gas momentum are in the same direction as that of the rocket. How is the rocket still able to obtain thrust by ejecting the gases?

A 200-kg rocket in deep space moves with a velocity of \((121 \mathrm{m} / \mathrm{s}) \hat{\mathbf{i}}+(38.0 \mathrm{m} / \mathrm{s}) \hat{\mathbf{j}}\). Suddenly, it explodes into three pieces, with the first \((78\) kg) moving at \(-(321 \mathrm{m} / \mathrm{s}) \hat{\mathbf{i}}+(228 \mathrm{m} / \mathrm{s}) \hat{\mathbf{j}} \quad\) and the second \((56 \mathrm{kg})\) moving at \((16.0 \mathrm{m} / \mathrm{s}) \hat{\mathbf{i}}-(88.0 \mathrm{m} / \mathrm{s}) \hat{\mathbf{j}}\). Find the velocity of the third piece.

Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small and dense by scattering helium-4 nuclei from gold-197 nuclei. The energy of the incoming helium nucleus was \(8.00 \times 10^{-13} \mathrm{J},\) and the masses of the helium and gold nuclei were \(6.68 \times 10^{-27} \mathrm{kg}\) and \(3.29 \times 10^{-25} \mathrm{kg},\) respectively (note that their mass ratio is 4 to 197 ). a. If a helium nucleus scatters to an angle of \(120^{\circ}\) during an elastic collision with a gold nucleus, calculate the helium nucleus's final speed and the final velocity (magnitude and direction) of the gold nucleus. b. What is the final kinetic energy of the helium nucleus?

Calculate the final speed of a 110 -kg rugby player who is initially running at \(8.00 \mathrm{m} / \mathrm{s}\) but collides head-on with a padded goalpost and experiences a backward force of \(1.76 \times 10^{4} \mathrm{N}\) for \(5.50 \times 10^{-2} \mathrm{s}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.