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A cylindrical can of radius \(R\) is rolling across a horizontal surface without slipping. (a) After one complete revolution of the can, what is the distance that its center of mass has moved? (b) Would this distance be greater or smaller if slipping occurred?

Short Answer

Expert verified
The distance that the can's center of mass has moved after one revolution is \(2\pi R\). If slipping had occurred, this distance would have been greater.

Step by step solution

01

Find distance moved after one complete revolution

In one complete revolution, a circular object moves a distance equal to its circumference. The formula for the circumference of a circle is \(2\pi R\), where \(R\) is the radius of the circle. Therefore, the distance moved by the center of mass of the can is \(2\pi R\).
02

Assess the effect of slipping on the distance moved

If slipping occurred, the distance covered by the center of mass of the can would be greater than the distance covered in the no-slip condition. This is because when the can slips it also slides along the surface, besides rolling, which increases the total distance traveled by the can's center of mass.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Circular Motion
Circular motion is any motion of an object that revolves around a single path or axis along a circular trajectory. In the context of the cylindrical can rolling, this means the can completes a circular path with its entire surface, while its center follows a straight line trajectory. This combination of rotation and translation is crucial for understanding how rolling objects behave.
Moreover, in a circular motion situation, centering around an axis ensures that all points on the object's outer edge are equidistant from the center. Whether it's a can rolling on a flat surface or a car maneuvering around a curve, understanding circular motion helps us calculate the necessary physical properties, like velocity and acceleration, necessary for analyzing movement.
The Concept of Center of Mass
The center of mass is the average position of all the mass in an object. For uniformly dense objects like our cylindrical can, it is located at the geometrical center.
The center of mass plays a critical role in understanding how an object moves. When the cylindrical can rolls, even though each point on the surface follows an individual circular path, the center of mass moves in a straight line if there's no slipping.
In our problem, after one full revolution of the can, the center of mass travels a distance equal to the circle’s circumference:
  • Position is uniformly translated during a full rotation
  • Path traveled is represented by a straight line across the horizontal surface
Thus, knowing where the center of mass is aids us in predicting the translational motion from rotational action.
The Principle of Rolling Without Slipping
Rolling without slipping is a type of motion where the object rolls on a surface without any sliding. This implies that the bottom part of the object, although momentarily at rest relative to the surface, is in solid contact while moving.
For understanding our cylindrical can, rolling without slipping occurs when every point on the base of the can touches the ground once per rotation without skidding. This condition ensures that all motion is purely rotational and translational, without any extraneous slipping-derived movement. This is significant because:
  • The linear distance traveled by the center of mass equals one circumference after a full rotation
  • There is no energy loss due to sliding friction
Slipping, however, would cause greater distance travel and additional wear on surfaces involved.
Exploring the Circumference
Circumference signifies the linear distance around the outer boundary of a circular object. For a cylinder, it acts as both the path each point on the surface travels during a full rotation and as a measure of the rolling distance on a plane.
The formula to compute the circumference is:
  • \[ C = 2\pi R \]
This expression tells us that the circumference depends directly on the radius \( R \) of the circle.
In practical understanding, for every full rotation of the can, the center of mass covers a distance equal to the circumference. This equilateral translation confirms that:
  • The whole object has completed one full turn
  • The center has transitioned by the circle's full perimeter
Thus, the circumference forms the basis for calculating how far the center of mass has moved while rolling without slipping.

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Most popular questions from this chapter

A gymnast does cartwheels along the floor and then launches herself into the air and executes several flips in a tuck while she is airborne. If her moment of inertia when executing the cartwheels is \(13.5 \mathrm{kg} \cdot \mathrm{m}^{2}\) and her spin rate is 0.5 rev/s, how many revolutions does she do in the air if her moment of inertia in the tuck is \(3.4 \mathrm{kg} \cdot \mathrm{m}^{2}\) and she has \(2.0 \mathrm{s}\) to do the flips in the air?

A thin meter stick of mass \(150 \mathrm{g}\) rotates around an axis perpendicular to the stick's long axis at an angular velocity of 240 rev/min. What is the angular momentum of the stick if the rotation axis (a) passes through the center of the stick? (b) Passes through one end of the stick?

A bug of mass 0.020 kg is at rest on the edge of a solid cylindrical disk \((M=0.10 \mathrm{kg}, R=0.10 \mathrm{m})\) rotating in a horizontal plane around the vertical axis through its center. The disk is rotating at \(10.0 \mathrm{rad} / \mathrm{s}\). The bug crawls to the center of the disk. (a) What is the new angular velocity of the disk? (b) What is the change in the kinetic energy of the system? (c) If the bug crawls back to the outer edge of the disk, what is the angular velocity of the disk then? (d) What is the new kinetic energy of the system? (e) What is the cause of the increase and decrease of kinetic energy?

A hollow sphere and a hollow cylinder of the same radius and mass roll up an incline without slipping and have the same initial center of mass velocity. Which object reaches a greater height before stopping?

Gyroscopes used in guidance systems to indicate directions in space must have an angular momentum that does not change in direction. When placed in the vehicle, they are put in a compartment that is separated from the main fuselage, such that changes in the orientation of the fuselage does not affect the orientation of the gyroscope. If the space vehicle is subjected to large forces and accelerations how can the direction of the gyroscopes angular momentum be constant at all times?

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