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Two sinusoidal waves, which are identical except for a phase shift, travel along in the same direction. The wave equation of the resultant wave is $$y_{R}(x, t)=0.35 \mathrm{cm} \sin \left(6.28 \mathrm{m}^{-1} x-1.57 \mathrm{s}^{-1} t+\frac{\pi}{4}\right)$$.What are the period, wavelength, amplitude, and phase shift of the individual waves?

Short Answer

Expert verified
The characteristics of the individual sinusoidal waves are: amplitude of 0.35 cm, wavelength of 1 m, period of 4 s, and a phase shift of (蟺/4) radians.

Step by step solution

01

Identify the amplitude, wave number, angular frequency, and phase constant from the equation

We have the equation of the resultant wave: \(y_{R}(x, t) = 0.35 \mathrm{cm} \sin \left(6.28 \mathrm{m}^{-1} x - 1.57 \mathrm{s}^{-1} t + \frac{\pi}{4}\right)\). Compare it with the general equation for a sinusoidal wave: \(y(x, t) = A \sin(kx - \omega t + \phi)\), where A: amplitude k: wave number 蠅: angular frequency 蠁: phase constant From the comparison, we have: A = 0.35 cm k = 6.28 m鈦宦 蠅 = 1.57 s鈦宦 蠁 = 蟺/4 Since the two sinusoidal waves are identical, the amplitude of the individual waves is also 0.35 cm.
02

Find the wavelength

The wavelength (位) can be found using the wave number (k) by the following relation: \(k = \frac{2\pi}{\lambda}\), Rearranging for 位, we get: \(\lambda = \frac{2\pi}{k}\). Now, substitute the value of k: \(\lambda = \frac{2\pi}{6.28 \mathrm{m}^{-1}} = 1 \mathrm{m}\). So, the wavelength of the individual waves is 1 m.
03

Find the period

The period (T) can be found using the angular frequency (蠅) by the following relation: \(\omega = \frac{2\pi}{T}\), Rearranging for T, we get: \(T = \frac{2\pi}{\omega}\). Now, substitute the value of 蠅: \(T = \frac{2\pi}{1.57 \mathrm{s}^{-1}} = 4 \mathrm{s}\). So, the period of the individual waves is 4 s.
04

Find the phase shift

The phase shift (or phase angle) can be determined directly from the phase constant (蠁) in the given equation. 蠁 = 蟺/4 Since the two sinusoidal waves are identical except for a phase shift, their phase constant difference equals the phase shift. The phase shift of the individual waves is (蟺/4) radians.
05

State the results

The individual sinusoidal waves have the following characteristics: Amplitude: 0.35 cm Wavelength: 1 m Period: 4 s Phase shift: (蟺/4) radians

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sinusoidal Waves
Sinusoidal waves are a fundamental concept in the study of wave phenomena, especially in physics. Imagine a smooth, repetitive oscillation that resembles a gentle wave, like those seen on a calm sea. This is what sinusoidal waves are all about. They are described mathematically by the sine and cosine functions, which makes them predictable and easy to work with.

When a sinusoidal wave is expressed mathematically, it often has a form similar to this: \( y(x, t) = A \sin(kx - \omega t + \phi) \). In this equation:
  • \(A\) is the amplitude, representing the peak value of the wave's displacement.
  • \(k\) is the wave number, which helps define the wavelength鈥攖he distance over which the wave's shape repeats.
  • \(\omega\) is the angular frequency, indicating how many oscillations occur in a given time period.
  • \(\phi\) is the phase constant, affecting where the wave starts its cycle at \(t = 0\).
Sinusoidal waves are important in various fields because of their ability to describe phenomena such as sound, light, and even vibrations in mechanical structures. They provide a blueprint for understanding how energy propagates through space and time.
Wave Equation Analysis
Wave equation analysis involves breaking down the mathematical representation of a wave to extract meaningful physical properties. This analysis is crucial when you have a wave equation like the one provided in this exercise. By examining the wave equation, we can identify several key characteristics of the wave:
  • Amplitude (\(A\)): This is the maximum displacement from the wave's equilibrium position. In the given wave equation, the amplitude is 0.35 cm. This signifies how "tall" or "deep" the wave is as it oscillates.
  • Wave Number (\(k\)): Related to the wavelength \(\lambda\), the wave number is given by \(k = \frac{2\pi}{\lambda}\). Solving for \(\lambda\) using \(k = 6.28 \mathrm{m}^{-1}\), we find that the wavelength is 1 m. This tells us the spatial period of the wave.
  • Angular Frequency (\(\omega\)): This component signifies how quickly the wave oscillates in time. Calculated using the formula \(\omega = \frac{2\pi}{T}\), we find that the period \(T\) is 4 s when \(\omega\) is 1.57 \mathrm{s}^{-1}. Hence, the wave repeats its motion every 4 seconds.
  • Phase Shift (\(\phi\)): The phase constant indicates where in its cycle the wave starts at time zero. Here, \(\phi = \frac{\pi}{4}\) radians, showing that the wave is shifted from the origin point by this amount.
Understanding these aspects through wave equation analysis allows for a comprehensive grasp on how the wave behaves both in space and time.
Phase Shift
Phase shift is a concept that helps describe the horizontal displacement of a wave from its default position. It is significant when dealing with waves, especially when multiple waves interact or interfere.

