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Air temperature in the Sahara Desert can reach \(56.0^{\circ} \mathrm{C}\) (about \(134^{\circ} \mathrm{F}\) ). What is the speed of sound in air at that temperature?

Short Answer

Expert verified
The speed of sound in air at a temperature of \(56.0^{\circ} \mathrm{C}\) is approximately \(412.26 \, \mathrm{m/s}\).

Step by step solution

01

Convert the temperature from Celsius to Kelvin.

First, we need to convert the given temperature from Celsius to Kelvin using the following formula: \( \mathrm{K} = \mathrm{C} + 273.15 \). Given Celsius temperature: \(56.0^{\circ} \mathrm{C}\) We can plug in the given value and find the temperature in Kelvin: \[ T_{K} = 56.0 + 273.15 \]
02

Calculate the temperature in Kelvin.

After applying the conversion, we get the temperature in Kelvin: \[ T_{K} = 329.15 \, \mathrm{K} \]
03

Use the formula to find the speed of sound in air.

The formula for the speed of sound in air is given by: \[ v = 331.4 \sqrt{1 + \frac{T_{K}}{273.15}} \] Where - \(v\) is the speed of sound in air in meters per second (m/s), - \(T_{K}\) is the temperature in Kelvin. Now we can plug in the temperature value we found in step 2: \[ v = 331.4 \sqrt{1 + \frac{329.15}{273.15}} \]
04

Compute the speed of sound.

After plugging in the temperature value, we can compute the speed of sound: \[ v \approx 412.26 \, \mathrm{m/s} \] So, the speed of sound in air at a temperature of \(56.0^{\circ} \mathrm{C}\) is approximately \(412.26 \, \mathrm{m/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Temperature Conversion
In physics, converting temperatures from one scale to another is a common task. To convert Celsius to Kelvin, which is essential in many scientific calculations, you use a straightforward formula. The formula is:\[ K = C + 273.15 \]Here, \( K \) represents the temperature in Kelvin, and \( C \) is the temperature in Celsius. The Kelvin scale is particularly useful in physics as it starts from absolute zero, the point where theoretically, molecular motion ceases. This makes Kelvin an absolute scale of temperature.When converting the given temperature of \(56.0^{\circ} \mathrm{C}\) in the Sahara Desert to Kelvin, you add \(273.15\) to get \(329.15 \mathrm{K}\). This conversion allows you to easily use this value in other physics formulas, such as calculating the speed of sound in air.
Physics Formulas
Physics uses mathematical formulas to describe natural phenomena. One such formula is used to find the speed of sound in air under varying temperatures. The formula is:\[ v = 331.4 \sqrt{1 + \frac{T_{K}}{273.15}} \]In this formula, \( v \) is the speed of sound in meters per second, and \( T_{K} \) is the temperature in Kelvin. This formula highlights the direct relationship between air temperature and the speed of sound. As temperature increases, so does the speed of sound.In our specific exercise, you substitute \( T_{K} = 329.15 \mathrm{K} \), the converted temperature from Celsius, into the formula. After computing, you find that the speed of sound at this desert temperature is approximately \(412.26 \, \mathrm{m/s}\). This demonstrates how changes in temperature, particularly in extreme environments like deserts, can significantly impact physical processes.
Desert Climate
Deserts, such as the Sahara, are known for their extreme temperatures which fluctuate dramatically from day to night. During the day, temperatures can soar, reaching up to \(56.0^{\circ} \mathrm{C}\) as mentioned in the problem.Such high temperatures affect the behavior of gases, including the speed of sound, as molecules move faster in warmer conditions. Deserts experience unique challenges due to these conditions, influencing not only natural processes but also human activities like travel and habitat construction. These conditions make deserts ideal natural laboratories for studying the effects of heat on environmental and acoustic phenomena.
Kelvin Scale
The Kelvin scale is crucial in scientific study because it starts from absolute zero, the theoretical point where all molecular motion stops. Unlike Celsius or Fahrenheit, which are based on arbitrary points like the freezing or boiling of water, Kelvin measures absolute temperature. One unique aspect of the Kelvin scale is that there are no negative numbers. This makes it particularly valuable when involved in calculations requiring absolute temperature values. In our exercise scenario, converting the desert's Celsius temperature to Kelvin allows us to use it directly in physics formulas, which simplifies computations like the speed of sound. Remember, each increase in Kelvin corresponds directly to an increase in molecular kinetic energy, making it an indispensable tool in fields like thermodynamics and physical chemistry.

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Most popular questions from this chapter

A string with a linear mass density of fing with a linear mass density of \(\mu=0.0062 \mathrm{kg} / \mathrm{m}\) is stretched between two posts \(1.30 \mathrm{m}\) apart. The tension in the string is \(150.00 \mathrm{N}\). The string oscillates and produces a sound wave. A 1024 -Hz tuning fork is struck and the beat frequency between the two sources is \(52.83 \mathrm{Hz}\). What are the possible frequency and wavelength of the wave on the string?

Two identical strings, of identical lengths of \(2.00 \mathrm{m}\) and linear mass density of \(\mu=0.0065 \mathrm{kg} / \mathrm{m},\) are fixed on both ends. String \(A\) is under a tension of 120.00 N. String \(B\) is under a tension of \(130.00 \mathrm{N}\). They are each plucked and produce sound at the \(n=10\) mode. What is the beat frequency?

A string has a linear mass density \(\mu=0.007 \mathrm{kg} / \mathrm{m}\) a length \(L=0.70 \mathrm{m},\) a tension of \(F_{T}=110 \mathrm{N}, \quad\) and oscillates in a mode \(n=3\). (a) What is the frequency of the oscillations? (b) Use the result in the preceding problem to find the change in the frequency when the tension is increased by \(1.00 \%\).

When poked by a spear, an operatic soprano lets out a \(1200-\mathrm{Hz}\) shriek. What is its wavelength if the speed of sound is \(345 \mathrm{m} / \mathrm{s} ?\)

A 250-Hz tuning fork is struck and begins to vibrate. A sound-level meter is located \(34.00 \mathrm{m}\) away. It takes the sound \(\Delta t=0.10 \mathrm{s}\) to reach the meter. The maximum displacement of the tuning fork is \(1.00 \mathrm{mm}\). Write a wave function for the sound.

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