/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 74 When tightening a bolt, you push... [FREE SOLUTION] | 91Ó°ÊÓ

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When tightening a bolt, you push perpendicularly on a wrench with a force of \(165 \mathrm{N}\) at a distance of \(0.140 \mathrm{m}\) from the center of the bolt. How much torque are you exerting in newton-meters (relative to the center of the bolt)?

Short Answer

Expert verified
The torque exerted on the bolt when a perpendicular force of 165 N is applied at a distance of 0.140 m from the center is \(\underline{23.1}\) Nm (relative to the center of the bolt).

Step by step solution

01

Write down the torque formula

The formula to calculate torque is given by: torque = force × distance × sin(angle). Since the force is applied perpendicularly, the angle is 90 degrees, and sin(90) = 1.
02

Plug in the given values

In this problem, force = 165 N and distance = 0.140 m. Let's plug these values into the torque formula. torque = 165 N × 0.140 m × sin(90)
03

Calculate sin(90)

The sine of 90 degrees is 1. So, the torque formula becomes: torque = 165 N × 0.140 m × 1
04

Calculate the torque

Now, we can find the torque by multiplying the force and the distance. torque = 165 N × 0.140 m torque = 23.1 Nm The torque exerted on the bolt is \(\underline{23.1}\) Nm (relative to the center of the bolt).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Physics Torque Formula
Torque is a fundamental concept in physics, especially when analyzing the rotational motion of objects. It is the measure of how much a force acting on an object causes that object to rotate. The physics torque formula can be expressed as:
\[ \text{Torque (\tau)} = \text{Force (F)} \times \text{Distance (d)} \times \sin(\theta) \]
where \(\theta\) is the angle between the force vector and the lever arm. When the force is applied perpendicularly to the wrench, as in our exercise, \(\theta = 90^\circ\) and \(\sin(\theta) = 1\), simplifying our calculation.

Applying Newton's Laws of Motion to Understand Torque
Newton's Laws of Motion are the foundation of classical mechanics. The second law, which states that Force equals mass times acceleration (\(F = ma\)), is particularly relevant when we talk about rotational motion and torque. In the context of torque, we're dealing with rotational forces, and it's Newton's second law that explains how these forces cause an object to change its rotational velocity.

Role of Lever Arm in Torque

The 'distance' in the torque formula is often referred to as the lever arm. It's the perpendicular distance from the axis of rotation to the line of action of the force. The longer the lever arm, the less force required to achieve the same amount of torque—a principle evident in everyday tools like wrenches or door handles.
The Importance of Statics in Physics
Statics is the study of forces in equilibrium. When calculating torque, we are often dealing with static situations where the sum of forces and torques is zero. This means that for our wrench and bolt scenario, if there were other forces acting on the system, they would have to be in equilibrium for our torque calculation to be valid. Statics principles are critical in engineering and architecture because they ensure structures can withstand various forces without moving.

Applying Statics to Torque Problems

In statics problems involving rotation, the point where the object rotates is considered the pivot point. For the bolt and wrench, the bolt is the pivot. By understanding the principles of statics, we can analyze the forces at play and design systems that remain stable under different loads, ensuring safety and functionality in mechanical systems.

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Most popular questions from this chapter

A system of point particles is rotating about a fixed axis at 4 rev/s. The particles are fixed with respect to each other. The masses and distances to the axis of the point particles are \(m_{1}=0.1 \mathrm{kg}, r_{1}=0.2 \mathrm{m}\), \(m_{2}=0.05 \mathrm{kg}, r_{2}=0.4 \mathrm{m}, \quad m_{3}=0.5 \mathrm{kg}, r_{3}=0.01 \mathrm{m}\). (a) What is the moment of inertia of the system? (b) What is the rotational kinetic energy of the system?

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