/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Find the frequency of a tuning f... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the frequency of a tuning fork that takes \(2.50 \times 10^{-3} \mathrm{s}\) to complete one oscillation.

Short Answer

Expert verified
The frequency of the tuning fork is \(400 \mathrm{Hz}\).

Step by step solution

01

Identify the Period of Oscillation

The period of oscillation is given in the problem as \(2.50 \times 10^{-3} \mathrm{s}\). We'll denote this as T.
02

Use the Formula for Frequency

The frequency, f, of a periodic motion, like an oscillation, is the number of oscillations completed in one second. The frequency is related to the period using the following formula: \[f = \frac{1}{T}\]
03

Plug in the Period

Now, we can plug in the period, T, in the formula for the frequency: \[f = \frac{1}{2.50\times 10^{-3}\mathrm{s}}\]
04

Calculate the Frequency

Performing the calculation, we get: \[f = \frac{1}{2.50\times 10^{-3} \mathrm{s}} = 400 \mathrm{Hz}\] So, the frequency of the tuning fork is 400 Hz.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Period of Oscillation
Understanding the period of oscillation is fundamental when studying oscillatory motion in physics. It refers to the time taken for one complete cycle of oscillation to occur. This could be a swinging pendulum, an electron in its orbital path, or in this case, the vibration of a tuning fork.

In the given exercise, the tuning fork completes one oscillation in a time frame of \(2.50 \times 10^{-3} \mathrm{s}\). This duration is identified as the period (T). A quick tip to remember: the period of oscillation is inversely related to the frequency. This means that if we're discussing a high-frequency oscillation, it will have a short period, and conversely, a low-frequency oscillation will have a long period.

The period provides valuable insight into the behavior of oscillatory systems and is a key factor in calculating other properties of the system, such as frequency and angular velocity.
Oscillatory Motion
Oscillatory motion is characterized by the repetitive movement of an object back and forth through a central, or equilibrium, position. Imagine a playground swing going to and fro; this is a great visual for oscillatory motion. More technically, we witness this type of motion in springs, pendulums, and yes—tuning forks!

When discussing the oscillatory motion of a tuning fork, we're dealing with vibrations caused by the fork's tines moving rapidly back and forth. These vibrations create sound waves that we perceive as tones. Moreover, the concepts of amplitude and frequency enter the scene, which entail the maximum displacement from the equilibrium position and the number of oscillations per unit time, respectively.

The significance of oscillatory motion lies in its ubiquitous presence across various physical phenomena, making it a staple concept in wave mechanics, acoustics, and even quantum physics. Understanding the principles of oscillation helps in the design of many technological devices such as clocks, musical instruments, and seismic sensors.
Physics Formulas
Physics formulas are the mathematical expressions that describe the relationships between different physical quantities. These formulas are essential tools for physicists and engineers to predict the outcomes of experiments and to design systems that behave in predictable ways.

In the context of our tuning fork exercise, we applied the fundamental formula for the relationship between frequency (f) and period (T): \[f = \frac{1}{T}\]. By plugging in the value of the period, we use this formula to conclude the frequency with which the tuning fork vibrates.

Apart from this formula, physics includes a vast array of formulas to address concepts like motion, force, energy, momentum, and others. They serve as the framework within which we can systematically understand and analyze physical events. Familiarity with these formulas and a solid grasp of their application can significantly enhance a student's ability to solve complex problems across various topics in physics.

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Most popular questions from this chapter

Suppose you have a 0.750-kg object on a horizontal surface connected to a spring that has a force constant of 150 N/m. There is simple friction between the object and surface with a static coefficient of friction \(\mu_{\mathrm{s}}=0.100\) (a) How far can the spring be stretched without moving the mass? (b) If the object is set into oscillation with an amplitude twice the distance found in part (a), and the kinetic coefficient of friction is \(\mu_{\mathrm{k}}=0.0850,\) what total distance does it travel before stopping? Assume it starts at the maximum amplitude.

Some people think a pendulum with a period of 1.00 s can be driven with "mental energy" or psycho kinetically, because its period is the same as an average heartbeat. True or not, what is the length of such a pendulum?

With the use of a phase shift, the position of an object may be modeled as a cosine or sine function. If given the option, which function would you choose? Assuming that the phase shift is zero, what are the initial conditions of function; that is, the initial position, velocity, and acceleration, when using a sine function? How about when a cosine function is used?

The amplitude of a lightly damped oscillator decreases by \(3.0 \%\) during each cycle. What percentage of the mechanical energy of the oscillator is lost in each cycle?

Find the ratio of the new/old periods of a pendulum if the pendulum were transported from Earth to the Moon, where the acceleration due to gravity is \(1.63 \mathrm{m} / \mathrm{s}^{2}\)

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