/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 98 An airplane accelerates at \(5.0... [FREE SOLUTION] | 91Ó°ÊÓ

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An airplane accelerates at \(5.0 \mathrm{m} / \mathrm{s}^{2}\) for \(30.0 \mathrm{s}\). During this time, it covers a distance of \(10.0 \mathrm{km}\). What are the initial and final velocities of the airplane?

Short Answer

Expert verified
The initial and final velocities of the airplane are \(258.33 m/s\) and \(408.33 m/s\), respectively.

Step by step solution

01

Calculate the initial velocity

Plug the given values into the equation: v₀ = (10000 - 0.5 × 5.0 × 30.0²) / 30.0 v₀ = (10000 - 0.5 × 5.0 × 900) / 30.0 v₀ = (10000 - 2250) / 30.0 v₀ = 7750 / 30.0 v₀ = \(258.33 m/s\) The initial velocity of the airplane is \(258.33 m/s\). #2. Find the final velocity (v) using the equation v = v₀ + at# Now, we can use the initial velocity (v₀) and the given acceleration (a) and time (t) to find the final velocity (v) using the equation: v = v₀ + at
02

Calculate the final velocity

Plug the given values into the equation: v = 258.33 + 5.0 × 30.0 v = 258.33 + 150 v = \(408.33 m/s\) The final velocity of the airplane is \(408.33 m/s\). So, the initial and final velocities of the airplane are \(258.33 m/s\) and \(408.33 m/s\), respectively.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Initial Velocity
In kinematics, the initial velocity is a key concept that describes the speed at which an object begins its motion in a given scenario. When we talk about an airplane accelerating along a runway, its initial velocity (\(v_0\)) is the speed it starts at before any acceleration takes place. To find the initial velocity, we apply the formula that connects distance (\(s\)), acceleration (\(a\)), and time (\(t\)):

\[v_0 = \frac{s - 0.5 \times a \times t^2}{t}\]This formula rearranges the standard kinematic equation for distance to solve for initial velocity. In our exercise, values are substituted into the formula to calculate the initial velocity of the airplane. You can think of initial velocity as the launch speed or starting speed of any moving object.

Understanding initial velocity helps in predicting how far an object might travel, the time it will take, and how it eventually accelerates to different speeds.
Final Velocity
Final velocity is an essential concept that indicates the speed an object reaches after a period of acceleration. In our example with the airplane, the final velocity (\(v\)) is what the airplane achieves after accelerating on the runway for a specific amount of time. The formula used to determine final velocity is:

\[v = v_0 + a \times t\]This equation shows that the final velocity is the initial velocity plus the change in velocity (\(a \times t\)), due to acceleration over time. For the exercise at hand, by plugging the computed initial velocity and known values of acceleration and time, we find the final speed of the airplane.

Understanding final velocity is crucial because it provides insight into how fast the airplane is going at the end of its run, which is important for tasks like take-off or landing.
Acceleration
Acceleration is a fundamental concept in kinematics, representing the rate at which an object changes its velocity. It's often described in meters per second squared (\(\mathrm{m/s^2}\)). In our exercise, the airplane's acceleration is given as \(5.0 \mathrm{m/s^2}\). This tells us that each second, the airplane's velocity increases by \(5 \mathrm{m/s}\).

To understand acceleration, think of pressing the accelerator pedal in a car. The more you press, the faster the car speeds up, which is the same principle as the airplane's acceleration on the runway.
  • Acceleration is positive if speeding up.
  • Negative (deceleration) if slowing down.
In kinematics problems, knowing the acceleration helps predict how quickly an object will reach its desired speed, allowing for efficient planning of motion mechanics.
Distance
Distance in kinematics refers to how far an object travels when moving from one point to another. It is often measured in meters or kilometers. In the given problem, the airplane travels a distance of\(10.0 \mathrm{km}\). Understanding distance involves knowing how it relates to other kinematic variables like velocity and acceleration. Distance can be calculated using the equation:

\[s = v_0 \times t + 0.5 \times a \times t^2\]This formula is derived from the relationships among initial velocity, time, and acceleration.

In practical scenarios, calculating distance helps in determining the range of motion and planning for appropriate speed and acceleration. For the airplane, the covered distance is key for safe take-offs and landings.
Time
Time is the interval over which motion occurs, and it is fundamentally necessary to the study of kinematics. Time (\(t\)) is often measured in seconds. In this exercise, the airplane takes \(30 \mathrm{s}\) to accelerate and cover a distance of \(10.0 \mathrm{km}\).

The role of time in kinematics equations is crucial since it's used to calculate other variables like distance and velocity. When you analyze motion, you often need to determine how duration affects speed and distance.

In practical applications, precise timing is important for ensuring efficiency and safety. For airplanes, knowing the time required for acceleration helps with scheduling and coordination within airports, enhancing overall operational effectiveness.

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Most popular questions from this chapter

A motorcycle that is slowing down uniformly covers 2.0 successive \(\mathrm{km}\) in \(80 \mathrm{s}\) and \(120 \mathrm{s}\), respectively. Calculate (a) the acceleration of the motorcycle and (b) its velocity at the beginning and end of the 2 -km trip.

Dragsters can actually reach a top speed of \(145.0 \mathrm{m} / \mathrm{s}\) in only \(4.45 \mathrm{s}\). (a) Calculate the average acceleration for such a dragster. (b) Find the final velocity of this dragster starting from rest and accelerating at the rate found in (a) for \(402.0 \mathrm{m}\) (a quarter mile) without using any information on time. (c) Why is the final velocity greater than that used to find the average acceleration? (Hint: Consider whether the assumption of constant acceleration is valid for a dragster. If not, discuss whether the acceleration would be greater at the beginning or end of the run and what effect that would have on the final velocity.)

Between \(t=0\) and \(t=t_{0},\) a rocket moves straight upward with an acceleration given by \(a(t)=A-B t^{1 / 2}\) where \(A\) and \(B\) are constants. (a) If \(x\) is in meters and \(t\) is in seconds, what are the units of \(A\) and \(B\) ? (b) If the rocket starts from rest, how does the velocity vary between \(t=\) 0 and \(t=t_{0} ?\) (c) If its initial position is zero, what is the rocket's position as a function of time during this same time interval?

Compare the distance traveled of an object that undergoes a change in velocity that is twice its initial velocity with an object that changes its velocity by four times its initial velocity over the same time period. The accelerations of both objects are constant.

An airplane, starting from rest, moves down the runway at constant acceleration for 18 s and then takes off at a speed of \(60 \mathrm{m} / \mathrm{s}\). What is the average acceleration of the plane?

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