/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 94 On planet Arcon, the maximum hor... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

On planet Arcon, the maximum horizontal range of a projectile launched at \(10 \mathrm{m} / \mathrm{s}\) is \(20 \mathrm{m}\). What is the acceleration of gravity on this planet?

Short Answer

Expert verified
The acceleration due to gravity on planet Arcon is \(5 \frac{m}{s^2}\).

Step by step solution

01

Write down the given information

The initial velocity (v) is given as \(10\frac{m}{s}\), and the maximum horizontal range (R) is given as 20m. We will use these values along with the formula for horizontal range mentioned above to solve for the acceleration due to gravity (g).
02

Plug in the given values and solve for g

From the horizontal range formula: \[R = \frac{v^2 \sin{2\theta}}{g}\] Substitute the given values and write sin(2θ) as sin(90º) = 1 to get: \(20 = \frac{(10)^{2} \cdot 1}{g}\) Now, solve for the acceleration due to gravity (g): \(g=\frac{(10)^{2} \cdot 1}{20}\) \(g=\frac{100}{20}\) \(g = 5 \frac{m}{s^2}\)
03

State the answer

The acceleration due to gravity on planet Arcon is \(5 \frac{m}{s^2}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration due to Gravity
Acceleration due to gravity refers to the rate at which objects accelerate towards a planetary body, like Earth or Arcon, due to gravitational force. It is a constant value that affects projectile motion significantly and is denoted by the symbol \( g \). On Earth, this value is approximately \( 9.81 \frac{m}{s^2} \). However, this can vary for different planets depending on their mass and size.
This value is crucial when calculating the behavior of projectiles. It determines how fast an object will accelerate downwards, impacting both the time of flight and the range of the projectile. For a planet like Arcon, as in the exercise, where the acceleration due to gravity is \( 5 \frac{m}{s^2} \), projectiles would fall slower than on Earth. This means that they will have a longer time in the air relative to the same velocity and angle on Earth, thereby potentially traveling further horizontally.
The gravitational acceleration is directly used in the horizontal range formula, showing its critical role in calculating projectile paths.
Horizontal Range Formula
The horizontal range formula is an important concept in projectile motion calculations. It allows us to determine how far a projectile will travel horizontally before hitting the ground. The formula is expressed as:\[ R = \frac{v^2 \sin(2\theta)}{g} \]Here:
  • \( R \) is the horizontal range.
  • \( v \) is the initial velocity of the projectile.
  • \( \theta \) is the launch angle.
  • \( g \) is the acceleration due to gravity.
This formula assumes that air resistance is negligible and that the launch and landing heights are the same.
In our example, the problem was simplified by using maximum range conditions, implying a launch angle of 45 degrees (as \( \sin(90^\circ) = 1 \)). Therefore, \( \sin(2\theta) \) equals 1, which is useful in problems where the range is maximized for a given velocity.
Understanding this formula allows us to solve for unknowns, such as the acceleration due to gravity on Arcon, by rearranging the components depending on what data is available.
Physics Problem Solving
Physics problem solving is a key skill for understanding real-world applications of theoretical physics. When tackling problems like this, it's important to follow a structured approach:
  • Identify what is given: Start with recognizing the known quantities in the problem, such as initial velocity, range, or specific angles.
  • Choose the correct formula: Determine which physics formula applies. For projectile motion, it could be the range, time of flight, or maximum height formulas.
  • Substitute and solve: Carefully substitute the known values into the chosen equation and solve for the unknown. Be meticulous with units and conversion factors to avoid errors.
  • Check plausibility: Evaluate whether your answer is reasonable and makes sense in the context provided.
This methodical approach is beneficial not only when working on textbook problems but also in practical situations where understanding motion is crucial. Practicing diverse problems helps you become proficient and confident in tackling complex physics challenges.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A fastball pitcher can throw a baseball at a speed of 40 \(\mathrm{m} / \mathrm{s}(90 \mathrm{mi} / \mathrm{h}) .\) (a) Assuming the pitcher can release the ball 16.7 \(\mathrm{m}\) from home plate so the ball is moving horizontally, how long does it take the ball to reach home plate? (b) How far does the ball drop between the pitcher's hand and home plate?

A soccer goal is 2.44 m high. A player kicks the ball at a distance \(10 \mathrm{m}\) from the goal at an angle of \(25^{\circ} .\) The ball hits the crossbar at the top of the goal. What is the initial speed of the soccer ball?

A geosynchronous satellite orbits Earth at a distance of \(42,250.0 \mathrm{km}\) and has a period of 1 day. What is the centripetal acceleration of the satellite?

The position of a particle for \(t > 0\) is given by \(\overrightarrow{\mathbf{r}}(t)=\left(3.0 t^{2} \hat{\mathbf{i}}-7.0 t^{3} \hat{\mathbf{j}}-5.0 t^{-2} \hat{\mathbf{k}}\right) \mathrm{m} .\) (a) What is the velocity as a function of time? (b) What is the acceleration as a function of time? (c) What is the particle's velocity at \(t=2.0 \mathrm{s} ?(\mathrm{d})\) What is its speed at \(t=1.0 \mathrm{s}\) and \(t\) \(=3.0 \mathrm{s?}(\mathrm{e}) \mathrm{What}\) is the average velocity between \(t=1.0 \mathrm{s}\) and \(t=2.0 \mathrm{s} ?\)

A seagull can fly at a velocity of \(9.00 \mathrm{m} / \mathrm{s}\) in still air. (a) If it takes the bird 20.0 min to travel \(6.00 \mathrm{km}\) straight into an oncoming wind, what is the velocity of the wind? (b) If the bird turns around and flies with the wind, how long will it take the bird to return \(6.00 \mathrm{km} ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.