/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 95 Two sinusoidal waves are moving ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Two sinusoidal waves are moving through a medium in the positive \(x\) -direction, both having amplitudes of 7.00 \(\mathrm{cm},\) a wave number of \(k=3.00 \mathrm{m}^{-1},\) an angular frequency of \(\omega=2.50 \mathrm{s}^{-1}, \quad\) and a period of \(6.00 \mathrm{s},\) but one has a phase shift of an angle \(\phi=\frac{\pi}{12}\) rad. What is the height of the resultant wave at a time \(t=2.00 \mathrm{s}\) and a position \(x=0.53 \mathrm{m} ?\)

Short Answer

Expert verified
The height of the resultant wave at the given position x = 0.53 m and time t = 2.00 s is approximately \(0.90 \mathrm{cm}\).

Step by step solution

01

Wave 1 equation

\( y_1(x,t) = A \sin(kx - \omega t) \) For the second wave (with phase shift), the equation is:
02

Wave 2 equation

\( y_2(x,t) = A \sin(kx - \omega t + \phi) \) #Step 2: Find the algebraic sum of the wave functions at the given time and position# Now, we need to find the algebraic sum of the two wave functions at the given time t = 2.00 s and position x = 0.53 m. This is done by simply adding the wave functions together:
03

Algebraic sum of the wave functions

\( y_{result}(x,t) = y_1(x,t) + y_2(x,t) \) #Step 3: Compute the height of the resultant wave at x = 0.53 m and t = 2.00 s# Substitute the given values and the known constants into the equation for y_result(x,t):
04

Height of the resultant wave

\( y_{result}(0.53, 2.00) = 7.00 \operatorname{cm} \sin(3.00 (0.53) - 2.50 (2.00)) + 7.00 \operatorname{cm} \sin(3.00 (0.53) - 2.50 (2.00) + \frac{\pi}{12}) \) Compute the value of the height of the resultant wave:
05

Numerical value of the height of the resultant wave

\( y_{result}(0.53, 2.00) \approx -2.44 \operatorname{cm} + 3.34 \operatorname{cm} \approx 0.90 \operatorname{cm} \) Therefore, the height of the resultant wave at the given position and time is approximately 0.90 cm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sinusoidal Waves

Sinusoidal waves, a fundamental concept in the study of wave behavior, represent periodic oscillations that vary smoothly and continuously over time and space. Imagine a stone dropped into a calm pond: ripples expand in uniform circles, undulating in a manner predicted by sinusoidal functions. Such waves are mathematically described using the sine function, with the general equation of a sinusoidal wave in one dimension given by:

\( y(x,t) = A \times \text{sin}(kx - \text{ω}t + \text{ϕ}) \)

Here, \( A \) represents the amplitude, the maximum displacement from the rest position; \( k \) is the wave number, related to the wavelength; \( \text{ω} \) is the angular frequency, connected to the period and frequency; and \( \text{ϕ} \) is the phase shift, which dictates how the wave is offset relative to the origin. Understanding the sinusoidal nature of waves aids in predicting their interactions and resultant effects, a crucial aspect of fields ranging from acoustics to oceanography.

Wave Number

The wave number, often denoted as \( k \), is a vital feature that defines the spatial frequency of a wave. In essence, it's the number of wavelengths per unit distance and is mathematically expressed as the reciprocal of the wavelength (\( \text{λ} \)):

\( k = \frac{2\text{π}}{\text{λ}} \)

In the context of our problem, a wave number of \( 3.00 \text{m}^{-1} \) tells us how tightly packed the wave crests are along a meter's length in the medium. A higher wave number would suggest shorter wavelengths and thus more oscillations per unit length. The wave number directly contributes to how the wave's phase changes spatially, which determines interference patterns when multiple waves interact.

Angular Frequency

Angular frequency, symbolized by \( \text{ω} \), describes how rapidly the sinusoidal wave oscillates in terms of radians per second. It is tightly linked to the wave's frequency (\( f \)), which is the number of oscillations per second. The relationship between angular frequency, frequency, and period (\( T \)) is given by:

\( \text{ω} = 2\text{π}f = \frac{2\text{π}}{T} \)

For the exercise, with an angular frequency of \( 2.50 \text{s}^{-1} \), this quantifies how quickly each part of the medium moves through its vibration cycle. Understanding angular frequency is crucial for calculating a wave's energy and for synchronizing systems oscillating at similar frequencies, as seen in the concept of resonance.

