/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 Estimate the angular displacemen... [FREE SOLUTION] | 91Ó°ÊÓ

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Estimate the angular displacement (in radians and degrees) of Earth in one day of its orbit around the Sun.

Short Answer

Expert verified
The Earth displaces about 0.0172 radians or 0.986 degrees in its orbit around the Sun each day.

Step by step solution

01

Define the Angular Displacement for a Full Year

In one full orbit around the Sun, which is about 365.25 days, the Earth displaces an angle of \(2\pi\) radians or 360 degrees.
02

Calculate the Daily Displacement in Radians

To estimate the daily angular displacement in radians, the total angular displacement for a full orbit (\(2\pi\) radians) need to be divided by the number of days in a year (365.25). This gives: \( \frac{2\pi}{365.25} = 0.0172 \) radians. This is approximately the angular displacement in radians that the Earth orbits around the Sun in one day.
03

Calculate the Daily Displacement in Degrees

To estimate the daily angular displacement in degrees, perform the similar operation but with the total angular displacement for a full orbit being 360 degrees. This gives: \( \frac{360}{365.25} = 0.986 \) degrees. This is approximately the angular displacement in degrees that the Earth orbits around the Sun in one day.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Earth's Orbit
The Earth's orbit is the path it takes as it travels around the Sun. This journey looks like an elongated circle, or an ellipse. Each full orbit, or one revolution around the Sun, takes about 365.25 days—this is what defines a year. The numbers .25 accounts for the extra day every four years, which gives us a leap year with 366 days. This path is vast and influences various factors on Earth, such as season changes and the distribution of sunlight worldwide.
Understanding Earth's orbit helps explain why we have different seasons and varying day lengths throughout the year. As Earth travels along this elliptical path, its speed slightly changes due to gravitational forces. But for someone observing from a vast distance, it would appear the Earth traces out an almost perfect circle, completing one revolution each year. Grasping this concept is essential for understanding phenomena like change in solar exposure and day length.
Radians and Degrees Conversion
Radians and degrees are two ways of measuring angles, much like you can measure distance in miles or kilometers. A complete circle, or a full turn, equals 360 degrees—this is a common way people typically think about angles. However, in more advanced math and science contexts, radians are often preferred.
One full circle also represents an angle of \(2\pi\) radians, where \(\pi\approx3.14159\). In simpler terms, 180 degrees equals \(\pi\) radians, and therefore 1 degree is \(\frac{\pi}{180}\) radians.
To convert from degrees to radians, multiply the degree measure by \(\frac{\pi}{180}\). Conversely, to convert from radians to degrees, multiply the radian measure by \(\frac{180}{\pi}\). This conversion is crucial when working with equations and formulas in science and engineering, enabling seamless switching between two units depending on the context.
Daily Angular Displacement
Daily angular displacement refers to the small segment of the orbital circle the Earth travels each day. Given Earth completes a full loop around the Sun in about 365.25 days, we can divide the full 360-degree orbit by this period to find out how much Earth rotates in one day.
Calculating the daily displacement in degrees involves dividing 360 degrees by 365.25, resulting in approximately 0.986 degrees per day. For radians, the division of \(2\pi\) radians by 365.25 days gives around 0.0172 radians per day.
This small daily change is fundamental for understanding how Earth gradually shifts its position relative to the Sun, leading to observable variations in daylight across days and seasons. It also highlights the precision and regularity of celestial motions, allowing us to track time through calendars and even predict celestial events accurately.

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Most popular questions from this chapter

A table saw has a 25 -cm-diameter blade that rotates at a rate of \(7000 \mathrm{rpm}\). It is equipped with a safety mechanism that can stop the blade within \(5 \mathrm{~ms}\) if something like a finger is accidentally placed in contact with the blade. (a) What angular acceleration occurs if the saw starts at \(7000 \mathrm{rpm}\) and comes to rest in \(5 \mathrm{~ms}\) ? (b) How many rotations does the blade complete during the stopping period?

How would a flywheel's (spinning disk's) kinetic energy change if its moment of inertia were five times larger but its angular speed were five times smaller? A. \(0.1\) times as large as before B. \(0.2\) times as large as before C. same as before D. 5 times as large as before E. 10 times as large as before

The outside diameter of the playing area of an optical Blu-ray disc is \(11.75 \mathrm{~cm}\) and the inside diameter is \(4.5 \mathrm{~cm}\). When viewing movies, the disc rotates so that a laser maintains a constant linear speed relative to the disc of \(7.5 \mathrm{~m} / \mathrm{s}\) as it tracks over the playing area. (a) What are the maximum and minimum angular speeds (in \(\mathrm{rad} / \mathrm{s}\) and \(\mathrm{rpm}\) ) of the disc? (b) At which location of the laser on the playing area do these speeds occur? (c) What is the average angular acceleration of a Blu-ray disc as it plays an 8.0-h set of movies?

What is the speed of an electron in the lowest energy orbital of hydrogen, of radius equal to \(5.29 \times 10^{-11} \mathrm{~m}\) ? The mass of an electron is \(9.11 \times 10^{-31} \mathrm{~kg}\) and its angular momentum in this orbital is \(1.055 \times 10^{-34} \mathrm{~J} \cdot \mathrm{s}\).

What are the units of angular velocity \((\omega)\) ? Why are there factors of \(2 \pi\) present in the equations of rotational motion?

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