/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 A roller coaster car starts from... [FREE SOLUTION] | 91Ó°ÊÓ

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A roller coaster car starts from rest at the top of a track \(30.0 \mathrm{m}\) long and inclined at \(20.0^{\circ}\) to the horizontal. Assume that friction can be ignored. (a) What is the acceleration of the car? (b) How much time elapses before it reaches the bottom of the track?

Short Answer

Expert verified
The acceleration of the roller coaster car down the inclined track is approximately \(3.35 \, m/s^2\) and the time it takes for the car to reach the bottom of the inclined track is approximately \(3.81 \, s\).

Step by step solution

01

Calculate the acceleration

First, we need to find the acceleration of the car down the inclined track. We can use the formula for acceleration due to gravity on an inclined plane: \(a = g \sin(\theta)\). Using \(g = 9.80 \, m/s^2\) and \(\theta = 20^{\circ}\), we get: \(a = (9.80 \, m/s^2) \sin(20^{\circ})\) \(a \approx 3.35 \, m/s^2\) The acceleration of the car down the inclined track is approximately \(3.35 \, m/s^2\).
02

Calculate the final velocity

Now, we'll use the kinematic equation for velocity with constant acceleration: \(v_f^2 = v_i^2 + 2a(x_f - x_i)\). Since the car starts from rest, we have \(v_i = 0\). Let \(x_i = 0 \, m\) and \(x_f = 30.0 \, m\). We already calculated the acceleration, \(a = 3.35 \, m/s^2\). Plugging these values, we get: \(v_f^2 = (0)^2 + 2(3.35 \, m/s^2)(30.0 \, m)\) \(v_f^2 \approx 201.0 \, m^2/s^2\) \(v_f \approx 14.18 \, m/s\) The final velocity of the car at the bottom of the inclined track is approximately \(14.18 \, m/s\).
03

Calculate the time to reach the bottom

Finally, we'll use the kinematic equation for displacement with constant acceleration: \(x_f - x_i = v_i t + \frac{1}{2}at^2\). Since the car starts from rest, we have \(v_i = 0\). Let \(x_i = 0 \, m\) and \(x_f = 30.0 \, m\). We already calculated the acceleration, \(a = 3.35 \, m/s^2\). We can rewrite the equation as: \(t = \sqrt{\frac{2(x_f - x_i)}{a}}\) Plugging the values, we get: \(t = \sqrt{\frac{2(30.0 \, m)}{3.35 \, m/s^2}}\) \(t \approx 3.81 \, s\) The time it takes for the car to reach the bottom of the inclined track is approximately \(3.81 \, s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Due to Gravity
Understanding the acceleration due to gravity is fundamental when studying mechanics and is especially crucial when examining movement along an inclined plane. Imagine dropping an object from a certain height; it will accelerate towards Earth's surface due to gravity. This acceleration, denoted by the letter 'g', is approximately \(9.80 \, m/s^2\) on Earth's surface.

This value can be thought of as the acceleration experienced by an object in free fall, under the influence of gravity alone, without any air resistance. In physics problems involving inclined planes, gravity's effect is modified because the object is not in free fall, but is instead moving along a slope.

To calculate the actual acceleration of an object sliding down an inclined plane, you will need to adjust the acceleration due to gravity using the sine of the angle of inclination, as shown in our roller coaster example. This adjustment reflects the fact that only a portion of gravity's force is pulling the object along the plane's surface, with the rest acting perpendicularly and thus not influencing horizontal displacement.
Kinematic Equations
Kinematic equations allow us to describe the motion of objects using mathematical formulas. These equations come into play when we talk about variables such as displacement (\(x\)), initial velocity (\(v_i\)), final velocity (\(v_f\)), acceleration (\(a\)), and time (\(t\)). These five key variables are related in a way that allows us to predict an object's motion when some of the variables are known.

In our roller coaster example, we used the kinematic equation \(v_f^2 = v_i^2 + 2a(x_f - x_i)\) to find the final velocity of the car at the bottom of the track. This equation is particularly useful when the time variable is not needed.

Common Kinematic Equations

  • \(v_f = v_i + at\)
  • \(x_f - x_i = v_i t + \frac{1}{2}at^2\)
  • \(x_f - x_i = \frac{v_i + v_f}{2}t\)
  • \(v_f^2 = v_i^2 + 2a(x_f - x_i)\)

Each of these equations applies to motion with constant acceleration, so in cases where acceleration varies, they must be used with caution or adapted accordingly.
Inclined Plane Calculations
Calculating the motion of objects on inclined planes is a common challenge in physics. Inclined planes are surfaces tilted at an angle to the horizontal, and they can drastically alter the dynamics of motion compared to flat surfaces.

In our roller coaster example, we first estimated the acceleration due to gravity component along the inclined plane using trigonometry, applying the sine function to the plane's angle of inclination. Following this, we used kinematic equations adapted for an inclined plane scenario, allowing us to find how long it would take for the object to reach the bottom.

Important Considerations for Inclined Planes:

  • The angle of the plane affects the acceleration and displacement of the object.
  • Friction can significantly impact the object's movement but is often omitted for simplified calculations.
  • Normal force acts perpendicular to the plane, contrasting with the gravity force that must be resolved into parallel and perpendicular components.

When working through inclined plane problems, you must always resolve forces into components parallel and perpendicular to the plane. This process involves a good understanding of trigonometry and vector decomposition, which are the keys to mastering physics problems involving inclined planes.

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