/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 86 A flywheel \(\left(I=50 \mathrm{... [FREE SOLUTION] | 91Ó°ÊÓ

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A flywheel \(\left(I=50 \mathrm{kg}-\mathrm{m}^{2}\right)\) starting from rest acquires an angular velocity of \(200.0 \mathrm{rad} / \mathrm{s}\) while subject to a constant torque from a motor for 5 s. (a) What is the angular acceleration of the flywheel? (b) What is the magnitude of the torque?

Short Answer

Expert verified
The angular acceleration of the flywheel is \(40 rad/s^2\) and the magnitude of the torque applied by the motor is \(2000 N \cdot m\).

Step by step solution

01

Identify the given variables

Moment of Inertia (I): \(50 kg \cdot m^2\) Initial Angular Velocity (\(\omega_i\)): \(0 rad/s\) Final Angular Velocity (\(\omega_f\)): \(200 rad/s\) Time (t): \(5s\)
02

Calculate the angular acceleration using the angular velocity relation

Using the angular velocity relation, we can find the angular acceleration (\(\alpha\)): \(\omega_f = \omega_i + \alpha t\) Rearrange the equation to solve for \(\alpha\): \(\alpha = (\omega_f - \omega_i) / t\) Substitute the given values: \(\alpha = (200 - 0) / 5\)
03

Compute the angular acceleration

Now, let's calculate the angular acceleration (\(\alpha\)): \(\alpha = 200 / 5\) \(\alpha = 40 rad/s^2\) The angular acceleration of the flywheel is \(40 rad/s^2\).
04

Calculate the magnitude of the torque using the torque relation

Now, we'll use the torque relation to find the magnitude of the torque (\(\tau\)): \(\tau = I\alpha\) Substitute the given values: \(\tau = (50 kg \cdot m^2)(40 rad/s^2)\)
05

Compute the magnitude of the torque

Finally, let's calculate the magnitude of the torque (\(\tau\)): \(\tau = 50 \cdot 40\) \(\tau = 2000 N \cdot m\) The magnitude of the torque applied by the motor is \(2000 N \cdot m\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Angular Acceleration
Angular acceleration is a change in angular velocity over time. In simpler terms, it tells us how quickly something is spinning faster or slower. Imagine watching a merry-go-round at the park. If it starts from a standstill and speeds up, it has angular acceleration.
The formula to find angular acceleration is:
  • \[\alpha = \frac{\omega_f - \omega_i}{t}\]
Here:
  • \(\omega_f\) is the final angular velocity,
  • \(\omega_i\) is the initial angular velocity,
  • \(t\) is the time in which the change occurs.
In our exercise, the flywheel starts at a speed of \(0 rad/s\) and reaches \(200 rad/s\) in \(5\) seconds. Plugging these into the formula gives us an angular acceleration of \(40 rad/s^2\). That means every second, the flywheel's spinning speed increases by \(40 rad/s\). This shows how intuitive angular acceleration measures the rapidity of rotational speed change.
Exploring Torque Calculation
Torque is a measure of the rotational force applied to make an object spin. Imagine using a wrench to turn a bolt. The force you apply with the wrench, multiplied by the distance from the bolt, is the torque. Think of it as the twist applied to make things go round.
The relationship between torque (\(\tau\)) and angular acceleration (\(\alpha\)) in a rotational system is given by the equation:
  • \[\tau = I \alpha\]
Where:
  • \(I\) is the moment of inertia,
  • \(\alpha\) is the angular acceleration.
Using the flywheel example, the moment of inertia was provided as \(50 \ kg \cdot m^2\), and the angular acceleration was found to be \(40 \ rad/s^2\). Substituting these into the equation gives \(\tau = 2000 \ N \cdot m\). That's the power the motor needs to provide to accelerate the flywheel at the desired rate.
This illustrates that torque is crucial not only for setting objects in motion but also for understanding the strength of forces in rotational dynamics.
The Role of Moment of Inertia
The moment of inertia, often symbolized as \(I\), is a measure of an object's resistance to changes in its rotation. It's similar to mass in linear motion but for rotations. Think of it as how hard it is to spin something or to stop it once spinning.
Different shapes or mass distributions affect how easy or hard it is to change rotational speeds. For instance, a flywheel with mass concentrated far from its center has a larger moment of inertia compared to one with its mass nearer to the center.
The moment of inertia is calculated differently based on shape and mass distribution. For simple shapes, standard formulas are often used. In our context, the flywheel's given moment of inertia was \(50 \ kg\cdot m^2\). This tells us that with constant torque, this is the resistance faced while trying to change its rotational speed.
Understanding this concept is vital in designing systems that rotate, making sure the torque requirement, motor specifications, and system dynamics are aligned.

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Most popular questions from this chapter

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