/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Someone drops a \(50-\mathrm{g}\... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Someone drops a \(50-\mathrm{g}\) pebble off of a docked cruise ship, \(70.0 \mathrm{m}\) from the water line. A person on a dock \(3.0 \mathrm{m}\) from the water line holds out a net to catch the pebble. (a) How much work is done on the pebble by gravity during the drop? (b) What is the change in the gravitational potential energy during the drop? If the gravitational potential energy is zero at the water line, what is the gravitational potential energy (c) when the pebble is dropped? (d) When it reaches the net? What if the gravitational potential energy was 30.0 Joules at water level? (e) Find the answers to the same questions in (c) and (d).

Short Answer

Expert verified
(a) The work done by gravity on the pebble during the drop is \(34.285\,\mathrm{J}\). (b) The change in gravitational potential energy during the drop is also \(34.285\,\mathrm{J}\). (c) The gravitational potential energy when the pebble is dropped is \(34.285\,\mathrm{J}\). (d) The gravitational potential energy when the pebble reaches the net is \(1.4705\,\mathrm{J}\). (e) With the given initial potential energy of \(30.0\,\mathrm{J}\), the gravitational potential energy when the pebble is dropped is \(64.285\,\mathrm{J}\), and when it reaches the net, it is \(31.4705\,\mathrm{J}\).

Step by step solution

01

Find the work done by gravity on the pebble

To find the work done by gravity on the pebble during the drop, we can use the formula: \( W = mgh \) where \(m = 50\,\mathrm{g} = 0.05\,\mathrm{kg}\) (Convert the mass from grams to kg), \(g = 9.81\,\mathrm{m/s^2}\) (acceleration due to gravity), \(h = 70\,\mathrm{m}\) (height above the waterline). Substituting the values, we have: \( W = (0.05\,\mathrm{kg})(9.81\,\mathrm{m/s^2})(70\,\mathrm{m})\) \( W = 34.285\,\mathrm{J}\) The work done by gravity on the pebble during the drop is \(34.285\,\mathrm{J}\).
02

Find the change in the gravitational potential energy

To find the change in gravitational potential energy during the drop, we will use the same formula as in Step 1: \( \Delta U = mgh \) Since the formula is the same, the change in gravitational potential energy during the drop is also \(34.285\,\mathrm{J}\).
03

Find the gravitational potential energy when the pebble is dropped

Since in this part it's mentioned that the gravitational potential energy is zero at the waterline, that means when the pebble is dropped, the gravitational potential energy is: \( U_1 = mgh \) As we have calculated previously, the gravitational potential energy when the pebble is dropped is \(34.285\,\mathrm{J}\).
04

Find the gravitational potential energy when it reaches the net

To find the gravitational potential energy when the pebble reaches the net, we need to use the height from the waterline to the person on the dock holding the net, which is \(3\,\mathrm{m}\). This time, the gravitational potential energy becomes: \( U_2 = mg(3\,\mathrm{m})\) Substituting the values, we have: \( U_2 = (0.05\,\mathrm{kg})(9.81\,\mathrm{m/s^2})(3\,\mathrm{m}) \) \( U_2 = 1.4705\,\mathrm{J}\) The gravitational potential energy when the pebble reaches the net is \(1.4705\,\mathrm{J}\).
05

