/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 A spaceship is traveling at a co... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A spaceship is traveling at a constant velocity of \(\vec{\nabla}(t)=250.0 \hat{\mathrm{i}} \mathrm{m} / \mathrm{s}\) when its rockets fire, giving it an acceleration of \(\overrightarrow{\mathbf{a}}(t)=(3.0 \hat{\mathbf{i}}+4.0 \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s}^{2} .\) What is its velocity 5 s after the rockets fire?

Short Answer

Expert verified
The velocity of the spaceship 5 seconds after the rockets fire is \(v_f = (265.0\hat{i} + 20.0\hat{k}) \, m/s\).

Step by step solution

01

Define given variables

We need to first define the given variables: Initial velocity, \(v_i = 250.0 \hat{i} \, m/s \) Acceleration, \(a = (3.0\hat{i} + 4.0\hat{k}) \, m/s^2 \) Time interval, \(t = 5s\)
02

Write the formula for the final velocity

We need to use the formula for the final velocity after a certain time period with acceleration: \(v_f = v_i + a*t \)
03

Apply the formula to the vectors

We need to find the final velocity of the spaceship separately for the i and k components. For i component: \(v_{i_i} = 250.0 \, m/s \) \(a_i = 3.0 \, m/s^2\) For k component: \(v_{i_k} = 0 \, (since \, no \, initial \, k \, component \, exists)\) \(a_k = 4.0 \, m/s^2\)
04

Calculate the final velocity

Calculate the final velocity for the i and k components separately, using the formula: \(v_{f} = v_i + a*t \) For i component: \(v_{f_i} = v_{i_i} + a_i * t = 250.0 + 3.0*5 = 265.0 \, m/s \) For k component: \(v_{f_k} = v_{i_k} + a_k * t = 0 + 4.0*5 = 20.0 \, m/s \)
05

Combine the final velocity components

Combine the i and k components of the final velocity to get the total final velocity vector: \(v_f = v_{f_i}\hat{i} + v_{f_k}\hat{k} = 265.0\hat{i} + 20.0\hat{k} \, m/s \) The velocity of the spaceship 5 seconds after the rockets fire is \(v_f = (265.0\hat{i} + 20.0\hat{k}) \, m/s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant Velocity
Imagine you're on a smooth, straight highway with your car's cruise control set to a steady 60 miles per hour. This simple yet fundamental scenario is an example of constant velocity in physics.

Constant velocity means that an object is moving in a straight line at an unchanging speed. This involves both magnitude (speed) and direction, which when combined, define velocity as a vector quantity. In the context of our spaceship exercise, the initial velocity vector is given as \(\vec{abla}(t)=250.0 \hat{\mathrm{i}} \mathrm{m} / \mathrm{s}\). Here, \(\hat{\mathrm{i}}\) represents the direction along the x-axis, and the magnitude (250.0 m/s) confirms that the speed is constant during that initial phase of the motion.

But why is it important to know whether the velocity is constant? Because if there's no change in velocity, it means there's no acceleration – and understanding this difference is crucial to solving kinematics problems.
Acceleration
Acceleration is what you feel when your car starts speeding up as soon as the traffic light turns green. It's a measure of how quickly the velocity of an object changes over time, which can mean speeding up, slowing down, or changing direction.

In physics, acceleration is another vector quantity, meaning it has both magnitude and direction. It's defined by the rate of change in velocity and is given by the formula: \( a = \frac{{\Delta v}}{{\Delta t}} \), where \(\Delta v\) is the change in velocity and \(\Delta t\) is the time it takes for that change to occur. In our spaceship exercise, the acceleration vector is \(\overrightarrow{\mathbf{a}}(t)=(3.0 \hat{\mathbf{i}}+4.0 \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s}^{2}\), indicating changes in both the x-direction (i) and the z-direction (k).
Final Velocity Calculation
Your journey progresses, and as you approach a hill, you push down on the gas pedal, increasing the speed of your car - you're calculating final velocity without even thinking about it. The final velocity is the speed and direction an object reaches after accelerating over a period of time.

