/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 What force does a trampoline hav... [FREE SOLUTION] | 91Ó°ÊÓ

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What force does a trampoline have to apply to Jennifer, a 45.0-kg gymnast, to accelerate her straight up at \(7.50 \mathrm{m} / \mathrm{s}^{2}\) ? The answer is independent of the velocity of the gymnast-she can be moving up or down or can be instantly stationary.

Short Answer

Expert verified
The force that the trampoline has to apply to Jennifer to accelerate her straight up at \(7.50 \,m/s^2\) is approximately \(778.95 \, N\).

Step by step solution

01

Calculate the gravitational force

First, we need to calculate the gravitational force acting on Jennifer. We can do this using the formula: F_gravity = m * g, where m represents her mass (45.0 kg), and g represents the acceleration due to gravity (9.81 m/s²). F_gravity = 45.0 kg × 9.81 m/s²
02

Calculate the net upward force

Next, we have to find out the net upward force, F_net, required for Jennifer to accelerate at 7.50 m/s². We can do this using the formula: F_net = m * a, where m is Jennifer's mass (45.0 kg) and a is her upward acceleration (7.50 m/s²). F_net = 45.0 kg × 7.50 m/s²
03

Determine the total force exerted by the trampoline

Finally, we need to determine the total force, F_total, exerted by the trampoline, which must overcome both the gravitational force and produce the net upward force required to accelerate Jennifer at 7.50 m/s². We can find F_total by adding F_gravity and F_net. F_total = F_gravity + F_net Now we will calculate the values.
04

Calculate F_gravity

Using the formula from step 1, we can calculate the gravitational force on Jennifer: F_gravity = 45.0 kg × 9.81 m/s² = 441.45 N (Newtons)
05

Calculate F_net

Now let's calculate the net upward force required to accelerate Jennifer at 7.50 m/s² using the formula from step 2: F_net = 45.0 kg × 7.50 m/s² = 337.50 N (Newtons)
06

Calculate F_total

Finally, let's determine the total force exerted by the trampoline using the calculation from step 3 by adding F_gravity and F_net: F_total = 441.45 N + 337.50 N = 778.95 N (Newtons) So, the force that the trampoline has to apply to Jennifer to accelerate her straight up at 7.50 m/s² is approximately 778.95 N.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force Calculation
When dealing with physics problems involving gravity, it's crucial to understand how to calculate the gravitational force. This force is a pull that the Earth exerts on any object with mass. The calculation is straightforward: it involves multiplying the mass of an object by the acceleration due to gravity.

For Jennifer, the gymnast on the trampoline who weighs 45.0 kg, we apply this concept using the formula:
\[F_{gravity} = m \times g\]
Where \(m\) represents mass and \(g\) is the acceleration due to gravity, which on Earth is approximately \(9.81 \text{m/s}^2\). Hence, her gravitational force is:
\[F_{gravity} = 45.0 \text{kg} \times 9.81 \text{m/s}^2 = 441.45 \text{N}\]
This force acts downward, pulling Jennifer towards the center of the Earth. In our trampoline scenario, any upward movement must counteract this gravitational force.
Net Force Calculation
The net force is the cumulative effect of all forces acting on an object, which leads to the object's acceleration. In the context of trampoline physics, we focus on the net upward force.The net force required to accelerate an object can also be determined via Newton's second law, but it's specifically about understanding the resulting force after all individual forces are combined (including gravitational force).

For Jennifer to achieve an upward acceleration of \(7.50 \text{m/s}^2\), we calculate her required net force by using the formula: \[F_{net} = m \times a\]
Here, \(m\) is again her mass, and \(a\) is her acceleration. Thus, the net upward force is:
\[F_{net} = 45.0 \text{kg} \times 7.50 \text{m/s}^2 = 337.50 \text{N}\]
This calculation tells us that to move Jennifer upwards against gravity with the specified acceleration, a net upward force of 337.50 N is necessary.
Acceleration
Acceleration is the rate at which an object's velocity changes over time, and it's a vector quantity, which means it has both magnitude and direction. In our trampoline example, Jennifer has an upward acceleration when bouncing. This upward acceleration is the change in her velocity as she speeds up moving away from the trampoline surface.

