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If a car has a suspension system with a force constant of \(5.00 \times 10^{4} \mathrm{N} / \mathrm{m}\), how much energy must the car's shocks remove to dampen an oscillation starting with a maximum displacement of \(0.0750 \mathrm{m} ?\)

Short Answer

Expert verified
The energy that the car's shocks must remove to dampen the oscillation starting with a maximum displacement of \(0.0750 m\) is \(U = 140.625 J\).

Step by step solution

01

Write down the given information

We are given: - Force constant (\(k\)): \(5.00 \times 10^4 N/m\) - Maximum displacement (\(x\)): \(0.0750 m\)
02

Apply the potential energy formula

Now we will apply the formula for the potential energy stored in a spring: \(U = \frac{1}{2}kx^2\)
03

Substitute the given values and solve for the energy

Substitute the given values of \(k\) and \(x\) in the formula: \(U = \frac{1}{2}(5.00\times 10^4 N/m)(0.0750 m)^2\) Calculating the potential energy: \(U = \frac{1}{2}(5.00\times 10^4 N/m)(0.005625 m^2)\) \(U = 140.625 J\)
04

Write the final answer

The energy that the car's shocks must remove to dampen the oscillation starting with a maximum displacement of \(0.0750 m\) is: \(U = 140.625 J\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Dissipation
When a car experiences a bump in the road, its suspension system absorbs energy to maintain a smooth ride. However, the energy initially stored in the springs of the suspension doesn't just disappear. It needs to be dissipated. This process is known as energy dissipation. In spring systems, energy dissipation refers to the reduction of energy through internal processes such as friction or resistance.

Energy dissipation usually results in the conversion of mechanical energy into thermal energy. Rubbers, hydraulic fluids in dampers, or air resistance can transform the kinetic energy into heat, which eventually spreads into the surroundings. Over time, this gradual release prevents the mechanical system from remaining in perpetual motion.

For example, in cars, the shock absorbers are tasked with "soaking up" excess energy from the springs to prevent continuous bouncing. Without energy dissipation, any initial displacement in the system would result in prolonged vibrations, leading to an uncomfortable ride.
  • Essentially, energy dissipation is the act of converting stored energy into non-usable forms, usually heat.
  • It's vital to systems that require effective vibration control, like vehicles or engineering structures.
  • Efficient energy dissipation mechanisms ensure stability and comfort.
Damping in Mechanical Systems
In mechanical systems, damping is a critical concept. It describes the process that reduces the amplitude of oscillation. This is achieved by dissipating the energy stored in the system. Damping is essential for stabilizing vibrating systems by removing energy, ensuring they don't oscillate indefinitely.

Different types of damping are used, such as viscous damping, where a damper uses a fluid to resist motion. This type of damping is common in vehicle shock absorbers. Another example is frictional damping, where surfaces in contact slide against each other.

The key role of damping in mechanical systems includes:
  • Minimizing vibrations: Reducing amplitude ensures smoother operation.
  • Preventing systems from reaching resonance: This occurs when the system oscillates at its maximum amplitude, which can be destructive.
  • Increasing safety and comfort: Decreased oscillations help improve stability in structures and vehicles.
Damping relies on converting mechanical energy into other forms, which generally leads to reduced vibration. An example would be adjusting the shock absorbers in a car's suspension system. By dissipating energy adequately, the ride remains comfortable and the car maintains stable control.
Potential Energy in Springs
Springs are commonly used in many mechanical systems due to their ability to store and release energy effectively. The amount of energy stored in a spring depends on its stiffness and how far it is stretched or compressed. This stored energy is called potential energy.

For a spring, potential energy (\( U \)) is determined using the formula: \( U = \frac{1}{2}kx^2 \), where \( k \) represents the spring constant, and \( x \) is the maximum displacement from the spring's natural position.
  • Spring constant (\( k \)) is a measure of the stiffness of the spring.
  • Maximum displacement (\( x \)) is how far the spring is stretched or compressed.
Understanding potential energy in springs helps solve problems related to oscillations. In our car suspension example, the potential energy originally stored due to displacement can be calculated using the mentioned formula.

This energy provides the basis for determining how much energy needs to be dissipated to bring the car back to equilibrium after a bump.

Springs, therefore, act as excellent storage devices for mechanical energy, temporarily holding it and then returning it when needed. This ability is crucial in applications that require controlled energy management, like shock absorption in vehicles or even in watches and various mechanical devices.

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Most popular questions from this chapter

Explain in terms of energy how dissipative forces such as friction reduce the amplitude of a harmonic oscillator. Also explain how a driving mechanism can compensate. (A pendulum clock is such a system.)

Assume that a pendulum used to drive a grandfather clock has a length \(L_{0}=1.00 \mathrm{m}\) and a mass \(M\) at temperature \(T=20.00^{\circ} \mathrm{C} .\) It can be modeled as a physical pendulum as a rod oscillating around one end. By what percentage will the period change if the temperature increases by \(10^{\circ} \mathrm{C} ?\) Assume the length of the rod changes linearly with temperature, where \(L=L_{0}(1+\alpha \Delta T)\) and the rod is made of brass \(\left(\alpha=18 \times 10^{-6 \circ} \mathrm{C}^{-1}\right)\)

The length of nylon rope from which a mountain climber is suspended has an effective force constant of \(1.40 \times 10^{4} \mathrm{N} / \mathrm{m} .\) (a) What is the frequency at which he bounces, given his mass plus and the mass of his equipment are \(90.0 \mathrm{kg}\) ? (b) How much would this rope stretch to break the climber's fall if he free-falls \(2.00 \mathrm{m}\) before the rope runs out of slack? (Hint: Use conservation of energy.) (c) Repeat both parts of this problem in the situation where twice this length of nylon rope is used.

Suppose you have a 0.750-kg object on a horizontal surface connected to a spring that has a force constant of 150 N/m. There is simple friction between the object and surface with a static coefficient of friction \(\mu_{\mathrm{s}}=0.100\) (a) How far can the spring be stretched without moving the mass? (b) If the object is set into oscillation with an amplitude twice the distance found in part (a), and the kinetic coefficient of friction is \(\mu_{\mathrm{k}}=0.0850,\) what total distance does it travel before stopping? Assume it starts at the maximum amplitude.

As you pass a freight truck with a trailer on a highway, you notice that its trailer is bouncing up and down slowly. Is it more likely that the trailer is heavily loaded or nearly empty? Explain your answer.

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