Calculate gravitational potential energy with the given initial potential energy

The initial potential energy is given as \(30.0\,\mathrm{J}\) at water level. Therefore, we will add this value to the potential energies calculated in Steps 3 and 4. For the gravitational potential energy when the pebble is dropped, we have: \( U'_1 = U_1 + 30.0\,\mathrm{J} = 34.285\,\mathrm{J} + 30.0\,\mathrm{J} = 64.285\,\mathrm{J}\) For the gravitational potential energy when the pebble reaches the net, we have: \( U'_2 = U_2 + 30.0\,\mathrm{J} = 1.4705\,\mathrm{J} + 30.0\,\mathrm{J} = 31.4705\,\mathrm{J}\) With the given initial potential energy of \(30.0\,\mathrm{J}\), the gravitational potential energy when the pebble is dropped is \(64.285\,\mathrm{J}\), and when it reaches the net, it is \(31.4705\,\mathrm{J}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Potential Energy
Gravitational potential energy is the energy an object possesses because of its position in a gravitational field. It is dependent on three main factors: the object's mass (\( m \)), the height (\( h \)) of the object above a reference level, and the acceleration due to gravity (\( g \)), which is approximately \( 9.81 \,\mathrm{m/s^2} \) on Earth. This potential energy is mathematical expressed as \( U = mgh \).

For instance, in the problem we are exploring, when the pebble is held \( 70 \) meters above the waterline, its gravitational potential energy can be calculated. When calculating or comparing gravitational potential energy, it's crucial to set a baseline, or point of zero potential energy. In our example, the waterline is initially set as this zero point.

Understanding these concepts is essential, not only for calculating the gravitational potential energy at various positions but also for comprehending how energy transformations occur during a free fall.
Work Done by Gravity
Work done by gravity involves the energy transferred to or from an object by the gravitational force as it moves a certain distance. It is closely related to gravitational potential energy because any change in gravitational potential energy corresponds to work being done by gravity. The formula to calculate this work is similar to that for gravitational potential energy: \( W = mgh \). This signifies that the work done by gravity is essentially the energy shift as an object moves from one point to another vertically.

In our exercise, the pebble falls from a height of \( 70 \) meters to a net located \( 3 \) meters above the water. By calculating \( mgh \) for this height difference, we find that the work done by gravity is \( 34.285 \, \mathrm{J} \). This represents the energy gravity has transferred to the pebble during its descent, emphasizing the powerful role gravity plays in influencing motion and energy distribution.
Physics Problems
Solving physics problems, like the one involving the falling pebble, requires understanding the underlying principles of physics concepts such as gravitational potential energy and work.

A typical problem-solving approach includes identifying:
  • All given data, like the pebble's mass and height.
  • The formulas applicable to the problem, such as \( W = mgh \).
  • The conditions, like what is defined as zero potential energy.
Developing a systematic approach to physics problems helps in breaking down complex concepts into manageable calculations, ensuring a step-by-step resolution. Most importantly, interpreting the physical meaning of the results is key, as seen when calculating how energy changes and is impacted by various positions and influences. Practicing these components strengthens proficiency not just in dealing with numbers but in grasping how fundamental forces like gravity practically operate in our world.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Neglecting air resistance, how much would I have to raise the vertical height if I wanted to double the impact speed of a falling object?

A mysterious constant force of 10 \(\mathrm{N}\) acts horizontally on everything. The direction of the force is found to be always pointed toward a wall in a big hall. Find the potential energy of a particle due to this force when it is at a distance \(x\) from the wall, assuming the potential energy at the wall to be zero.

Assume that the force of a bow on an arrow behaves like the spring force. In aiming the arrow, an archer pulls the bow back \(50 \mathrm{cm}\) and holds it in position with a force of 150 N. If the mass of the arrow is \(50 \mathrm{g}\) and the "spring" is massless, what is the speed of the arrow immediately after it leaves the bow?

A skier starts from rest and slides downhill. What will be the speed of the skier if he drops by 20 meters in vertical height? Ignore any air resistance (which will, in reality, be quite a lot), and any friction between the skis and the snow.

A couple of soccer balls of equal mass are kicked off the ground at the same speed but at different angles. Soccer ball A is kicked off at an angle slightly above the horizontal, whereas ball \(B\) is kicked slightly below the vertical. How do each of the following compare for ball \(A\) and ball \(B\) ? (a) The initial kinetic energy and (b) the change in gravitational potential energy from the ground to the highest point? If the energy in part (a) differs from part (b), explain why there is a difference between the two energies.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.