The formula to calculate final velocity when acceleration is constant is \( v_f = v_i + a*t \), where \(v_f\) is the final velocity, \(v_i\) is the initial velocity, \(a\) is the acceleration, and \(t\) is time. The calculation was performed separately for the i and k components in the given solution because velocity and acceleration are vector quantities. Understanding this helps students grasp why the velocity changes, and how to compute it in problems involving multi-dimensional movement.
Vector Addition
When planning a road trip, you might have to drive east and then north to reach your destination. Similarly, in physics, an object might not move in a straight line but instead have components of motion in different directions. Vector addition comes into play when combining these different motion components.

In our exercise, after calculating the final velocity components, they need to be combined to find the total vector. This process uses vector addition: the i (x-axis) and k (z-axis) components are summed to get the final answer. So, if the spaceship has a velocity vector of \(265.0\hat{i}\) in the i direction and \(20.0\hat{k}\) in the k direction, we use vector addition to combine these and find the complete final velocity vector. It's like connecting the dots of your route on a map, from start to finish, to trace the complete path.

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Most popular questions from this chapter

The 18 th hole at Pebble Beach Golf Course is a dogleg to the left of length \(496.0 \mathrm{m}\). The fairway off the tee is taken to be the \(x\) direction. A golfer hits his tee shot a distance of \(300.0 \mathrm{m},\) corresponding to a displacement \(\Delta \overrightarrow{\mathbf{r}}_{1}=300.0 \mathrm{m} \hat{\mathbf{i}}, \quad\) and hits his second shot \(189.0 \mathrm{m}\) with a displacement \(\Delta \overrightarrow{\mathbf{r}}_{2}=172.0 \mathrm{m} \hat{\mathbf{i}}+80.3 \mathrm{m} \hat{\mathbf{j}}\) What is the final displacement of the golf ball from the tee?

An experimental jet rocket travels around Earth along its equator just above its surface. At what speed must the jet travel if the magnitude of its acceleration is \(g\) ?

The maximum horizontal distance a boy can throw a ball is \(50 \mathrm{m}\). Assume he can throw with the same initial speed at all angles. How high does he throw the ball when he throws it straight upward?

A particle has a position function \(\overrightarrow{\mathbf{r}}(t)=\cos (1.0 t) \hat{\mathbf{i}}+\sin (1.0 t) \hat{\mathbf{j}}+t \hat{\mathbf{k}}, \quad\) where the arguments of the cosine and sine functions are in radians. (a) What is the velocity vector? (b) What is the acceleration vector?

The coordinate axes of the reference frame \(S^{\prime}\) remain parallel to those of \(S\), as \(S^{\prime}\) moves away from \(S\) at a constant velocity \(\quad \overrightarrow{\mathbf{v}}_{\mathbf{S}^{\prime}}=(4.0 \hat{\mathbf{i}}+3.0 \hat{\mathbf{j}}+5.0 \hat{\mathbf{k}}) \mathrm{m} / \mathrm{s}\) (a) If at time \(t=0\) the origins coincide, what is the position of the origin \(O^{\prime}\) in the \(S\) frame as a function of time? (b) How is particle position for \(\overrightarrow{\mathbf{r}}(t)\) and \(\overrightarrow{\mathbf{r}}^{\prime}(t),\) as measured in \(S\) and \(S^{\prime}\), respectively, related? (c) What is the relationship between particle velocities \(\overrightarrow{\mathbf{v}}(t)\) and \(\overrightarrow{\mathbf{v}}^{\prime}(t) ?\) (d) How are accelerations \(\overrightarrow{\mathbf{a}}(t)\) and \(\overrightarrow{\mathbf{a}}^{\prime}\) (t) related?

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