In this context, the phase shift is directly obtained from the phase constant \(\phi\) in the wave equation. Here, it is given as \(\frac{\pi}{4}\) radians. This quantifies how far the wave has shifted along the x-axis.
  • If the phase shift is positive, the wave is moved to the left of its usual starting position.
  • If the phase shift is negative, the wave shifts to the right.
When two sinusoidal waves are in phase (meaning they have the same phase shift), their crests and troughs align perfectly, leading to constructive interference where the waves add up to make a larger wave. Conversely, if they are out of phase (different phase shifts), the waves can cancel each other out, leading to destructive interference.

By understanding and calculating the phase shift, one can predict these interference patterns, which are crucial in numerous fields like acoustics, optics, and antenna design.

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Most popular questions from this chapter

Consider a wave described by the wave function \(y(x, t)=0.3 \mathrm{m} \sin \left(2.00 \mathrm{m}^{-1} x-628.00 \mathrm{s}^{-1} t\right)\) many crests pass by an observer at a fixed location in 2.00 minutes? (b) How far has the wave traveled in that time?

Two sinusoidal waves are moving through a medium in the same direction, both having amplitudes of \(3.00 \mathrm{cm}, \mathrm{a}\) wavelength of \(5.20 \mathrm{m},\) and a period of \(6.52 \mathrm{s}\), but one has a phase shift of an angle \(\phi\). What is the phase shift if the resultant wave has an amplitude of \(5.00 \mathrm{cm} ?[\)Hint: Use the trig identity \(\sin u+\sin v=2 \sin \left(\frac{u+v}{2}\right) \cos \left(\frac{u-v}{2}\right)\).

Use the linear wave equation to show that the wave speed of a wave modeled with the wave function \(y(x, t)=0.20 \mathrm{m} \sin \left(3.00 \mathrm{m}^{-1} x+6.00 \mathrm{s}^{-1} t\right)\) .is \(v=2.00 \mathrm{m} / \mathrm{s} .\) What are the wavelength and the speed of the wave?

A trough with dimensions 10.00 meters by 0.10 meters by 0.10 meters is partially filled with water. Small amplitude surface water waves are produced from both ends of the trough by paddles oscillating in simple harmoni,c motion. The height of the water waves are modeled with two sinusoidal wave equations \(y_{1}(x, t)=0.3 \mathrm{m} \sin \left(4 \mathrm{m}^{-1} x-3 \mathrm{s}^{-1} t\right)\) and\(y_{2}(x, t)=0.3 \mathrm{m} \cos \left(4 \mathrm{m}^{-1} x+3 \mathrm{s}^{-1} t-\frac{\pi}{2}\right) .\) What is the -wave function of the resulting wave after the waves reach menother and before they reach the end of the trough (i.e., assume that there are only two waves in the trough and ignore reflections)? Use a spreadsheet to check your aresults. (Hint: Use the trig identities \(\sin (u \pm v)=\sin u \cos v \pm \cos u \sin v\) and \(\cos (u \pm v)=\cos u \cos v \mp \sin u \sin v)\).

A pulse is defined as $$y(x, t)=e^{-2.77\left(\frac{2.00(x-2.00 \mathrm{m} / \mathrm{s}(t))}{5.00 \mathrm{m}}\right)^{2}}$$,defined \(\quad\) as.Use a spreadsheet, or other computer program, to plot the pulse as the height of medium \(y\) as a function of position \(x\). Plot the pulse at times \(t=0.00 \mathrm{s}\) and \(t=3.00 \mathrm{s}\) on the same graph. Where is the pulse centered at time \(t=3.00 \mathrm{s}\) ? Use your spreadsheet to check your answer.

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