To achieve the given acceleration of \(7.50 \text{m/s}^2\), the trampoline must exert a force on Jennifer that's not only enough to counteract her weight (caused by gravitational force) but also powerful enough to speed her up. To calculate this, you use the established formula: \[a = \frac{F_{net}}{m}\]
However, this time, we rearrange the formula to calculate the net force since we already have the desired acceleration and mass. Acceleration is a key factor in determining how powerful the trampoline's response needs to be.
Newton's Second Law
Newton's second law of motion underpins much of classical mechanics and is fundamental when assessing the forces on Jennifer as she bounces on a trampoline. It states that the force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma).

This law explains the relationship between an object's mass, the net force applied to it, and the subsequent acceleration. For Jennifer to ascend with an acceleration of \(7.50 \text{m/s}^2\), we see Newton's second law in action as the trampoline exerts a force to overcome her gravitational pull and provide additional force for her upward movement. This force is quantified by summing the gravitational pull and the force needed for her acceleration, leading to the total force the trampoline must apply:
\[F_{total} = F_{gravity} + F_{net} = 441.45 \text{N} + 337.50 \text{N} = 778.95 \text{N}\]
Newton's second law is the cornerstone for analyzing the motion of objects under the influence of various forces, and it is perfectly illustrated in the physics of trampolining.

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Most popular questions from this chapter

A 10.0 -kg mass hangs from a spring that has the spring constant \(535 \mathrm{N} / \mathrm{m}\). Find the position of the end of the spring away from its rest position. (Use \(g=9.80 \mathrm{m} / \mathrm{s}^{2}\).)

Astronauts in orbit are apparently weightless. This means that a clever method of measuring the mass of astronauts is needed to monitor their mass gains or losses, and adjust their diet. One way to do this is to exert a known force on an astronaut and measure the acceleration produced. Suppose a net external force of \(50.0 \mathrm{N}\) is exerted, and an astronaut's acceleration is measured to be \(0.893 \mathrm{m} / \mathrm{s}^{2} .\) (a) Calculate her mass. (b) By exerting a force on the astronaut, the vehicle in which she orbits experiences an equal and opposite force. Use this knowledge to find an equation for the acceleration of the system (astronaut and spaceship) that would be measured by a nearby observer. (c) Discuss how this would affect the measurement of the astronaut's acceleration. Propose a method by which recoil of the vehicle is avoided.

Two forces of \(\overrightarrow{\mathbf{F}}_{1}=\frac{75.0}{\sqrt{2}}(\hat{\mathbf{i}}-\hat{\mathbf{j}}) \mathrm{N} \quad\) and \(\overrightarrow{\mathbf{F}}_{2}=\frac{150.0}{\sqrt{2}}(\hat{\mathbf{i}}-\hat{\mathbf{j}}) \mathrm{N}\) act on an object. Find the third force \(\overrightarrow{\mathbf{F}}_{3}\) that is needed to balance the first two forces.

(a) What net external force is exerted on a \(1100.0-\mathrm{kg}\) artillery shell fired from a battleship if the shell is accelerated at \(2.40 \times 10^{4} \mathrm{m} / \mathrm{s}^{2} ?\) (b) What is the magnitude of the force exerted on the ship by the artillery shell, and why?

Two forces are applied to a 5.0 -kg object, and it accelerates at a rate of \(2.0 \mathrm{m} / \mathrm{s}^{2}\) in the positive \(y\) -direction. If one of the forces acts in the positive \(x\) -direction with magnitude \(12.0 \mathrm{N},\) find the magnitude of the other force.

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