Phase Shift

Phase shift, represented by \( \text{Ï•} \), is a measure of how far a wave is shifted horizontally from a reference point or another wave. Think of two friends swinging side by side: if they start swinging at different times, their motions will be out of sync, and the difference in their starting points can be considered a phase shift.

In our exercise, one wave is described with a phase shift \( \text{Ï•} = \frac{\text{Ï€}}{12} \) radians. This small adjustment means one wave is slightly 'ahead' or 'behind' the other, depending on the direction of the shift. Phase difference is critical in determining the type of interference (constructive or destructive) when waves meet, as it decides whether crests align with crests (amplifying the wave) or crests align with troughs (diminishing the wave).

Resultant Wave

The resultant wave is what we observe when two or more waves occupy the same space at the same time, leading to wave interference. The principle of superposition dictates that the resultant displacement is the sum of the individual displacements from all interfering waves.

\( y_{\text{result}}(x,t) = y_1(x,t) + y_2(x,t) + \text{...} + y_n(x,t) \)

In our given problem, we computed the resultant wave by adding the displacements from two waves at a certain time and position. The constructive or destructive nature of this interaction depends on their relative phase shifts. If the crests and troughs of the waves line up, the resultant wave will have a greater amplitude (constructive interference). If a crest of one wave aligns with a trough of another, they partially or completely cancel out (destructive interference). This simple concept explains a variety of phenomena, from noise-cancelling headphones to the vibrant patterns created by light passing through a double slit.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A Girl Scout is taking a 10.00-km hike to earn a merit badge. While on the hike, she sees a cliff some distance away. She wishes to estimate the time required to walk to the cliff. She knows that the speed of sound is approximately 343 meters per second. She yells and finds that the echo returns after approximately 2.00 seconds. If she can hike \(1.00 \mathrm{km}\) in 10 minutes, how long would it take her to reach the cliff?

Consider the wave function\(y(x, t)=(3.00 \mathrm{cm}) \sin \left(0.4 \mathrm{m}^{-1} x+2.00 \mathrm{s}^{-1} t+\frac{\pi}{10}\right)\).What are the period, wavelength, speed, and initial phase shift of the wave modeled by the wave function?

A trough with dimensions 10.00 meters by 0.10 meters by 0.10 meters is partially filled with water. Small amplitude surface water waves are produced from both ends of the trough by paddles oscillating in simple harmoni,c motion. The height of the water waves are modeled with two sinusoidal wave equations \(y_{1}(x, t)=0.3 \mathrm{m} \sin \left(4 \mathrm{m}^{-1} x-3 \mathrm{s}^{-1} t\right)\) and\(y_{2}(x, t)=0.3 \mathrm{m} \cos \left(4 \mathrm{m}^{-1} x+3 \mathrm{s}^{-1} t-\frac{\pi}{2}\right) .\) What is the -wave function of the resulting wave after the waves reach menother and before they reach the end of the trough (i.e., assume that there are only two waves in the trough and ignore reflections)? Use a spreadsheet to check your aresults. (Hint: Use the trig identities \(\sin (u \pm v)=\sin u \cos v \pm \cos u \sin v\) and \(\cos (u \pm v)=\cos u \cos v \mp \sin u \sin v)\).

A sunbather stands waist deep in the ocean and observes that six crests of periodic surface waves pass each minute. The crests are 16.00 meters apart. What is the wavelength, frequency, period, and speed of the waves?

Consider what is shown below. A 20.00-kg mass rests on a frictionless ramp inclined at \(45^{\circ} .\) A string with a linear mass density of \(\mu=0.025 \mathrm{kg} / \mathrm{m}\) is attached to the 20.00-kg mass. The string passes over a frictionless pulley of negligible mass and is attached to a hanging mass \((m)\) The system is in static equilibrium. A wave is induced on the string and travels up the ramp. (a) What is the mass of the hanging mass (m)? (b) At what wave speed does the wave travel up the string?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.